Kneel down for a junior high school physics question that can stump the physics teacher!!

pwd=1234 Extraction code: 1234 Introduction: Junior high school physics high-quality materials**, suitable for teachers at all stages, daily tutoring of students, sprint for the high school entrance examination, and skill improvement learning.

1.Under the appearance of h0, h0 is (e1 0 ) h'=( h'<(0 e2 ), and the probability that the system is in the excited state at all times.

2.Estimate the ground state energy of a one-dimensional harmonic oscillator. ze/r, r3.The actual hydrogen-like atom is not a point charge, his electric potential x(r)={ ,ze r,r>r

Find the first-order correction of the 1s energy level of the atom.

4.Knowing that two identical particles have spins of s, we find the probability that the system is in a spin symmetric state and a spin antisymmetric state.

5.It is known that under the appearance of lz, lx = 1 root number 2 (0 1 0 ) ly=1 root number 2 (0 --i 0 ).

1 0 1 --i 0 --i

0 1 0 0 --i 0

1) It is known that in the (0) state, find the possible measured value of lx and the corresponding probability.

2) In the state of "Justifiable" = (1 2), the probability that the possible measurement of lz is +1.

1 root number 2 hehe, I support playing you physics teacher.

It's easy to do. 1) You just ask him why walking to school is more tiring than cycling to school?

According to w=fs, it should be the same.

Ask him why the force of the wind on the kite is perpendicular to the surface of the kite when it is in the air.

Both of these questions look simple, but are difficult to explain.

Topic: What did the 2007 Nobel Laureate in Physics discover? And tell me what the nature of what he found

I'm in junior high school, believe me, this question is right.

Answer:1. Giant magnetoresistance effect (GMR).

2.The properties are: the greater the magnetic field, the greater the resistance.

You go online to find the 15th National Junior High School Physics Application Knowledge Contest (Semi-final) The fifth big question is a picture problem, don't think it's simple, but you don't know where to start, you print it out and give it to your teacher to do.

And if he still does it, you leave me a message, I left a physics problem in junior high school, and I asked my current high school physics teacher, and he couldn't do it, but he did it in the end, and it used the physics teacher, the math teacher, and I finally figured out why there is a math teacher? Because this problem is very demanding to find the best value, but it also needs to be based on physics knowledge.

Prove whether the rest mass of a photon is 0

Scientists are trying to prove it).

If he proves it, it means that he is capable of arrogance.

If the proof comes out that it is not 0, congratulations, a large part of physics will be overturned, and it will be easy in the future.

A particle of mass m is confined to two impenetrable ones of r = a and r = b.

Motion between concentric spheres. There are no other potentials, and the ground state energy and normalized wave function of the particle are found.

This question. But I guess you can't even read the title. Quantum mechanics questions for the graduate school entrance exam.

The 4th Talent Cup Junior High School Physics Application Knowledge Contest Multiple Choice Question 5 - Resistance.

The title is easy to remember, but I'm afraid it's difficult!Anyway, my physics teacher won't, you try, maybe it will work.

Input**.

Why does the rising bubble gradually grow larger when the water is just boiling?Why is it that after boiling for a while, there are no more bubbles?

I don't know how good your physics teacher is, try this, he didn't answer when I asked him in junior high school.

The airplane uses the lift of the air (the pressure difference acting on the upper and lower wings) when flying in the air, but the plane can still fly normally when it is upside down (belly up) in the trick flight, why?

Ask him what Einstein's favorite snack was when he was a child.

When inverted, the bottom is small and the top is large. The downward gravity of 1 kg of water remains the same, but the side walls of the container share part of the downward force, so the pressure on the bottom surface decreases.

To add, the title does not say that the container is full of water, so it is considered as if it is not full. Then the depth of the liquid becomes higher after the flip, and the pressure increases.

It should be that the pressure of the water around the container has increased, so the pressure has increased, the previous pressure is the pressure of the water on the bottom of the bottle, and after the inversion, it is the pressure of the water on the mouth and side wall of the bottle.

What's the explanation?,No!f／s=p。The liquid pressure is only related to depth, f=ps. The pressure does not change, the area becomes smaller, and the pressure decreases.

For containers before inversion (small bottom and large bottom), the pressure generated by the gravity of the liquid on the bottom of the container is equal to the gravity of the liquidAfter inversion (the upper bottom is large, the bottom bottom is small), due to the pressure generated by the liquid gravity, part of the pressure acts on the bottom of the container, and the other part acts on the side wall of the container, so the pressure becomes smaller.

The mass of A is greater than the mass of B, so the buoyancy of A is greater than that of B, so the volume of water discharged by A is greater than that of B, and the volume of water under water is greater than that of B.

Therefore A is wrong, B is wrong.

The volume of the outcropping of the water is equal, so the total volume of A is larger than that of B.

As for density, if the two are equally dense, the volume of the water outcropping should be proportional to the mass. Now that they are equal in volume above the water, it can be deduced that A is denser than B. Hence c pairs. The first half of the d sentence is true, but the second half is wrong.

b. Reduce friction between machines.

A is not true: It should be to increase the ratio of useful work to total work, not simply increase useful work.

c False: The ratio of useless work to total work should be reduced, not the total work.

dNo: the mechanical quality does not affect the power.

Choose a b

A is to increase the useful work, b is to reduce the useless work, and with the total work unchanged, they can both improve the mechanical efficiency.

c. Reducing the total work, all other things being equal, the useful and useless work are also reduced proportionally, and the efficiency cannot be improved.

d. Reducing the quality of the machine The quality of the machine and the useful work are not necessarily related in this problem, and the efficiency cannot be improved.

If it's a single choice, then choose A

The work done by the machine is based on various frictional forces to achieve movement, and if the friction decreases, then the total efficiency also decreases.

It does not improve mechanical efficiency.

To do this type of question, you need to be familiar with the formula.

By w=mgh=10800t*1000kg t*10nkg*50m=

q=mq,q=,q=3*10 7.m=180kg

Because the fuel gauge is an ammeter modification.

The current in the circuit, i=u (r+r'), when r changes, the current is not proportional to r, so the scale of the oil gauge is not uniform.

According to ** data: the fuel gauge is modified from the ammeter.

When fully fueled; The current passed by the fuel gauge is: 3 5=

Brought to the left figure: when the rheostat R slides to the A terminal, the oil volume is full R=0;u=' (1)

When the oil is empty; The current passed by the fuel gauge is:

Brought to the left figure: when the rheostat r slides to the b terminal, r=50, you can get u=')=') (2)

Namely:'=')

5r'=10 ohms (where: when the oil volume is full, r=0, the on-current is ).

I can't see the picture clearly, but it's a little bit positive.

It feels like the question hasn't been copied ......

1) p = f (4s) = mg (4s), the axle spacing may be a redundant condition (2) it feels like a chase problem, you can consider drawing on straw paper, and at the same time pay attention to the unit in front of the car: 1min stroke + 50m

Rear car: 1min stroke.

Just subtract it. 3) The size is multiplied by 1min of the time of the trip.

So 1 minute later 50+50 100m apart

WF FS 72 60 1 600 720 joules.