8 cups, all mouth side down, if all mouth side up, turn only 3 at a time, a few steps

The answer is: in four steps.

Explanation and analysis: The three cups that are turned each time are different. In this case, each cup will be turned 3 times. If a cup is turned even number of times, it is the same as at the beginning, and if it is turned odd times, it is the opposite at the beginning, and the actual operation method is as follows:

Assuming that the up-facing quilt is represented by U and the downward-facing cups are represented by N, then the 8 cups with the whole mouth facing down are: nnnnnnnn, and then according to turning only three at a time, you can get:

1、uuunnnnn；

2、uunuunnn；

3、uununuun；

4、uuuuuuuu；

So the answer is: after four steps, you can turn 8 cups with your mouth down into mouth up.

Step 3: Stack the cups with the mouth down and turn them over, stack the cups with the mouth down and turn them over, take a cup with the mouth facing up, (take one of the cups that has been turned over) buckle it on the cup and turn it over, don't you turn it three times at a time, and turn it up three times!

Step 4: 1. Turn the 3 cups with the whole mouth down ——— 5 down and 3 up.

2. Turn 1 cup with mouth down, turn cup down 2 cups with mouth down——— 2 up and 6 down.

3. Turn the cup with the mouth down 3 times——- 5 up and 3 down.

4. Turn the cup with the mouth down 3 ——- 8 up.

Accomplish the goal.

You don't need a single step, as long as you put all the cups on the ground and you're doing a handstand, all you see is mouth up.

I used 4 steps. For the sake of convenience, I have lined up the cups and numbered them from 1 to 8 in order. The first step is 123, the second is 345, the third is 567, and the fourth is 358. Explanation: 124678 flipped once.

35 Turned three times, from the top to the top, it can be seen, and finally all the cups are facing up.

Watchtower Lord!

No. Because three cups are odd numbers, two at a time are even numbers, and n even numbers cannot be odd numbers, so they can't. Even x odd is not equal to odd.

Flip all at least 3 steps, if you flip one of the cups more than once, you have to flip 2 more steps, and so on, you can only flip 1 2n times to complete the task, n is greater than 0. It is required to turn two times at a time, and the final result is 2m times, and m is greater than 0. Since there are no positive integers m and n such that the equation:

1 2n 2m is established, so can't complete the task!

Take three cups as an example: all flip at least 3 steps, if one of the cups is flipped more than once, you have to flip 2 more steps, and so on, you can only flip 1 2n times to complete the task, n is greater than 0. It is required to turn two times at a time, and the final result is 2m times, and m is greater than 0.

Since there are no positive integers m and n so that equations 1 2n 2m hold, the task cannot be completed! The same is true for 7 cups, i.e., finding any positive integers m and n makes equations 5 2n 3m true, and there is obviously such an infinite group of m and n.

There are 3 teacups on the table, all facing upwards, and they are flipped each time.

du2 can only go through zhi several times to flip dao so that the cups of the 3 cups are all specialized.

Downward? A: No, you cannot.

Each time the turn belongs to 1, 3 are facing up the teacup is flipped into the cup mouth all down must go through an odd number of flips, each flip 2 no matter how many times, it is equivalent to each flip 1 a total of even times, odd is not equal to even, so it is impossible.

Up up up, down down up, down up and down, up and down...

No, because there are always odd numbers facing up.

Summary. Hello, hello, I'm glad to help you learn 31-22=98-5=3 pro, hello, I'm glad to help you learn 31-22=98-5=3 pro, at this time you have to look at your picture, see what the situation of your icon is like Qigao, and then the old ruler can calculate the next step

9 3 3 This is every increase in height.

So how high are the cups stacked up?

3b, but add the height of a cup.

Dear, this data is in yours**.

The height of a cup is 10, isn't it plus 7?

Yes, that's just one piece of data.

You didn't let me see your actual picture!

Didn't you just say that you have to add a difference of one cup to the top, that is, the first cup minus three.

How do you list the equation, is that so? Excuse me, b*3+(10 7).

Yes. b*3+(10 3) is that right?

What can be calculated by 3b+7 is calculated first.

Each cup is turned odd number of times, as follows:

110011, 001000, 111111, here 0 represents up, 1 represents down, then according to the above method, you only need to turn 6 times to turn all the cups up

So the answer is: 6

This is not possible We write a cup with the mouth up as "0" and a cup with the mouth down as "1" At the beginning, because the seven cups are all facing up, the sum of the seven numbers is 0, which is an even number Every time a cup is turned, the number changes from 0 to 1, or from l to 0, changing the parity

Four cups are turned at a time, so the parity of the sum of the seven numbers remains the same as the original So, no matter how many times you flip them, the sum of the seven numbers is still an even number and the seven cups are all facing down, and the sum is 7, which is an odd number, therefore, it is impossible

There are six cups, all of which are placed face down on the table If you can only turn 5 cups at a time, it will take at least a few times to get them all facing up Solution: This is an Olympiad problem about parity Each cup is originally facing down, and in order to face up, it needs to be turned an odd number of times to complete. All 6 cups are from face down to face up, and it takes 6 odd times to complete.

Flip 5 cups at a time, 5 means turn an odd number of times, and a minimum of 6 such odd times is required. So the answer is 6 times.

4 times. After the first time, it becomes 1 down 3.

After the second time, it becomes 2 up and 2 down. (You can't reverse the first 3 cups, otherwise you'll be back to the beginning.) That is, the cup that did not move for the first time should be reversed from the two cups that have been moved) this time

After the third time, it becomes 3 under 1. (Because the minimum number of times is required, this time we need to push towards the final result.) Reverse 2 cups and one of them down, and it becomes 1 up and 3 down).

Fourth: Reverse the 3 cups that are downward, and all 4 are up.

Four times, 0 for up and 1 for down.

First: 1000

The second time: 0110

Third time: 0111

Fourth: 0000

You can't say half of it.