6th grade fun math olympiad questions who have to write on the face

The fun Olympiad questions in the Olympiad should be for some grades, and the fun questions for the third grade will not necessarily be done for the 6th grade students! But I'll still share with you a kind of problem, the pirate money problem, the specific details, you can search for it in the evening!!

1). 2007-（

2).There are already a lot of people who have given the answer.

4).segment), need drama 7-1 = 6 (times).

It takes 30 6=5 (minutes) each time

paragraph), need drama 8-1 = 7 (times).

It takes 7*5=35 (minutes).

5).Interpreting the problem as finding the greatest common divisor of 2 numbers does not give [6813,8136] = 9

Because the two numbers are multiples of the greatest common divisor, respectively, 9m, 9n gives the result of 9*(m-n), and the infinite calculation is carried out until the final m=n, and the difference = 0 then m-n=1 before the difference

Extend AE, extend DC, and let their intersection point be h

In this way, the triangle AOE and the triangle GOH are similar.

and oh=3ao

GOH area = area of 9xaoe.

GOH area = 18, then HEC area = 18-11 = 7 Obviously triangle ABE area = triangle HEC area = 7 rectangular ABCD area = 4x triangle ABE area = 28

Triangular ABE area = triangular HEC area = 7

Rectangle ABCD area = 4x triangular ABE area = 28

If we consider the female representative as unit 1, then the male representative is 700 more than the unit 1, and the male representative is reduced by 1 10, which is 9 10 and 700 (1-1 10) = 630 in number.

The number of female delegates is 1-1 20 = 19 20

So it turns out that there are (1999-630) (9 10 + 19 20) = 1369 (37 20) = 740 female deputies.

There are 740 + 700 = 1440 male delegates.

Yesterday there were 1440 + 740 = 2180 people attending the meeting.

If we consider the 700 first, if they are reduced by 1,10, it will be 630, which is the reduction of the proportion of male delegates who are more female than the female delegates. The remaining male and female representatives are the same, but the reduction is different, and the sum of the reduced numbers is 1999-630 = 1369 (persons). Since the remaining male and female representatives are equally represented, then the number can be set at 20 respectively.

At this time, the male deputies decreased by 20 * 1 10 = 2 shares, and the female deputies decreased by 20 * 1 20 = 1 shares, leaving 20-2 + 20-1 = 37 shares, which is the reduced number of 1369 people. 1369 37 = 37 (person), which is 1 part. Then the number of people attending the meeting yesterday was 20 * 37 * 2 + 700 = 2180 people.

Yesterday's male delegates were divided into two parts, one with 700 and one with as many female delegates.

Today, the number of male delegates decreased by 1 10, i.e. 1-1 10 = 9 10,700 The part attended: 700 9 10 = 630 The same number of female delegates also attended: 9 10, = 18 20.

Female delegates attended yesterday's: 1-1 20 = 19 20.

1999-630 = 1369 (the same part of male and female deputies is added, tentatively called the total) Male deputies are the total: 18 18 + 19 = 18 37 Female deputies are the total: 19 18 + 19 = 19 37 The number of male deputies is partial:

1369 18 37 = 666 Number of female delegates: 1369 19 37 = 703

The number of female delegates yesterday: 703 19 20 = 740 (people) The number of male representatives yesterday: 666 9 10 +700 = 1440 (people).

How many more men (1 1 10) than women (1 1 10)?

700 (1 1 10) 630 (person).

Subtracting the number of male deputies (1 1 10) is 630 more than that of female deputies (1 1 10), the remaining number is the sum of the number of female deputies (1 1 10) and female deputies (1 1 20).

1999 630 1369 (person).

Find out the number of women delegates who participated in yesterday's meeting.

740 (person).

The total number of participants who attended yesterday.

740 700 740 2180 (person).

A: There were 2,180 people attending yesterday.

At this time, the number of male delegates is reduced by 1 10 to 700 (1-1 10) = 630, and the number of female delegates is 1-1 20 = 19 20

So it turns out that there are (1999-630) (9 10 + 19 20) = 1369 (37 20) = 740 female deputies.

There are 740 + 700 = 1440 male delegates.

Yesterday there were 1440 + 740 = 2180 people attending the meeting.

Female delegate x

Male x+700

1-10%)(x+700)+(1+5%)x=1995 solution: x=700

Total number of participants yesterday: x+700+x=2100 (people).

Let the right ones be x and the wrong ones be y

The score is 0, so the formula is.

8x-5y=0

x+y=26

And then we solve the equation and we get x=10 y=16

So do 10 questions correctly and 16 questions incorrectly.

Let it be true A and false B

Then a+b=26

8a-5b=0

Get a=10

b=16 checks. That's right. Got 10 right.

If the son gets x questions right, he gets 26-x questions wrong.

8x-5（26-x）=0

x=10

If you do the x path right, you do the wrong (26-x) way.

8x-5*(26-x)=0

8x-130+5x=0

13x=130

x=10A; 10 were right; I got 16 things wrong.

Set correct x questions and wrong y questions.

8x-5y=0

x+y=26

This gives us x=10 and y=16

10 questions are correct and 16 questions are false.

If the son does the x right way, then the wrong question is 26-x. List the equation 8x-5(26-x)=0 and simplify it to 13x=130. The solution is x=10, that is, the son has done 10 questions correctly.

If you do the x path right, then the wrong one is 26-x

8x-5（26-x）=0

x is equal to 10

Solving equations is not very fast, 8x-5y=0, x+y=26, solving x=10, y=16, do 10 problems correctly. If you don't need to solve the equation, you can also make it by pushing it down. This question should not have reached the level of the sixth grade Olympiad.