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There are many ways to test this.
First: SO2 has bleaching properties, and SO3 has no bleaching properties.
Second: SO2 has strong reducibility, SO3 has no reducibility. SO2 can fade the acidic KMno4 solution, while SO3 does not react with the acidic KMno4 solution.
Third: SO2 is a gas and SO3 is a solid.
Fourth: Under normal conditions, SO2 gas does not react with concentrated H2SO4, and SO3 gas fumes when it encounters concentrated H2SO4 to generate oleum acid.
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Sulfur trioxide is oxidizing and sulfur dioxide is reducing. Get starch, potassium iodide or a similar redox test reagent to detect it.
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Hold them separately in water, SO2 becomes sulfurous acid, and SO3 becomes sulfuric acid, and the reaction formula is as follows:
so2+h2o=h2so3 so3+h2o=h2so4
This is more difficult, it needs to be weighed, it is necessary to have two solvents of the same mass, and the same volume of SO2 and SO3 (the mass must not exceed their solubility, in order to be more accurate, the experimental sample should be used more) fully dissolved and weighed, and the large mass is SO3.
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Cooling, sulfur trioxide is solid at zero degrees Celsius, and sulfur dioxide is gaseous.
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At room temperature, sulfur trioxide is liquid and sulfur dioxide is gaseous (melting point, boiling point.
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Sulfur dioxide is inspected.
Gas Method 1:
The gas is passed into a purple solution of acidic potassium permanganate.
If the solution fades, then it is sulfur dioxide gas.
Principle: Strong reducibility of sulfur dioxide.
Makes strong oxidation.
The acidic potassium permanganate is reduced to a colorless substance.
Method 2 for testing sulfur dioxide gas:
The gas is introduced into hydrogen sulfide.
In aqueous solution, if a yellow precipitate is observed, then it is sulfur dioxide gas.
Principle: SO2+2H2S=5S+2H20.
Method 3 for testing sulfur dioxide gas:
Pass the gas into the magenta.
In solution, if the magenta fades and under heating conditions, the magenta turns red, then it is sulfur dioxide gas.
Principle: Sulfur dioxide reacts with certain colored substances in magenta to form unstable color-finding substances.
Method 4 for testing sulfur dioxide gas:
The gas is passed into the iodine wine.
, the solution turns white and bubbles are produced, then it is sulfur dioxide gas.
Principle: SO2+2+2H20==H2SO4+2HI.
Sulfur dioxide (or H2SO3) can fade the magenta solution, and it is much more than sulfur dioxide that can fade the magenta solution.
Proven with simple experiments:
1. Gases such as Cl2, NO2, and O3 can also make the magenta solution fade quickly.
2. Dilute H2SO4, dilute HCl, and dilute Hno3 can make the magenta solution fade quickly.
3. Hydrogen peroxide.
Bromine water and iodine water can also fade the magenta solution.
Therefore, the correct test method for the detection and identification of sulfur dioxide must pass sulfur dioxide gas into a test tube containing magenta solution, and observe the changes in the color of the magenta solution. Heat the tube and observe how the solution changes.
Therefore, to test and identify whether a gas is sulfur dioxide, it is not only necessary to see whether the gas can fade the magenta solution, but also to see whether the fading solution can reappear the color of magenta under heating conditions, which is the most characteristic and special property and inspection (identification) method of sulfur dioxide gas.
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Very simply, you can use lead acetate test strips or solutions, what can turn black is hydrogen sulfide gas, and what does not turn black is sulfur dioxide.
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It can be identified with bromine water:
Bromine water and hydrogen sulfide and sulfur dioxide redox reaction and carbon dioxide Zheng Jiao Sui no reaction bromine water and difan wax sulfur oxide: 2H2O + br2 + SO2 = = 2HBR + H2SO4 phenomenon: bromine water fades.
Bromine water and hydrogen sulfide: br2+h2s==2hbr+s Phenomenon: Bromine water fades and produces yellow precipitates.
There is no phenomenon in the same C02.
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To distinguish between hydrogen sulfide and sulfur dioxide, it can be ignited, hydrogen sulfide can be burned in air, while sulfur dioxide is non-flammable.
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Lead reagents can also be used for different odors, and the precipitate dissolution properties formed by the two are different.
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Bromine pretends to be a rampant water.
SO2+BR2+2H2O==2HBR+H2SO4, SO2 can fade BR2.
H2S+BR2==2HBR+S (Shen Hall Car Lake), H2S can make BR2 fade and rush into S precipitation.
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It can mainly be identified from the smell is different.
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Sulfur dioxide(Chemical formula: SO) is a gas under standard conditions and at room temperature and pressureSulphur trioxide(Chemical formula: SO) is a solid under standard conditions and a liquid at room temperature and pressure.
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