How many kilowatt hours of electricity is lost in a month when a 1250kva transformer is lost

I have here a sample information of Shanghai Electric Co., Ltd. **** transformer factory for your reference: Model: SCL-1250 10 (KVA) no-load loss PO (KW):

Be. The load loss pk(kw) at 100 degrees is: The no-load current IO (%) is:.

No-load monthly iron loss (PO): days = load monthly loss (OK) If it is at 100 degrees: the no-load current is negligible.

Total:

It depends on the size of your load, no-load loss and load loss are very different, I have 1250kva transformer data at hand, no-load loss is, 30 days per month loss: degree, 50% rated load loss is, monthly loss: degree.

Don't you understand my algorithm? You can also calculate according to your own transformer information, as long as you know the no-load and load loss.

Don't you just want to know about the loss? The no-load loss and load loss of 1250kVA transformer can not be calculated? Khan!!

Summary. How much electricity does a 1250kva transformer lose in a month?

Hello dear, 1250kv transformer consumes electricity for one hour.

The no-load loss of 1250kva transformer: watts, the loss per day is: degrees), this is the cold rolling data; watts, the daily loss is: degrees), this is the hot rolling data.

No-load monthly iron loss (PO): days = load monthly loss (OK) If it is at 100 degrees: the no-load current is negligible. Total:

Then the hourly power consumption is the kilowatt-hour.

How much electricity does a 1250kva transformer lose in a month?

How much electricity does a 1250kva transformer lose in a month? Hello dear, 1250kv transformer consumes 1250kva transformer for one hour no-load loss: watts, and the daily loss is:

degrees), which is the cold-rolled data; watts, the daily loss is: degrees), this is the hot rolling data. No-load monthly iron loss (PO):

Day = load monthly loss (OK) If it is at 100 degrees: the day no-load current is negligible. Total:

If my answer is helpful to you, please give a thumbs up (in the lower left corner), I look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress. Finally, I wish you good health and a good mood!

18000 degrees.

Large transformers are typically 95 to 98 percent efficient. Your 1,250,000 volt, ampere transformer belongs to a large transformer, so its loss rate should be about 2%. Then 1250 multiplied by 24 multiplied by 30 multiplied by 0.02 equals 18000 degrees.

If the transformer configuration is used reasonably, the loss is about 15%.

24-hour operation.

1250*24*30*kWh.

The specifications of the transformers are the same, the models are different, and the losses vary greatly.

The loss of the transformer includes iron loss and copper loss.

The former is fixed on a monthly basis, but different manufacturers and designs have different fixed values.

The latter is varied and related to the electricity load, with large load and large loss, so your problem can only be analyzed qualitatively, and cannot tell you a data quantitatively.

You just want to know what has changed? Do you know the no-load loss and load loss of 1250kva transformer? Perspire!!!

Summary. Dear, I'm glad to answer your <>

Answer: A 1250kva transformer for one month, the no-load loss is, the loss is 30 days per month: degrees, the loss at 50% of the rated load is, and the monthly loss: degrees.

How much electricity does a 1250kva transformer lose in a month?

Dear, I'm glad to answer your eyes and guess the omission [Micro Zhaoqing laughs] Answer: A 1250kva transformer is rotten for a month, the no-load loss is, the loss is 30 days per month: degree, the loss at 50% of the rated load is, the monthly loss: degree.

The no-load loss of 1250kva transformer: watts, the loss per day is: degrees), this is the cold rolling data; watts, the daily loss is:

degrees). The higher the average load coefficient of the no-load loss load curve of the transformer, the smaller the loss ratio of the transformer should be selected in order to achieve the smaller the loss of electric energy; The lower the average load factor of the load curve, the smaller the power loss, and the larger the loss ratio, the transformer with the larger the loss ratio. Transformer 1, transformer loss calculation formula (1) active loss:

p p0 kt 2pk---1) (2) reactive power loss: δq q0 kt 2qk---2) (3) comprehensive power loss: δpz δp kqδq---3) q0 i0 spinal focus sn, qk uk sn where:

Q0 - no-load reactive power loss (kvar) P0 - no-load loss (kw) pk - fixed load loss (kw) sn - the first fixed capacity of the frontal plexus of the transformer (kva) i0 - the percentage of no-load current of the transformer.

Dear, hello, I am happy to solve the problem for you, 250kva transformer, if the iron core uses the current good quality cold-rolled grain oriented silicon steel sheet material, then its iron consumption is generally about 590 watts, then it consumes electricity fiber fuel per hour, a month is calculated as 30 days, so such a large capacity transformer consumes 425 kWh of electricity in a month. Therefore, the transformer iron consumption consumption is a lot. The no-load loss of 250kva is 720w, and it will be multiplied by 24 * 30 1000 = 518 degrees in a month.

Hello, in the 1250kva transformer data, the no-load loss is, 30 days per month: degree, 50% of the amount of the load is lost, monthly loss: degree.

Summary. How much electricity does a 1250kva transformer lose in a month? Hello dear, <> we have a 1250kva transformer here, the incoming line is 10kv, the outgoing line is 400v, the electricity consumption is about 10-150,000 kWh a month, the difference between the degree of the high-voltage meter and the low-voltage side meter is about 2000 degrees, is this loss large, how to calculate the transformer loss, thank you.

2000 100000 = about 2%. The loss is not high. But according to what you said, the monthly electricity consumption is about 10-150,000 kWh.

My answer is helpful to you, please give a like (rate in the lower left corner), look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress. Finally, I wish you good health and a good mood!

How much electricity does a 1250kva transformer lose in a month?

How much electricity does a 1250kva transformer lose in a month? Hello dear, <> we have a 1250kva variable omen trace voltage destroyer here, the incoming line is 10kv, the outgoing line is 400v, the electricity consumption is about 10-150,000 degrees a month, the difference between the degree of the high-voltage meter and the low-voltage side meter is about 2000 degrees, is this a big loss, how to calculate the transformer loss, thank you. 2000 100000 = about 2%.

The loss is not high. But according to what you said, the monthly electricity consumption is about 10-150,000 kWh. The load is relatively small.

The rated current of the transformer is 1250000 400 pieces, and the number is 3 = 1800A. Hope it helps. My answer is helpful to you, please give a like (rate in the lower left corner), look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress.

Finally, I wish you good health and a good mood!

There is no low-voltage electricity measurement here, and the high-voltage electricity measurement is about 100,000 degrees, so what is the loss this month.

Hello dear, <>

Between high-voltage metering and low-voltage conglomerate, the main problem is the loss of the transformer, which is affected by factors such as transformer model and electricity load at 2% 5 Therefore, try to dismantle the meter on both sides to solve the difficulty of loss analysis, I hope that the brother shirt can help you. My answer is helpful to you, please give a like (rate in the lower left corner), look forward to your like, your efforts are very important to me, and your support is also the motivation for my progress. Finally, I wish you good health and a good mood!