Solving! Math problems for the first year of junior high school! Super easy!

It's quite simple, but unfortunately I can't see the title clearly.

Solution: Sell x pieces of beer A and beer B (5000-x) in the month

70%*35x+80%*35(5000-x)=150500 Solution: x=1500

5000-1500=3500 (pieces).

A: The distributor sells 1,500 pieces of A beer and 3,500 pieces of B beer.

If there is interference in the conditions, you can eliminate it yourself and you can calculate the answer.

By (5,000 pieces of beer A and B were sold in the month, and X pieces of beer were sold in the first grade.) It can be seen that the B beer is (5000-x) pieces, and because (70% of the total price of the beer sold at home in that month was donated to the disaster area, and then 80% of the total loan for the sale of B beer in that month was donated to the disaster area) [50x+35x(5000-x)] x 70%+ 5000-x) x 80%=150500 Then solve the equation and it's OK!!

Since x and y are inverse to each other, and a and b are reciprocal to each other, x+y=0 -y=x ab=1 so: (a+b)(x+y)-ab=-1

y x=1, so choose d

Select each other as the reciprocal, you can get ab=1, x, y are opposite to each other, you can get x+y=0, x y=-1, substitute the above values, get the original formula =0

d.Because they are inverse numbers to each other, x+y=0, x y=-1, and because they are reciprocal to each other, ab=1Bring in the formula to get zero.

A, nine points 12 - (Chunsen +3) rough sell = 9

B, 13 o'clock stool acre and a half 12-(

Wish. Thank you.

Memorize 5 words within 5 minutes for passing, more than has been positive, now there are 5 students recorded as follows: -3,0,+1,+2,-1

Question: How many words did they memorize?

Solution: From the condition "memorize 5 words within 5 minutes to pass, more than the one is positive" can be obtained if a student memorizes 5 words within 5 minutes The record is 0If you have more than 5 on your back, you will add it, otherwise you will subtract!

Therefore, the number of words memorized by the 5 students is as follows:

Student 1: 5-3 = 2 (pcs).

Student 2: 5+0=5 (pcs).

Student 3: 5+1=6 (pcs).

Student 4: 5+2=7 (pcs).

Student 5: 5-1=4 (pcs).

Answer: 5 students memorized 2, 5, 6, 7, and 4 respectively.

It's a calendar issue.

The holidays may be July, August, or January or February.

Case-by-case discussion: If it is July, the sum of dates is 84-7=77.

Then the middle day is the 11th. Probably: July.

If it's August, then the date sum is 84-8=76 and is not divisible by 7, no.

The same goes for January, not February.

So it is: July 14 home.

Because 84 minus the number of months is a multiple of 7.

So it can be deduced that the month is July.

Set number X to go home.

x+x-1+x-2+x-3+x-4+x-5+x-6=84-77x-21=77

x=14 so go home on July 14th.

1. Root number 5, root number 7

2、x<=0

I'm sorry, but I don't know how to call a root number.