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Just ask my brother!
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From the first encounter to the second encounter, they walked two round-trips, which took 4 hours, that is, a total of two hours to walk back and forth, and when they met for the first time, A walked 80 kilometers, that is, 2 hours to walk 80 kilometers, and the speed was 40 kilometers per hour. B starts from the first encounter and travels 80 kilometers to A, and then 60 kilometers from A, sharing 4 hours at a speed of 140 4 = 35 kilometers per hour.
I didn't see anyone doing it above just now, but the first floor is wrong, and the second floor is right. However, my analysis is easy to understand!
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The first encounter, car A and car B traveled a total of 1 full length, car A traveled 1 80 kilometers for the second encounter, car A and car B traveled a total of 3 full lengths, car A traveled 3 80 kilometers, and car A traveled 2 with a total length of 60 kilometers, and the total length was (80 3 60) 2 150 (kilometers) When they met for the second time, car A traveled 80 3 240 (kilometers) and car A traveled 240 4 60 (kilometers) per hour
On the second encounter, car B traveled 150 3 240 210 (km) and car B traveled 210 4 km per hour).
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1.From the first encounter to the second encounter.
B (towards A) walked a total of 80+60 140km and took 4 hours, so B's speed was 35km h.
2.From the first encounter to the second encounter, A and B walked a total of 2 whole journeys, which took 4 hours, so A and B walked a total of 2 hours.
3.The first encounter between the two cars took a total of 1 whole journey, so it can be seen that it took 2 hours, so the speed of car A (to B) was 80 2 40km hours, and the other way: the whole journey was 150km
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Full Journey: (80 3+60) 2 150 (km) The first encounter took one full journey, and by the second encounter, two more full journeys were traveled for a total of four hours, so the speed of car A was 80 (4 2) 40 (km) per hour
Car B traveled 80+60 140 (km).
And because both cars traveled for 4 hours, the speed of car B was 140 4 35 (km/h).
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Continue to draw the line segment diagram.
A and B met for the first time, and a total of 1 whole course.
A traveled 80 kilometers.
From the first encounter to the second encounter, A and B traveled 2 whole courses, of which B traveled 80 + 60 = 140 kilometers.
B speed per hour: 140 4 = 35 km/h.
A and B travel a total of 1 full time: 4 2 = 2 hours.
A per hour: 80 2 = 40 km.
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1 Let the speed of the water x, then the speed of the ship 3x, then 16(3x+x)=192 x=3
It takes 192 (3x-x) = 192 to return to Port A, 6 = 32 hours2 Set the water velocity x and the speed of A y
Then 4(x+y)=120
6(y-x)=120 The solution yields x=5 y=25 and the velocity z of B
Then 8 (z+5) = 120 solution Z = 10, then B returns 120 (10-5) = 24 hours.
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1.The speed of going down the river relative to the river bank is 4 v of water, and the speed of going up the river is 2 v of water, so it takes 16 2 to return to 32 hours.
V water is equal to 30 km per hour, v v water is equal to 20 km per hour, and v water is equal to 5 km per hour. v B v water is equal to 120 8 is equal to 15 kilometers per hour, v B is equal to 10 kilometers per hour, and when the reverse current, the speed of B relative to the river bank is 10 5 5 kilometers per hour, so B takes 120 5 24 hours against the current.
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1: Let the water flow rate x, then 4x*16=192 This problem is solved.
2: Set the water flow velocity x, then the downstream velocity of boat A is 30, and the countercurrent velocity is 20, x=(30-20) 2=5 There is no difficulty in this problem.
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This is from **.,It seems to have been done.,I'll check the homework book I've done.,But I have to send you which homework book this is.,I'm easy to find.。
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1. A construction site needs tons of loess, and it has been transported 10 times with a truck with a deadweight ton, and the rest has been transported by a truck with a deadweight ton, how many times will it be transported?
2. The fertilizer plant plans to produce 540 tons of fertilizer in 36 days, how many tons does it produce in a day on average?
3. There are 190 tons of water in pool A and 78 tons of water in pool B. Feed the water from pool A into pool B at a rate of 8 tons per minute, and after a few minutes, the water volume of the two pools will be equal?
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There is no correct answer. The area of the triangle is ( )cm. If the area of the parallelogram is 64cm, the area of the triangle is (32)cm.
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1、(2)
Now the 5th grade question, we 6th graders all think Alexander!!
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The right angle of an isosceles right triangle is 8 dm long, the area of this triangle is (32 dm, and the area of a parallelogram of equal height is (64 dm. Two identical trapezoids are put together into a parallelogram, the area of this parallelogram is 280cm, the height is 35cm, and the sum of the upper and lower bottoms of each trapezoid is (8
cm。Cut the largest triangle from a rectangular cardboard 40 decimeters long and 30 decimeters wide, and the area of this triangle is (600 cm.
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