In the second year of junior high school, you need steps, but you really can t do it.

The second year of junior high school?We may not have the same version.

1.The inverse proportional function y=k x passes through the point (-3,1), k=-3*1=-3 The inverse proportional analytic formula is: y=-3 x

When x=1 2, y=-6 combines the two points (-3,1) and (1 2,-6) to give 1 2m+n=-6 and -3m+n=1

The analytical formula of the primary function is calculated to be y=-2x-5

2.y=k x (m+1,1) y=m+1 x

And since "the equation x -2mx + m + 2 = 0 has two equal real roots" there is 4m -4(m+2) = 0, i.e. (2m-1) = 9

m=2 or -1, m=2, y=3 x which is y, and the range is y -3

m=-1 y=0?Is the question wrong?This shouldn't be on topic. Because k≠0 is m≠-1

1) 1 and 3 quadrants b(1 2,-1) 2 and 4 quadrants I don't know much about this yet, we haven't learned this yet.

4.If the speed of the cyclist is x, then the speed of the car is 2x, and the time is equal because they arrive at the same time

10/x=10/2x+1

The solution is x=5 answers....

In the last question, multiply the numerator and denominator by 12 at the same time to get 8x-9y, 9x+18y

If you're a little tired, go and rest first (bye-bye.

, do your homework.

You can't do it so easily, you're a vegetarian??

Question 1 x —y —(x-y)=(x+y)(x-y)-(x-y)=(x+y-1)(x-y).

So a=x+y-1

Question 2 (2x+5) -2x-5) =4x +20x+25-(4x -20x+25)=40x

Question 3: Let the original side length of the square be x

x+3)²-x²=45

x²+6x+9-x²=45

6x+9=45

x=6, so that the original side length of the square is x

x²-(x-3)²=45

x²-(x²-6x+9)=45

6x-9=45x=9

Don't mess with these questions, just take them apart step by step, don't be afraid to make mistakes, at least that's what you do. The first and second questions are taken apart in parentheses, and the third one is figuring out the equations.

x 2-y 2-(x-y)=(x+y)(x-y)-(x-y)=(x-y)(x+y-1)so a=(x+y-1).

According to the sum of squares formula (a+b) 2=a2+b2+2ab, (a-b) 2=a2+b2-2ab

(a+b) 2-(a-b) 2=2a 2+2b 2+4ab gives the original formula =4x 2+50+40x

Suppose the original side length is a, then the area is a 2, and the side length increases by 3 and the area increases (a+3) 2-a 2=6a+9=45, so a=6

Similarly: a 2-(a-3) 2=6a-9=45 gives a=9

ap=2,aq=6,q-o-oa,amq aob,aq ab=qm ob,6 10=qm 8,qm=

s apq=1 2ap qm=1 2 2 square units)s quadrilateral opqb=s aob-s apq=square units) <

t=2, op=6-2=4, bq=2*2=4, therefore, the coordinates of q point are (8*3 5,6*2 5) i.e. (24 5,12 5), since sopq=4*24 5 2=48 5, sobq=8*12 5 2=48 5, therefore, the area of the quadrilateral opqb is 96 5 square units.

According to the title: OA=6, OB=8, AOB is a direct triangle.

According to the Pythagorean theorem ab 2=oa 2 + ob 2 AB=10

After the Q point to do the high QM of QAP (M point is on OA), AMQ is similar to AOB.

then according to the similarity triangle theorem.

am/ao=aq/ab=mq/ob

Get am=mq=

The area of a quadrilateral pobq is equal to the area of AOB minus the area of apq.

That's 6x8

Let the edge ap of the triangle apq be high as h

sin oab=8 10=h 8 to get h=

Area of the triangle apq = 1 2*2*

Area of OPQB = 1 2*6*

I hope you can calculate the specific steps yourself, I only provide ideas, the general is the big triangle OAB minus the small triangle AQP, the base and height of the small triangle is the abscissa of AP and Q, write the relationship with time. Try it yourself

1) The ordinate does not change during the excitation of a unit of triangular OAB to the right along the X-axis. Swiftness.

Substituting y=3 into y=6 3 x yields x=2 3

So a=2 3-(-3 3)=5 3

2) If the corresponding point of the triangle OAB around the point Mingchang Qing O is rotated 30 degrees in the counterclockwise direction and the corresponding point of b is E, then OE = 6

If e is done on the x axis of em on m, then em=3, om=3 3, so e(-3 3,-3).

Substituting e(-3 3,-3) into y=k x yields, k=9 3

1, because point A happens to fall on the inverse proportional function image, and the coordinates of the traces and a are also known to be merged with the state, and it is translated to the right, then 3=6 3 x is obtained

then x=2 3. Then the coordinates of point A after the evaluation are (2, 3, 3).Then a=2 3-(-3 3)=5 3

2, it won't.

First of all, you have to like mathematics, understand the basics, and you will naturally be able to do problems, and you have to memorize more formulas. If you are not annoyed, you can preview what you will go on later, try to retrace some formulas and theorems by yourself, this is a compulsory course for mathematical methods, such as x 0sin(x) x 1 It is necessary to push it down, and the Lagrange median theorem and so on and many other things. Anyway, when I was studying high math, I reasoned.

Hello, it's that you don't need to extract x, it's =(xy-x) xy x-y

x²y²-x³y/x-y

x²y(y-x)

x²y