Grade 6 math five part fraction application questions.

1.68 kilograms of cabbage were transported from the bamboo forest vegetable farm, accounting for 4 7 of the vegetables transported, how many kilograms of vegetables were transported in total?

119 kg.

2.There are 180 pear trees in the Hsinchu orchard, which is 5 8 of peach trees, how many peach trees are there?

288 trees. 3.A book is 80 pages, Liu read 15 pages on the first day, 1 5 on the second day, how many pages are left after two days?

48 pages. 4.A piece of wire, the first day used to use the full length of 1 6, the second day to use the full length of 1 3, the first day used to use 30 meters shorter than the second day to use, how many meters of this wire original?

180 meters. 5.The kilogram of an orange is 2 3 of an apple, the kilogram of a banana is 1 2 of an orange, 60 kilograms more than a banana, how many kilograms are there of an orange?

60 kg.

1.Total weight of vegetables = 68 (4 7) = 68 7 4 = 119 kg.

2.Number of peach trees = 180 (5 8) = 180 8 5 = 288.

3.Pages left = 80-15 - (80-15) (1 5) = 80-15-13 = 52 pages.

4.Overall length = 30 (1 3-1 6) = 30 (1 6) = 30 6 = 180 meters.

5.Tangerines = 60 (3 2-1 2) = 60 1 = 60 kg.

kilogram) kilogram).

page) 4Let the total length be x meters, then: 1 3x-1 6x = 30x = 180 (meters).

5.Set oranges x kilograms.

then x 2 3-1 2x = 60

x = 60 (kg).

5. Tangerine = 60 (orange = 2 3 apples, then apples = 3 2 oranges.) Banana = 1 2 oranges, then apples - bananas = 3 2 oranges - 1 2 oranges = oranges = 60).

1: Let the total number of x kilograms be shipped, then: x*(4 7)=68 Calculate:

x=1192: If there are x peach trees, then: x*(5 8)=180 Calculate:

x=2884: Let the wire factory be x, then x*(1 3)-x*(1 6)=30 calculate:

x=1805: Let the orange be x, then: x (2 3)-x*(1 2)=60 Calculate :x=60

1. Analysis: If all the pears are priced according to the profit of 11%, then the money sold will be less than 2007 yuan, and the less part is the part of the profit of 26% of the orange than the profit of 11%, so as to find the orange.

Solution: 2007-1700 (1+11%)=120 (yuan).

120 (26%-11%)=800 (RMB).

A: The purchase price of this batch of oranges is 800 yuan.

2. Analysis: All the remaining clothes are sold, and the profit is 1800 yuan, which is the full price of 1-5 8 clothes, and the total number of clothes can be found.

Solution: 1800 60 (1-5 8).

80 (pieces) 60-(1800+200) 80 = 35 (yuan).

A: The cost of this batch of garments is 35 yuan per piece.

3. Solution: (22%-10%) 20 (30%-22%)

30 (kg).

A: Add 30 kg of saline with a concentration of 30% to get a saline with a concentration of 22%.

Let x kg of 30% brine be added, and the equation is obtained: 10% 20 + 30% x = 22% (20 + x)].

4. Analysis: Purchase price (1+35%) 90% = purchase price + profit + "hit" fee.

Solution: Let the purchase price be x yuan, then.

x ×（1+35%）×90%=x+208+50

1+35%）×90%-1]x=208+50

x=(208+50) 1+35%) 90%-1] (arithmetic minus x and =).

x=258÷

x=1200

A: The purchase price of this kind of TV is 1200 yuan.

1) Set the purchase price of orange x yuan.

x * 1 + 26%) 1700 - x) *1 + 11%) = 2007

Solve x 800 (yuan).

2) 1800 yuan is 1 5 8 3 8 The price of this part is 1800 3 8 4800

The cost is 4800 1800 200 2800 (yuan) 3) set to add x kg.

Then 20 * 10% +30% x = (20 + x) *22%.

Solve x 30 (kg).

4) Set the purchase price to x

Then (1 + 35%) x * 90% -x - 50 = 208 solution x 1200 (yuan).

I'll help you go to the math forum and ask

The length of a rectangle is increased by 10 1, and the length (1+1 10). The width was reduced by 10 1, and the width was the original (1-1 10).

then the area is the original (1+1 10)(1-1 10)=99 100<1

The area has decreased. The difference is 1 100

1. Fifth grade: 250 (1+1 5) 300 yuan.

6th grade: 300 (1-1 10) = 270 RMB.

2. Day 1: 360 1 5=72 pages.

Day 2: (360-72) 1 6=48 pages.

Day 3: (360-72-48) 1 2=120 pages.

How many more haven't been read: 360-72-48-120 = 120 pages.

3. The next day, the next day rolling, or: (1-1 5) 4 9 = 16 49 sold in two days: 1 5 + 16 45 = 5 9

1.250 (1+5 1)=300 [5th grade] 300 (1-1 10)=270 [6th grade] 2360 (1-1 5)=288 [Soqing left after the first day] 288 (1-1 6)=240 [left after the second day] 240 (1-1 2)=120.

3.1-1 5=4 Chizhen 5 4 5 (1-4 9)=4 9 1-4 9=5 9 [Five-ninths of these fruits were sold in these two days.]

1.The fifth grade donated 250 * (1 + 1 5) = 300 yuan.

2.On the first day, I read 360*1 5=72 pages.

The next day, I read (360-72)*1 6=48 pages.

On the third day, I read (360-72-48)*1 2=120 pages.

There are also 360-72-48-120=120 pages.

3.The two days of these fruits sold are 1 5 + (1-1 5) * 4 9 = 5 9

One. 250+1 Kaiyin 5*250=300 (Yuanjiana Hall) 300-(300*1 5)=240 (Yuan).

Two. On the first day, I read 360*1 5=72 (pages).

The next day, I read (360-72) * 1 6 = 48 (pages) Min ruined.

On the third day, I read (360-72-48) * 1 2 = 12099 pages) and 360-72-48-120 = 120 (pages) three. A total of 1 5 + (1-1 5) * 4 9 = 5 9 of these fruits were sold in two days

1. Fifth grade: 250 (1+1 5) 300 yuan.

6th grade: 300 (1-1 10) = 270 RMB.

2. Day 1: 360 1 5=72 pages.

Day 2: (360-72) 1 6=48 pages.

Day 3: (360-72-48) 1 Shan Dou 2 = 120 pages.

There are also many limbs but the manuscript is less than I haven't read: 360-72-48-120=120 pages.

3. The next day: (1-1 5) 4 Lixiao 9=16 49

1.Fifth grade: 250 (1+1 5) = 300 yuan.

Grade 6: 300 (1-1 10) = 270 RMB.

Page. 208 (1-1 6) = 240 pages.

240 (1-1 2) = 120 pages.

4 5 4 Interception 9 = 16 45

1 250 + 250 * one-fifth = 300 300-300 * one-tenth.

PLA soldiers reclaim a parallelogram-shaped vegetable patch. It has a base of 24 meters and a height of 16 meters. What is the area of the land?

2. A trapezoidal wheat experimental field, with an upper bottom of 86 meters, a lower bottom of 134 meters, and a height of 60 meters, how many square meters is the area of Li Yin? How many hectares?

3. A triangular piece of land, the bottom is 358 meters, the height is 160 meters, how many square meters is the area of this land? How many hectares?

Second, the total application problem is suspicious.

1. The PLA transport company transports a batch of coal, and if each truck is loaded with tons, it takes 16 vehicles to transport it at one time. If each truck is loaded with 6 tons, how many vehicles do you need to transport it all at once?

The main question? I'm a lot ==

Teacher Dead Man has done a lot for us ...

1.There is a vegetable field and a wheat field, half of the vegetable field and 1 3 of the wheat field is 13 hectares, and half of the wheat field and 1 3 of the vegetable field is 12 hectares. How many hectares of wheat are there?

2.If a kilogram of cooking oil is taken out of each of the two barrels, then 5 21 of the remaining oil in barrel A is equal to 1 3 of the remaining oil in barrel B. How many kilograms of cooking oil did each of the two barrels have?

3.There are a total of 1,300 students in A, B and C, and if the number of students in school A decreases by 1,11 and the number of students in school B increases by 64, the number of students in the three schools is equal. How many students are there in each of A, B and C?

Although I have graduated from the sixth grade, I feel that I have not learned the score problems well, so I would like to ask 1. 1. Each person in the kindergarten class will be given 17 pictures, and each person in the kindergarten class will be given 13 pictures, and the number of students in the large class is 3 5 in the small class

12 people are the least (1 12 + 1 4 + 2 3 = 1 when the number of people is the least) then more than 1 20 people do not give up their seats, there will be a year of passengers standing Answer: Let the total number of people be x, more than y (score) people do not give up their seats, there will be elderly passengers standing 2 15x less than 1 12x + yx

So y is greater than 1 20

1/4=3/12 ; 2/3=8/12;

So the number of elderly passengers is minimal.

So more than 1 20 people do not give up their seats, and there will be elderly people standing.

Old age, one in twentieth (absolutely correct).

Assuming that the original worker is 1 and the output is 1, the production efficiency is 1

Now the workers are, the output is, and the production efficiency is.

As a result, the production efficiency is now 175% of the original

（1+40%）/(1-1/5)=

The current production efficiency is 175% of the original level

Production efficiency = output number of people.

Original production efficiency = original output Original number of people.

Current production efficiency = current production Number of people now = (40% of the original production) 4 5).

Current productivity: original productivity = 40% 4 5 = 1 2 = 50%.

The number of original workers is x, the output is y, and the production efficiency is z

z=y x the number of active workers is, and the efficiency is the current work efficiency.

So now the production efficiency is 175% of the original.