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It is okay to destroy or change the original spatial structure by high temperatures, and there is no essential difference.
Protein denaturation refers to the change of the original specific spatial conformation of the molecule under the influence of physical or chemical factors, resulting in the partial or total loss of its physical and chemical properties or biological functions, which is called protein denaturation.
Physical methods such as heating, ultraviolet radiation, and vigorous ** denature proteins, usually breaking hydrogen bonds in protein molecules.
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Destruction, being altered, for example, is a carrier protein, the shape will change when transported, and if it is destroyed, the protein will be destroyed.
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Destruction, destruction is death, change is still alive.
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High temperature is the destruction of protein structure,,, there should be no change in this piece of content.
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There is not much difference, it is the same when answering the questions.
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Disruption of high temperatures renders proteoenzymes inactive.
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Okay, okay, okay, okay.
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Different proteins have different ability to tolerate high temperatures, but in general, high temperatures alter the spatial structure of proteins, which is irreversible.
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a. High temperature will change the spatial structure of the protein, and the spatial structure will be loose and noisy, and it is easy to be hydrolyzed by protein pick-up enzymes, which is correct;
B. From the analysis of A, it can be seen that B is wrong;
c. From the analysis of A, it can be seen that C is wrong;
d. Protein denaturation is a change in the spatial structure of protein spring beats, not peptide bond breakage, peptide bond break requires the catalysis of the corresponding enzyme, D error
Therefore, a
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a. The breakage of the peptide bond needs to be trapped by hydrolase enzymes, and a is wrong;
b. The composition of the elements will not change, b is wrong;
c. In the process of boiling eggs, due to the high temperature breaking the hall, the spatial structure of the protein molecule is broken, so that the protein is denatured, C is correct;
d. Amino acids are the basic units that make up proteins, and they cannot be obtained without the decomposition of related enzymes
Therefore, c
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a) Experimental procedures.
1) Analysis of the stem can be seen whether the **ethanol of the experiment can denature the protein, the independent variable is the presence or absence of ethanol, the amount of reagent is an irrelevant variable, and the irrelevant variables should be consistent and appropriate during the experiment, so the B test tube plus 5 drops of absolute ethanol as the experimental group, and the A test tube should add 5 drops of distilled water as the control
2) Analysis of experimental results.
Since this experiment is a sex experiment, the result of the experiment is that ethanol may or may not denature the protein, so there are two scenarios in which the experimental result is expected.
3) The reddish-yellow precipitate appeared in the A test tube, and the B test tube did not appear, indicating that ethanol can denature amylase (protein);
4) A test tube appeared red and yellow precipitate, and B test tube also appeared, indicating that ethanol could not denature amylase (protein);
5) The independent variable of the experiment in this experiment was the presence or absence of ethanol, group A was the control group, and group B was the experimental group
So the answer is yes or no
1) 5 drops of distilled water.
3) A test tube has a reddish-yellow precipitate, and B test tube does not appear.
4) A test tube has a red-yellow precipitate, and B test tube also appears.
5) Ethanol with or without a test tube.
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