Chickens and rabbits are in the same cage, there are 10 more chickens than rabbits, and 10 more chic

No equations. There are 10 more chickens than rabbits, and each chicken has two legs. There should be more than 2*10=20 feet. But in fact, there are only 10 more feet, and 20-10 = 10 feet less. Why.

Because chickens have 2 legs each, rabbits have 4 legs each. That is, a rabbit has 2 more legs than a chicken. That is, exchanging a rabbit for a chicken.

Just reduce 2 feet. Then you need to change a few rabbits with 10 legs. It is very simple to use 10 * 2 = 5, and use 5 rabbits for 10 legs, that is, the number of rabbits is 5, and the number of chickens is 10 more than rabbits, and the chickens are 5 + 10 = 15.

Column formula (2*10-10) (4-2)=5,5+10=15.

This is faster and time-saving than equations, but not as easy to understand as equations.

There are x chickens and y rabbits.

x-y=10

2x-4y=10

x=15,y=5

There are 15 chickens and 5 rabbits.

Hello landlord, set the chicken for x, the rabbit for y, according to the title: x-y = 102x-4y = 10

Solve x=15

y=5, so there are 15 chickens and 5 rabbits. I hope mine can satisfy you, if you have any questions, please continue to ask, satisfied, yours is the motivation I know!

If there are x rabbits, the chickens will have good luck (10+x), 4x-2(10+x)=60

4x-20-2x=60

2x=80 next to lead x=40

40 + 10 = 50 (only).

A: There are 50 chickens and 40 rabbits

Set up x jujube rabbits, and Jibi type (x+10) only regret stupid guesses.

4x-60=2(x+10)

4x-60=2x+20

2x=80x=40

x+10=50

Let x chickens, x-10 rabbits, 2x-4(x-10)=10 x=15 x-10=5 chickens, 5 rabbits.

Ten more chickens than rabbits, 60 less than rabbits, ten chickens have 20 legs, if there are no ten chickens, the number of chickens is the same as rabbits, chickens have 80 feet less than rabbits, and a chicken has two feet less than a rabbit, a total of 80 less, so it is 40 rabbits, 50 chickens.

There are 10 more chickens than rabbits, and if there are ten more rabbits, the number of chickens and rabbits is the same, and the rabbits have 100 more feet than the chickens, and common sense can know that the rabbits have two more feet than the chickens. Chicken: 100 2=50 (only) Rabbit: 50—10=40 (only).

Hello, you can assume that there are x rabbits, and according to the question, you can know that there are x + 10 chickens.

The equation can be listed according to another condition.

Solve the equation and get x = 40, i.e. there are 40 rabbits and 50 chickens.

Please refer to the following figure for the specific solution process

If there are x rabbits, then there are 10+x chickens, according to the theme.

4x－2(10+x)=60

Solve the equation and get: x=40

There are 50 chickens and 40 rabbits.

If there are x chickens, then the rabbits are x-10.

Chicken feet are 2x and rabbit feet are 4 (x-10) feet.

4（x-10）-2x=60

x=50.

x-10=50-10

40 pcs. So there are 50 chickens and 40 rabbits.

There are x chickens.

There are 10 more chickens than rabbits.

Then there are (x-10) rabbits.

Chicken feet have a total of 2x and rabbit feet have a total of 4 (x-10).

There are 10 more chicken feet than rabbit feet.

then 2x-4(x-10)=10

2x-4x+40=10

x = 15 chickens and 15 rabbits 15-10 = 5.

Solution: Let the rabbit have x, 2(x+10)-4x=10, 2x=10, x=5, so the chicken has: 5+10=15

A: There are 15 chickens and 5 rabbits.

Solution: If there are x chickens, then there are x-10 rabbits.

2×x-（x-10）×4=10,2x-4x+40=10

40-2x=10

2x=40-10

2x=30x=15, rabbits have 15-10=5,