Math problems are not required to be done in full. Math problems will not be done

1.Solution: Let x1 and x2 (x1>x2) be the two solutions of the equation.

x1+x2=-3;

x1*x2=-2m;

x1-x2=3;

Solve the above three equations to obtain:

x1=0;x2=-3;m=0;

Substituting the equation yields: x 2 + 3x = 0

So m=0;

2.The method is similar to the previous question.

Solution: Let x1 and -x1 be the two solutions of the equation.

because x1+(-x1)=(k-1);

So k-1=0

k=1;Solve the above three equations to obtain:

x1=0;x2=-3;m=0;

Substituting the equation yields: x 2 + 3x = 0

So m=0;

Substituting the equation yields: x 2-5 = 0

x=plus or minus root number 5;

The equation has two solutions, so k=1;

3.(omitted) refer to questions 1 and 2.

4.Solution: Let the third side length be c;

There are two scenarios:

The first type is the third edge.

From the Pythagorean theorem:

3^2+4^2=c^2;

Solution: c=5; (or c = -5, unreasonable, rounded) the second type: the side of length 4 is the positive side.

From the Pythagorean theorem:

3^2+c^2=4^2

Solution: c = root number 7; (or c = negative root number 7, unreasonable, rounded) In summary, the third side length is 5 or the root number 7

ps: I feel like this is a junior high school math homework, and I should do it myself.

Hehe, it's obvious that this is a middle school math problem.

I envy your wit.

It is very good at using network resources, and if you use the office formulator to type it out, it will look more professional and easier to solve.

The funnel of a rice mill is composed of two parts: a cylinder and a cone, the bottom diameter is 4dm, the cylinder is 2dm high, and the cone is 4dm high. Rice weighs per cubic decimeter. What is the maximum number of kilograms of rice that this funnel can hold?

If the rice yield is 70%, how much rice can be ground in a funnel of rice?

Solution: First calculate the volume of the funnel, since the bottom diameter is 4dm, the bottom radius is 2dm. The formula for the volume of the cylinder is v= r 2h, and the data is substituted to get v1= 2) 2 2 cubic decimeters.

The volume formula of the cone is v=1 3 r 2h, and the substituting data gives v2=1 3 2) 2 4 cubic decimeters. So the total volume of the funnel is v=v1+v2 cubic decimeters.

Then calculate how many kilograms of rice the funnel can hold, because the weight of rice per cubic decimeter is w=.

Finally, calculate how much rice can be ground in a funnel of rice, because the rice yield of rice is 70%, so the weight of rice that can be ground in a funnel of rice is m=.

A: This funnel can hold up to paddy, and one funnel of paddy can grind rice.