How many 10 inch helium balloons can carry a 500g box into the sky? 5

Updated on technology 2024-03-05
9 answers
  1. Anonymous users2024-02-06

    I feel five or six hundred.

  2. Anonymous users2024-02-05

    If you say 10 inches is China's city inch, it is about 300 mm in diameter and 150 mm in radius, the volume of this balloon is about: v = 4 3x XR 3 and the density of helium is about, the density of air is about if you don't count the weight of the balloon itself, the weight of the object that each balloon can lift is w Then, all gravity and buoyancy should be balanced, you can list: , that is, the mass of helium plus the weight of the object is equal to the buoyancy of the air on the balloon because, the previous has known v, after substitution, The weight of the object that can be lifted by a single balloon can be obtained w = (that is, the weight that a single balloon can lift grams of 2 catties is about equivalent to 1 kilogram, which is 1000 grams, so the approximate number of helium-filled balloons required to lift a weight of 2 catties is:

    1000 means that to lift a 2-pound weight, about 67 10-inch helium balloons are needed.

  3. Anonymous users2024-02-04

    Eh, sudden death, you are on vacation Hongfeng Lake internship, why bother, the amount you want to Jinfoshan, you eat the co-pilot refuses.

  4. Anonymous users2024-02-03

    Generally, there are 13L, 22L, 40L, etc. Under the general filling pressure, 13L can be charged with 30 10-inch balloons, and 22L can be charged with about 50.

  5. Anonymous users2024-02-02

    If you say 10 inches, it is equivalent to a diameter of 300 mm and a radius of 150 mm. The volume of such a balloon is about the size of the balloon: v = 4 3 x x r 3 l.

    Whereas, the density of helium is about , and the density of air is about . If the weight of the balloon itself is not counted, the weight of the object that can be lifted by each balloon is w. Well, all gravity and buoyancy should be balanced and can be listed:

    w = , which is the mass of helium plus the weight of the object equal to the buoyancy of the air on the balloon.

    Because, we already know v before, after substitution, you can get the weight of the object that a single balloon can lift w = = . That is, a single balloon can lift grams of weight.

    2 catties is equivalent to about 1 kilogram, which is 1000 grams, so the approximate number of helium-filled balloons required to lift 2 catties of weight is: 1000 Zen leaks and 67 first grips. In other words, to lift a weight of 2 pounds, you need about 67 10-inch helium balloons.

  6. Anonymous users2024-02-01

    To put it simply, items that weigh no more than 2 pounds may be able to fly into the sky.

  7. Anonymous users2024-01-31

    It can fly, and the general large balloon is filled with helium, which has a relative molecular weight of 2, which is less than the average relative molecular weight of air of 29, and is an inert gas, which is safe.

  8. Anonymous users2024-01-30

    Look at the average weight.

    The weight of the object of 2 catties is about 98n, ignoring the weight of the balloon, 0 1atm helium is, air is, help here.

  9. Anonymous users2024-01-29

    1. Full air density:

    Helium density: buoyancy: f = (air density - helium density) * g * v = 100 * g (

    v = cubic meter.

    The weight of the balloon skin, the basket is not taken into account. There is a lot to think about actually making balloons.

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