Can anyone give me a little bit of a chemistry topic and ask a chemistry question?

The calculation process is shown in the figure below, and the result is 9 times that of the original rent, <>

i.e. 270 ml.

n23h2

2NH3 starts.

Invert. x3x balanced.

1-x3-3x

2x because of n in the gas mixture

The volume fraction is a%, so there is:

1-x1-x）+（3-3x）+2x

a%x=(4a%--1) (2a%--1)1) NH in the mixture

The volume fraction is: 2x

4--2xx100%=1--4a% (you substitute x into it) 2) The pressure in the container is (4--2x) before the reaction

White precipitate E: AGCL

Phenomenon 1: White precipitation.

then a can be baco3

Equation 1 is: BaCO3 + 2HCl2 + H2O + CO2

Reaction 2 equation is: BaCl2 + H2SO4 BaSO4 + 2HCl

Phenomenon 1: No significant change.

A can be NACO3 or K2CO3

It's tiring to read your questions.

The compounds that we are familiar with that are insoluble in dilute nitric acid are BaSO4 and AGCL is AGCL

Reaction 1: BaCO3 + HCl = CO2 + BACl2 + H2O Reaction 2: BACl2 + H2SO4 = BASO4 + H2Cl

(1) CXHY, then, that is, x:y is 1 to 2, experimental CH2.

2) M=, the molecular formula is C4H6.

3) CH2 CHCH2CH3 (1-butene); CH3CH CHCH3 (2-butene);

CH2CH(CH3)2(2-methylpropene).

Let the molecular weight be CXHY, then, that is, X:Y is 1 to 2, and the experimental formula CH2 can be deduced according to PV=NRT, and N=M M and M=density*volume:

m=rt*density p

Under standard conditions, the pressure and temperature can be known, and the molecular mass can be deduced, and it is very simple to go down.

The stone stood for two months, playing an element.

A and B can be converted into each other, B is generated in boiling water to C, C is oxidized in the air to D, D has the smell of rotten eggs.

Answer = = Eggs, Chickens......Needless to say, it's very old, but it's interesting......

The cathode is connected to the negative electrode, the reaction gets electrons, the valency of the element decreases, and the reaction should be generated by (SO4)2- (this is the most likely), because it is an acidic environment, the hydrogen atom participates in the reaction, after trimming, the first empty is as follows:

so4)2- +2e- +4h+= so2↑ +2h2o

The second void, looking at the Mn element alone, the valency increases by 2, and 1mol Mn loses 2mol electrons, then the theoretical yield of mnO2 is 1mol, which is converted into a mass of 87g

Manganese rises by 2 valence, so that one mole of manganese dioxide is generated, and the transfer of electrons is not 2 moles, and through 2 moles of electrons in the circuit, is not 1 mole of manganese dioxide generated, is not 87 grams.

Got it?

Hehe, because yin and yang have to be reconciled, there is no charge in the water, and if there is +, there must be - if you say cl-, oh-, no3- all of these three are with - to die hehe.

First of all, the wastewater is obviously alkaline, and it can be concluded that there is OH-, and if there is OH-, AG+, Fe3+ can be excluded, because the reaction will occur. So the only cations left are K+, and the anions may have Cl-, Oh-, and No3.

As for why NO3- is excluded, because now there are AG+, FE3+, and only NO3- can coexist with them.

Therefore, the wastewater in plant A is k+, cl-, oh-, and there are ag+, fe3+, no3-

Chloride ions, hydroxide ions, nitrate ions are all anions.

If it is chloride ions, hydroxide ions, nitrate ions, then all ions are negative, then water will be negative, which is impossible, because the positive and negative charges must be canceled out and neutral as a whole, so the answer can only be potassium ions, chloride ions, hydroxide ions.

The ions in a solution should be balanced, and hydroxide and chloride ions are both negative ions, so there must be a positive ion potassium.

The aqueous solution is electrically neutral, and your answer is that the charge cannot be conserved! Huh....

Nitrate ions are strongly oxidizing ions and are acidic ions. Moreover, it is impossible for the solution to contain only anions, it must be both anion and ion.

The charge is conserved, the solution is obviously neutral, and it is impossible to have only anions and no cations.

Because although the wastewater is alkaline, the solution is electrically neutral and cannot be all negative ions.

The number of electrons is the same as the number of protons, as shown in the periodic table, the number of electrons in sodium hydroxide is 11 + 8 + 1 = 20

The number of electrons of ammonia is 3 + 7 = 10, which is exactly two to one, that is, 5g of sodium hydroxide and how many grams of ammonia contain the same amount of substance, the amount of hydrogen spring banquet sodium oxide is 5 40 = 1 8, and the Huaiqi mass of ammonia is 17 * 1 8 = 17 8

5g of sodium hydroxide is moles, and each mole of sodium hydroxide has (11 + 8 + 1) na, so it is 5 grams of sodium hydroxide and has (7 + 1 + 1 + 1) na per bright mole of ammonia, so an electric void needs ammonia moles, which is grams.