A ship sailed upriver from Bridge No. 1 to Bridge No. 2

The formula for the sum and difference problem.

Sum difference) 2 large numbers.

and difference) 2 decimals.

And times the problem and (multiples of 1) decimals.

Decimals, multiples, and large numbers.

or and decimal large numbers).

Difference multiplier problem Difference (multiple of 1) decimals.

Decimals, multiples, and large numbers.

or decimal difference for large numbers).

Tree planting problem 1 The tree planting problem on non-closed routes can be divided into the following three situations:

If trees are to be planted at both ends of the unenclosed line, then:

Number of plants Number of stages 1 Full length Plant spacing 1

Full length plant spacing (number of plants 1).

Plant spacing: Full length (number of plants: 1).

If trees are to be planted at one end of the unenclosed line and not at the other end, then:

Number of plants, number of stages, full length, plant spacing.

Full length, plant spacing, number of plants.

Plant spacing, full length, number of plants.

If trees are not planted at both ends of the unenclosed line, then:

Number of plants Number of stages 1 Full length Plant spacing 1

Full length plant spacing (number of plants 1).

Plant spacing: Full length (number of plants: 1).

2 The relationship between the number of tree planting problems on closed lines is as follows.

Number of plants, number of stages, full length, plant spacing.

Full length, plant spacing, number of plants.

Plant spacing, full length, number of plants.

Profit and loss problem Profit and loss) The difference between the two distributions The number of shares participating in the distribution is large and the number of shares participating in the distribution is large and small) The difference between the two distributions The number of shares participating in the distribution is a small loss) The difference between the two distributions The number of shares participating in the distribution meet the problem of the encounter distance Speed and the time of the encounter.

Encounter time, encounter distance, speed and.

Speed and distance traveled to meet time.

Catch up and the problem, catch up and the distance, the speed difference, the catch up time.

Chase time, chase distance, speed difference.

Speed difference, chase distance, chase time.

Flowing water problem Downstream velocity Hydrostatic velocity Water velocity.

Countercurrent velocity Hydrostatic velocity Water velocity velocity.

Hydrostatic velocity (downstream velocity countercurrent velocity) 2

Water velocity (downstream velocity counter-current velocity) 2

Concentration issues Weight of solute Weight of solvent Weight of solution Weight of solute Weight of solution 100% concentration.

The weight of the solution The concentration of the solute is the weight of the solute.

The weight of the solute concentration of the solution.

Profit vs. discount issues.

Profit, Sell Price, Cost.

Profit Margin Profit Cost 100% (Sell Price Cost 1) 100%.

With the water as the reference system, it takes 20 minutes for the boat to leave the log, and it takes 20 minutes to return, which means that it takes 40 minutes to catch up with the log. Then the flow velocity of the water sales Xiaozhou v=2000 40=50m min

That is, the speed of the water flow is 50 meters per minute of loss.

Judging by what you wrote, the logs fell from the ship, not from the bridge. So it should be that the boat has dropped a log from the boat when it sailed to the No. 2 bridge, but after 20 minutes, when the boat sailed to point A, it was found that the log had fallen at the No. 2 bridge (as for why it was found that it fell at the No. 2 bridge and not elsewhere, there is no point in arguing, because the title has already said that a log was found to be lost at the No. 2 bridge), so the link calculation method provided by the landlord is correct. When the boat sailed from Bridge No. 2 to point A, the log had fallen off and drifted with the current, but when the boat sailed to point A, the people on board found it and chased the log back, so the time to calculate the log drifting naturally added the time for the ship to sail from Bridge No. 2 to point A.

The link you gave is the right solution! Don't be disappointed, you use your brain like this, it shows that you love to think, so you will progress faster!

The point is that the wood was on the ship, and it fell at the position of the 2nd bridge, and it was found that the wood had been dropped, and the wood had been floating for 20 minutes.

The question says that the wood fell on the 2nd bridge, and after the wood fell, the wood floated backwards, and the boat walked forward, and it was found 20 minutes later. I just started chasing, so I have to add those 20 minutes. i.e. the starting point of the boat and the wood are on the 2 bridge.

The text says that "after another 20 minutes of sailing to point A, I found that the wood on the 2nd bridge had fallen", which only refers to the location where the boat fell off the wood, and the time that did not point out is the current. Don't understand the bridge span, the wood falling from the bridge (that's right, your equation is right).

The number in the link is incorrect, y=5 6=m-seconds, it is correct.

Your solution is not unique, but it is all around the meter second.

The formula for the sum and difference problem.

Sum difference) 2 large numbers.

and difference) 2 decimals.

and times the problem. and (multiples of 1) decimals.

Decimals, multiples, and large numbers.

or and decimal large numbers).

The problem of difference times. Difference (multiple of 1) decimal place.

Decimals, multiples, and large numbers.

or decimal difference for large numbers).

Tree planting issues. 1 The problem of tree planting on non-closed routes can be divided into the following three situations:

If trees are to be planted at both ends of the unenclosed line, then:

Number of plants Number of stages 1 Full length Plant spacing 1

Full length plant spacing (number of plants 1).

Plant spacing: Full length (number of plants: 1).

If trees are to be planted at one end of the unenclosed line and not at the other end, then:

Number of plants, number of stages, full length, plant spacing.

Full length, plant spacing, number of plants.

Plant spacing, full length, number of plants.

If trees are not planted at both ends of the unenclosed line, then:

Number of plants Number of stages 1 Full length Plant spacing 1

Full length plant spacing (number of plants 1).

Plant spacing: Full length (number of plants: 1).

2 The relationship between the number of tree planting problems on closed lines is as follows.

Number of plants, number of stages, full length, plant spacing.

Full length, plant spacing, number of plants.

Plant spacing, full length, number of plants.

Profit and loss issues. Profit and loss) The difference between the two distributions The number of shares participating in the distribution (large profit and small profit) The difference between the two distributions The number of shares participating in the distribution (large loss and small loss) The difference between the two distributions The number of shares participating in the distribution meets the problem.

The distance traveled by the encounter speed and the time of the encounter.

Encounter time, encounter distance, speed and.

Speed and distance traveled to meet time.

Catch up on the problem. Chase distance, speed difference, chase time.

Chase time, chase distance, speed difference.

Speed difference, chase distance, chase time.

Running water problems. Downstream velocity Hydrostatic velocity Water velocity velocity.

Countercurrent velocity Hydrostatic velocity Water velocity velocity.

Hydrostatic velocity (downstream velocity countercurrent velocity) 2

Water velocity (downstream velocity counter-current velocity) 2

Concentration issues. The weight of the solute The weight of the solvent The weight of the solution.

The weight of the solute is 100% concentrated by the weight of the solution.

The weight of the solution The concentration of the solute is the weight of the solute.

The weight of the solute concentration of the solution.

Profit vs. discount issues.

Profit, Sell Price, Cost.

Let the speed of the boat be x and the current be y, 20 minutes = 1200 seconds (x-y) is the speed of sailing against the current (x+y) is the speed of sailing along the water, i.e., 2000 y = 2000 + 1200 (x-y) x+y 2000 y is the time when the wood floats;

1200 (x-y) is the distance from 2 bridges in 20 minutes to point A;

2000+1200 (x-y) is the total distance from bridge 1 to bridge 2 to point a;

2000+1200 (x-y) (x+y) is the time to chase wood, the distance divided by the speed of sailing.