What is the mass and velocity formula of the theory of relativity

The formula for mass and velocity in relativity is m=m0 (v u-1)=m0 (1-v 2 c 2).

The relationship between mass and velocity is derived: the S' system (where a small ball at rest A', the mass M0) moves with velocity V along the x-axis relative to the S system (where a small ball at rest A, mass M0) moves in the positive direction of the X-axis, let the mass of A' relative to the S system be m, and according to the symmetry of the system, the mass of A relative to the S' system is also m.

Assuming that the two small balls collide and become one, the relative velocity of the S' system is U' and the relative velocity of the S system is U, and the law of conservation of momentum holds in both reference frames, the S system: mv=(m+m0)u, and the s' system: -mv=(m+m0)u'.

From the formula for velocity, u'=(u-v) (1-uv c 2), and according to the symmetry of the system, u'=-u, we get: (v u) 2-2v u+(v c) 2=0.

The solution is: v u=1 (1-v 2 c 2), since v > u, so v u=1+ (1-v 2 c 2). So m=m0 (v u-1)=m0 (1-v 2 c 2).

What is said upstairs is the mass and energy formula of the theory of relativity: e=mc 2 The formula of the relationship between mass and velocity of the theory of relativity:

m'=m [(1-v 2 c 2) (1 2)] It can be seen from this equation that under Einstein's assumption that the speed of light cannot be exceeded, the closer the velocity v of an object is to the speed of light c, its relativistic mass m'will be much greater than its rest mass" c, m'- The > is endless.

e=mc^2

where m is the mass and c is the speed of light.

The formula for mass and velocity in relativity is m=m0 (v u-1)=m0 (1-v 2 c 2).

The derivation of the relationship between mass and velocity shows that the S' system (where a small ball A' at rest and the mass M0) moves with velocity V along the X-axis relative to the S system (where a small ball A at rest and the mass M0) moves with velocity V in the X axis, and the mass of A relative to the S system is m, and according to the symmetry of the system, the mass of A relative to the S' system is also m.

Suppose that the two small balls collide and become one, and the relative velocity of the S'system is U' and the relative velocity of the S system is U, and the law of conservation of momentum holds in both reference frames, and the S system: mv=(m+m0)u, and the s' system: -mv=(m+m0)u'.

From the formula for velocity, u'=(u-v) (1-uv c 2), and according to the symmetry of the system, u'=-u, we get: (v u) 2-2v u+(v c) 2=0.

The solution is: v u=1 (1-v 2 c 2), since v > u, so v u=1+ (1-v 2 c 2). So m=m0 (v u-1)=m0 (1-v 2 c 2).

Upstairs is talking about the mass of the theory of relativity and the formula of the amount of virtual energy to be dismantled: e=mc 2 The formula for the relationship between mass and velocity of the theory of relativity:

m'=m [(1-v 2 c 2) (1 2)] It can be seen from this equation that under Einstein's assumption that the speed of light cannot be exceeded, the closer the velocity v of an object is to the speed of light c, its relativistic mass m is similar to that of the jujube'will be much greater than its rest mass" c, m'- The > is endless.

The s' system moves with velocity v along the x-axis in the positive direction of the s-system, and an object is wheeled relative to s(s') is tied to the velocity v(v'movement, then v and v'The velocity transformation relationship between v and c is related to v and c, as follows: firstly, according to the Lorentz coordinate transformation, there is a tong then x'=(x-vt) qingji (1-v 2 c 2), y'=y, z'=z, t'=(t-vx c 2) 1-v 2 .

The formula for mass and velocity in relativity is m=m0 (v u-1)=m0 (1-v 2 c 2).

The relationship between mass and velocity is derived: the S' system (where a small ball at rest A', the mass M0) moves with velocity V along the x-axis relative to the S system (where a small ball at rest A, mass M0) moves in the positive direction of the X-axis, let the mass of A' relative to the S system be m, and according to the symmetry of the system, the mass of A relative to the S' system is also m.

Assuming that the two small balls collide and become one, the relative velocity of the S' system is U' and the relative velocity of the S system is U, and the law of conservation of momentum holds in both reference frames, the S system: mv=(m+m0)u, and the s' system: -mv=(m+m0)u'.

From the formula for velocity, u'=(u-v) (1-uv c 2), and according to the symmetry of the system, u'=-u, we get: (v u) 2-2v u+(v c) 2=0.

The solution is: v u=1 (1-v 2 c 2), since v > u, so v u=1+ (1-v 2 c 2). So m=m0 (v u-1)=m0 (1-v 2 c 2).

What is said upstairs is the mass and energy formula of the theory of relativity: e=mc 2 The formula of the relationship between mass and velocity of the theory of relativity:

m'=m [(1-v 2 c 2) (1 2)] It can be seen from this equation that under Einstein's assumption that the speed of light cannot be exceeded, the closer the velocity v of an object is to the speed of light c, its relativistic mass m'will be much greater than its rest mass".

, m'- The > is endless.

The formula for the change of mass with velocity in the theory of relativity is m= m0.

where m is the mass and m0 is the static mass, which is called the Lorentz factor, and its magnitude is 1 [(1-v2 c2). From this equation, it can be seen that the mass of an object increases with increasing velocity, and when the velocity increases to close to the speed of light, the mass is close to infinity, which is also the reason why the speed of light cannot be reached.

The relationship between mass and velocity is derived: the S' system (where a small ball at rest A', the mass M0) moves with velocity V along the x-axis relative to the S system (where a small ball at rest A, mass M0) moves in the positive direction of the X-axis, let the mass of A' relative to the S system be m, and according to the symmetry of the system, the mass of A relative to the S' system is also m.

Assuming that the two small balls collide and become one, the relative velocity of the S' system is U' and the relative velocity of the S system is U, and the law of conservation of momentum holds in both reference frames, the S system: mv=(m+m0)u, and the s' system: -mv=(m+m0)u'.

From the velocity synthesis formula, u'=(u-v) (1-uv c 2), and according to the symmetry of the system, u'=-u, we get: (v u) 2-2v u+(v c) 2=0, solution: v u=1 (1-v 2 c 2), since v >u, v u=1+ (1-v 2 c 2).

So m=m0 (v u-1)=m0 (1-v 2 c 2).

Velocity synthesis formula: v(x)=dx dt= (dx-ut) ( (dt-udx c 2)) =(dx dt-u) (1-(dx dt)u c 2) =(v(x)-u) (1-v(x)u c 2) The same can be done for v(y),v(z).