Grade 8 Mathematics Simplification Questions, Junior 2 Mathematics, Simplification Questions Urgent

Simplification: [5xy (x -3xy)-(3x y) 5xy) [5x 2y 2(x-3y)+27x 6y 6] 25x 2y 2).

x^2y^2[5x-15y+27x^4y^4]÷ 25x^2y^2）(5x-15y+27x^4y^4)/25

a+2）²（a-2）²（a²+4）²

a²-4）²（a²+4）²

a^4-16)^2

x+y-z）（x-y+z）

x+(y-z))(x-(y-z))

x^2-(y-z)^2

x^2-y^2+2yz-z^2

a+b）²+a+b）（a-b）-2ab

A 2 + 2 Ab + B 2 + A 2-B 2-2 Ab2A 2 Decomposition Factor: m +6m +9m

m(m^2+6m+9)

m(m+3)^2

ab（a-b）²+a（b-a）²

ab（a-b）²+a（a-b）²

ab（a-b）²(b-1)

x to the fourth power +8

1/2(x^4-16)

1/2(x^2+4)(x^2-4)

1/2(x^2+4)(x-2)(x+2)x²-5）²+8（5-x²）+16

x²-5）² 8（x²-5）+16

x²-5 -4）²

x²-9）²

Typing is not easy, such as satisfaction, hope.

1 root number 3

2 The root of the second is number six.

3 Three-tenths of a five.

4 Fifteen trumpets n

5 y times the root number 2x

6 Nine Roots No. Y

I have read the other answers below ,,,, and they are all wrong!!

Root number 32 + root number 98/2

Root number 32 + root number 4 of 196 times root number (up and down at the same time multiply root number 2, the denominator is rationalized) = 4 times root number 2 (root number 32 = root number 16 * root number 2, root number 16 is equal to 4, so root number 32 is equal to 4 times root number 2) + one-seventh (root number 196 = 14, root number 4 is equal to 2, and after about a fraction is equal to one-seventh).

1/2 of the root number 20-5 times the root number + 5 root number

Twice the root number 5 (the root number 20 is equal to the root number 4 times the root number five, and the root number four is equal to 2, so the root number 20 is equal to the second root number 5) - half times the root number two (the root number is multiplied by the root number two at the same time up and down by the root number, and the result is the root number 2 of the two, and the root number of the two times the root number of the second multiplied by the root number 5 becomes the root number 2 of the fifth of the two) + the root number five.

Root number five - five times the root number two.

Root No. 18 Root No. 2 - Root No. 12 Root No. 3

Root number 36 (the root number multiplied by the root number is equal to the number in the multiplication, and then the root number is written on the outside) - the root number 36 = 6-6

Root number 12 minus root number 3 equals 2 root number 3 - root number 3

Equal to the root number 32.

Gen Fang Na No. 8 minus root No. 32 plus 2 times the root number 2 equals 2 root number 2 minus 4 root number 2 + 2 root number 2 equals 03. A is equal to the root number 34

We haven't handed over the four points yet, what is this thing?

First factoring, then general division, the process is as follows:

x+1）/（x-2）-x/（x^2-2x）]（x-4/x)=[（x+1）/（x-2）-x/x（x-2）]（x-4/x)=[（x+1）/（x-2）-1/(x-2)]（x-4/x)=（x-4/x)

x/(x-2)]（x-4/x)

x/(x-2)]（x^2-4)/x

x/(x-2)]（x^2-4)/x

x (x-2)](x+2)(x-2) x writes the numerator and denominator together.

x/(x-2)]（x+2)(x-2)/x=x（x+2）（x-2）/[(x-2)x]=x+2

The first question seems to be a bit problematic.

**There is a detailed process...

Solution: Original formula = 2 (root number 2-1) + root number [17-2 (root number 72)] = 2 (root number 2) - 2 + root number 9 - root number 8

2 (root number 2) -2 + 3 - 2 (root number 2) = 1

It's a bit troublesome to play the root number, let's talk about the idea, first of all, decompose the formula in the big root number with a perfect square formula.

3-2 root number 2 = 2-2 root number 2 + 1 = (root number 2 -1). The second formula is the same, and the formula inside the root number is factored using a perfectly squared formula. Note: To split 17 into 9+8. The next steps should be fine.

If you don't understand, ask again.