Two math application problems Urgency 25

1 If the height is xcm, the length is 3 4x, and the width is 1 3x the length and width is 5 12x 15

x 36, so the length is 27cm, the width is 12cm, and the volume is 36cm3 high

2 From the inscription, it can be seen that the books in the fourth and fifth grades are equal, so there are x books in the fourth and fifth grades, and y books in the sixth grade.

1／3x＝1／4y

x＝3／4y

You can also list the equation: x x y 180

y＝72，x＝54

So 54 books for the fourth grade, 54 books for the fifth grade, and 72 books for the sixth grade.

1。Solution: If the height is x, the length is 3 4x, and the width is 1 3x, and there are 3 4x-1 3x=15cm

x=36cm

So height = 36cm, length = 27cm, width = 12cm, volume = 36 * 27 * 12 = 11664 square centimeters.

There is a problem with question 2, and I can't do it.

If the height is x3 4*x-x 3=15, and x=36, then the height is 36, the length is 27, and the width is 12, then the volume is 36*27*12=11664

Then 3x+3x+4x=180 x=18

then the fourth grade gets 18*3 54

5th grade 18*3 54

6th grade 18*4 72

1. The length is A, the width is B, and the height is H

a=3/4h,b=1/3h

a-b=15

h=45,a=,b=15

2. The question was not asked.

1.Set the length to x, the width to y, and the height to z

According to the problem, it is obtained: x=3 4z, y=1 3z, x-y=15 solution: 3 4z-1 3z=15

z=36x=3/4z x=27

y=1/3z y=12

x*y*z=11664

1. Set the length to a, the width to b, and the height to h

System of equations available: a=3 4h (1).

b=h/3 (2)

a=b+15 (3)

Substituting (3) into (1): b + 15 = 3 4h (4) substituting (2) into (4): h 3 + 15 = 3 4h gives h = 36, b = 12, a = 27

The volume is 11664

2 Let the equal number be x

The available equation: 3x+3x4x=180, x=18 is 18*3 54 for the fourth and fifth grades, and 180 54*2 72 for the sixth grade

Question 1: Length: Height 3 4:1 2:4 9:12 Height: Width = 1 3:1 = 1:3 = 4:12

Length: Width = 9:4

15 (1-4 9) = 27 (cm) long.

27 3 4 36 (cm) high.

27*4 9 12 (cm) wide.

27*36*12＝11664(cm^2)

Question 2: If the book for grade 4 is A, then the fifth grade is also A, and the sixth grade is B

Then there is 2a+b=180 a 3=b 4 and the solution is a=54 b=72

1 All 1 set a price reduction of x yuan.

100-x）（10x+100）-80（10x+100）=2160

The solution yields x=2 or x=8

2. Let ab=x, bc=y

xy=72, 5x+2y=54 gives x=6, y=12, or x=, y=15

2 (100-x)(100+10x)- 80(100+10x)=2160

10000+1000x-100x-10x²-8000-800x=2160

10x²+100x-160=0 x²-10x+16=0 (x-3x-8)=0

x1=2 x2=8

2) Set the length to x and the width to y

2x + 2y = 54 x+ y = 7

x(27-x)=72 -x²+27x-72 = 0 x²-27x+ 72 = 0

x²-27x+72=0 (x-24)(x-3)=0

Therefore, the length is x=24 m (x2=3 is not appropriate) and the width is 3 m.

1） (100-x)(100+10x)- 80(100+10x)=2160

10000+1000x-100x-10x²-8000-800x=2160

10x²+100x-160=0 x²-10x+16=0 (x-2)(x-8)=0

x1=2 x2=8

2) Set the length to x and the width to y

2x + 2y = 54 x+ y = 7

x(27-x)=72 -x²+27x-72 = 0 x²-27x+ 72 = 0

x²-27x+72=0 (x-24)(x-3)=0

Therefore, the length is x=24 m (x2=3 is not appropriate) and the width is 3 m.

the previous year's balance; the total expenditure or total input of the previous year;

2 What does this question mean, it doesn't feel right.

Tell A and B the amount of production per day, and a total of 30 days, (3 * 40 + 2 * 50) * 30 = 6600, is the landlord mistaken?