Junior High School Physics Formulas p gh and p f S Urgent .

In the high school range p= gh is applicable to the calculation of all liquid pressures!!

p=f s can be used to calculate the pressure of a liquid, for example, if you take water and take a regular column of water, which is equivalent to a solid, so you can calculate the pressure of a liquid

f is the pressure s is the area of action.

I'm in junior high school, so let's talk about my understanding.

When the shape is clear, the solid is used with F s and the liquid is not clear with the density gh The shape is not clear, both can be used with both F s and density gh downstairs mine is right?

= m v density = mass volume car excavation acres.

p=f s pressure = pressure area under force.

p= gh Liquid Closed Land Pressure = Density Heavy Dispersion Acceleration Liquid Depth.

A: This formula is an export formula. Because.

p=w/tw=fs

So p=fs t=f(s t) (where s t=v) so p=fv

where f denotes the force acting on the object and v denotes the velocity of the object at this time.

Power is equal to the force multiplied by the velocity.

p=uip=i^2r

p=(u^2)/r

p=w/tp=f*v

Which is used in pure circuits! 1. It can be used in kinematics! W is a noisy argument orange! f is an external force, I don't know if you have learned it in the second year of junior high school!

I don't understand hi me!

Answer: This formula is an export formula. High elimination stool because.

p=w/tw=fs

So. p=fs/t=f(s/t)

Thereinto. s/t=v)

Old. p=fv

where f is the force acting on the object, and v is the speed at which the object is moving.

The first formula is when the force area is constant.

The pressure generated by the pressure exerted on this area.

The second formula should be wrong.

The pressure of the liquid is p= gh

It is related to the density of the liquid and the depth of the position in the liquid.

ρ=m/v

Density = mass volume.

p=f s pressure = pressure area under force.

p= gh liquid pressure = density gravitational acceleration liquid depth.

1 All = m v Density = Mass Volume.

p=f s pressure = pressure area under force.

p= gh liquid pressure = density gravitational acceleration liquid depth.

= m v --density = mass m volume v

p=f/s...Pressure p = pressure f area s s

p=ρgh...Pressure of the liquid p = density of the liquid * acceleration due to gravity g * depth of the liquid h

The first density, the first.

Second, three pressures, these three formulas will be used in pressure.

is the density of the object, and if the object is uniform, then the density of any part of it is the same. If you don't understand it thoroughly, let's use an analogy:

For example, if you have a pound of cake m, you have to divide it evenly (because the object is uniform) v children (each child represents 1 unit area), and the cake that each child gets is (the quality cake that each child has).

I don't know if you can understand that you don't think of v as a whole and divide it into v parts.

When I first studied physics, I had the same idea as you, but when I thought about this example, I understood.

Different objects of the same substance, with large mass and large volume, have equal ratios of mass and volume, and the density is independent of mass and volume.

Different substances of different substances, the same volume, large mass, high density.

Also, this is the formula for calculating density, knowing any two of the three quantities, you can find the third quantity.

How could it not be understood.

Mass, volume, you know, density, it's actually mass per unit volume, sad, it's really hard to say.

Actually, you can understand it by looking at their units.

First of all, it's not p but . The density of a substance indicates the characteristic that the masses of different substances of the same volume are generally different. It is defined or numerically equal to the mass m of the object divided by the corresponding volume v, which is generally stated in the book:

The mass of a substance per unit volume is called the density of that substance. Add me if you have a problem.