Please answer this application question, 1 application question, please answer it

60 meters per minute is 10 meters more than 50 meters per minute.

50 meters per minute, when the class bell rings, there is 3 * 50 = 150 meters from the school.

60 meters per minute, when the class bell rings, you can walk 2 * 60 = 120 meters.

Illustrating that the speed of 60 meters is 50 meters more than 50 meters, you can go 150 + 120 = 270 meters.

Because 60 meters per minute is 10 meters more than 50 meters per minute.

So, from the time he left until the bell rang for class, there were 270 10=27 minutes.

Therefore, the distance from his house to the school = 27 * 50 + 150 = 1500 meters.

or = 270 * 60-120 = 1500 meters.

Let the time be t and the distance be s

t+3)50=s

t-2)60=s

Solution s=1500

1: The distance from home to school remains the same.

2: Time * Speed = Distance.

So: set time = x

So. 50x+150=60x-120

x = 27 minutes.

So distance = 50 * 27 + 150 = 1500 meters.

The distance from home to school is 1500 meters. It is calculated as; Let the distance be s meters, then the formula is s 50-s 60 = 5, and the calculated result is s = 1500 (meters).

Solution: Let the number of people in each group be x. Then the second batch went to 3x students, and according to the question, they got 4x+3x=210

Solve x=30

So 3x=90

A: The second batch went to 90 students.

Each group had the same number of people, with a total of 7 groups of 30 people in each group, and 90 people in the second batch of 3 groups.

Solution: There are 4+3=7 groups in the first and second batches.

Number of people per group: 210 7 = 30 people.

The number of people who went to the second batch: 30x3=90 people.

The first and second batches have a total of 4+3=7 groups, 210 7=30 people, 30*3=90 people.

Use mine.

6 3-3 1 = 15 (square meters).

200 8 8 = 12800 (square key meter).

250+80) 2=660 (m).

Width: Rolling cherry blossom 24 2-7 = 5 (cm).

Area: 7 5 = 35 (square centimeters).

1.The total length of this rope is x meters.

1-55%)x+10] x(1-44%)-10=50 to get x=

Answer: The rope is full of meters.

2.Set up x tons of fertilizer in warehouse A and y tons of fertilizer in warehouse B.

x+y=48

1-20%)x=

Solution: x=28, y=20

Answer: The original fertilizer in warehouse A is 28 tons, and the original fertilizer in warehouse B is 20 tons.

It's 4/5 (4 5).

1.The solution of the equation is:

Solution: Set X parts A and (X-12) parts B, and get:

x-12)+(4/5)x=42

9/5x=54

x=30=30-12=18 (pcs).

A: 30 pieces of Part A were produced, and 18 pieces of Part B were produced.

2.Arithmetic solution:

30 (pcs) 30-12 = 18 (pcs).

A: 30 pieces of Part A were produced, and 18 pieces of Part B were produced.

You can't get the answer from known conditions alone.

There are definitely fewer conditions.

Solution: If Company A does it for 9 days first, the remaining Company B can complete the task for another 7 days;

This sentence can be understood as: A and B cooperated for 7 days, and then A did it for another 2 days and could complete the task.

If Company B does it for 8 days first, the remaining Company A can complete the task for another 7 days.

This sentence can be understood as: A and B cooperate for 7 days, and then B does it for another 1 day and can complete the task.

So 1 day of work for B = 2 days of work for A.

Then, Company A and Company A will do it for 9 days first, and the remaining Company B will do it for another 7 days to complete the task, which is equivalent to the work of Company A: 9 + 7 x 2 = 23 days.

4600 23 = 200 pieces.

A: Company A processes 200 pieces of clothing per day.

Solution: Let A be x every day, and B y every day, then.

9x+7y=4600

7x+8y=4600

The solution is x=200 and y=400

So Company A processes 200 pieces of clothing every day.

If A and B can do x and y pieces respectively in one day, then:

9x+7y=4600

7x+8y=4600

Solve x y

Company A processes m pieces every day; Company B processes n pieces per day. According to the title:

9m+7n=4600

8n+7m=4600

m=200

n= 400

A: Company A processes 200 pieces of clothing per day.

Circumference: 420 (m).

At least it can be increased:

3600 (sqm).