How can these questions be solved, how can this question be solved?

From the above conclusions, we can get it.

Wang Hong, Li Tie, Chen Wu, Liu Jian, and Zhou Bin answered the questions correctly and incorrectly.

Wang Hong 7 to 2 wrong, Li Tie 4 to 5, Chen Wu 6 to 3, Liu Jian 5 to 5, Zhou and 7 to 3 wrong.

This question is not good, the answer is too easy to see, d

2 [Answer] c. Analysis: From the last sentence of the question stem, it can be seen that the views of college graduates in 1964 and 1982 on the reasons for going to college in their first year of college are different, so item C can be introduced.

A, B, and D are not meant to be explained by the stem, nor can they be deduced from the stem.

I hope it can help you!

<>First of all, the following known number is 7, so the single digit of the dividend is also 7, because the result is equal to 0, so the following box of the known number 7 should be filled in 7, the known number 3 should be filled in 3, the known number 1 is divided by borrowing a bit from the known number 3 to get the known number 1 should be filled in 8, the hundred digit of the dividend is borrowed by one and then borrowing one from the thousand digit minus 5 to know that the following two boxes are filled in 8, because the number of single digits of the known number of 7 and the 8 just filled in to determine the single digit of the quotient is 9, and the single digit of the divisor is 3, The tens of the quotient are 6 and the thousand digits of the dividend are 6. Hope it helps.

You can't fill in 5 at the minimum, do you find out?? If you fill in 5, the top is smaller than the bottom, and the subtraction is a negative number.

<> first pushes out 11-3=8 so we get 55[8].

Push 13-5=8 again to get [8]37 [8][3][7] to get [6]41[7].

9 55[8] The single digit is 8, so it can only be 1*8 2*4 2*9 3*6 4*2 4*7 6*3 6*8 9*2

Only 93 * 6 = 558 gives 9[3] and [6]837 93 = 9 gets[6][9].

I've tried various situations, and I personally feel that this problem is unsolvable. (The picture comes from the Internet).

No solution. From left to right, from top to bottom, set the four numbers as a, b, c, and d

From a-b=9, a+c=12, we get c+b=3, and from c-d=14, b+d=2, we get c+b=16

The above two formulas are self-contradictory, so there is no solution.

There is no solution to this problem, and it can't be solved.

You can set abcd:from left to right, top to bottom

look sideways a-b=9; c-d=14 So a+c-(b+d)=23 vertically look at a+c=12, b+d=2 so a+c-(b+d)=10

This is a wrong question, you can set the fourth number as x, then the above is 2-x, according to the above second number and then the first number is 9 + (2-x) = 11-x, according to the fourth number x then the left side is 14 + x, so (11-x) + (14 + x) = 25 is not equal to 12