If you want some 6th grade Olympiad exercises, it s best to have all Olympiad types.

Updated on educate 2024-03-27
6 answers
  1. Anonymous users2024-02-07

    1.Count the arcane 2Proportional Question 3

    Cylinders and cones 4Fraction application question 5Engineering Problem 6

    Logical Reasoning 7Cattle grazing problem 8Itinerary question 9

    Drawer principle 10Calculation of the area of irregular shapes 11Equation Application Problem 12

    Running Water Boating Problem 13Prime factor 14Divisibility of numbers 15

    Indefinite equation 16Clock Problem 17Principle of Repulsion 18

    Recursive method 19Backwards 20Principles of multiplication 20

    Principle of Addition 21Define a new operation22Application of equal difference series.

  2. Anonymous users2024-02-06

    Solution: According to the question, it takes 30 minutes to walk normally.

    It takes 45 minutes to walk 10 meters less per minute.

    If you walk 10 meters less per minute, you will walk less for 30 minutes.

    10 30 = 300 (meters).

    Those who walk less need to walk back in another 15 minutes.

    Then 300 (45-30) = 20 (meters).

    The reduced speed is 20 meters.

    The distance is 20 45=900 (meters).

    A: Mingming's house is 900 meters away from the school.

  3. Anonymous users2024-02-05

    7:00 to 7:30 for 30 minutes.

    6:50 to 7:35 for 45 minutes.

    Let us know that we have walked x meters per minute, and we can solve the equation 30x=45 (x-10) according to the problem: x=30 meters.

    30*30=900 (m).

  4. Anonymous users2024-02-04

    Go to the bookstore and buy a copy of the 6th grade math Olympiad.

  5. Anonymous users2024-02-03

    Each item under observation is (n+1) 3-n, and you can try it all at once!

    Apply the formula for summing continuous cubes and equal difference sequences.

    1x2+2x3+3x4+4x5+..2002x2003

    A and B respectively set off from AB and traveled in the same direction, their speed ratio was 3:2 when they started, after the encounter, A's speed increased by 1 5, B's speed increased by 2 5, and when A arrived at B, B was still 26km away from A. How many kilometers are the two places apart?

    Let AB and the two places be separated by x kilometers.

    2/(3+2)x]/[3×(1+1/5)]=[3/(3+2)x-26]/[2×(1+2/5)]

    x/9=3x/14-130/14

    13x/126=130/14x=90

    A, B, and C went shopping together, and 1 2 of A's money was equal to 1 3 of B's money, and 3 4 of B's money was equal to 3 5 of C's spending, and C spent 98 yuan more than A, and asked them how much money they had spent.

    490 yuan. A and B run a 100-meter run (assuming their speed remains the same), and when A runs 75 meters, B runs 60 meters. So, how many meters did B run when A reached the finish line?

    80 meters. 1/6 + 1/12 + 1/24 + 1/48 + 1/96 + 1/192

    The number of factor 5 determines the number of 0 at the end.

    2008 5 = 401 (rounded).

    2008 25=80 (rounded).

    2008 125 = 16 (rounded).

    2008 625 = 3 (rounded).

    401 + 80 + 16 + 3 = 500.

    1*2*3*4*5*6*……There were 500 zeros at the end of 2008

    If a car drives from A to B, if the speed is increased by 20%, it can arrive 1 hour earlier than the original time, and if it travels 120 kilometers at the original speed and then increases the speed by 25%, it can arrive 40 minutes in advance.

    40 minutes = 2 3 hours.

    Original time: 1 [1-1 (1+20%)] = 6 hours.

    The original speed [120-120 (1+25%)] 6-2 3-6 (1+25%)] = 24 8 15 = 45 km/h.

    A and B are 45 6 = 270 kilometers apart.

    The average score of the class in the final test of mathematics for class four (1) is 92 points, the number of boys who took the test is 18, the average score is 89 points, and the average score of girls is 94 points

    92-89) 18 (94-92) = 27 people.

    Chen Ming traveled 38 kilometers a day on flat roads and 23 kilometers a day on mountain roads, a total of 450 kilometers in 15 days. Asked how many kilometers of mountain roads he had walked during this time.

    38*15-450) (38-23)*23=8*23=184km.

  6. Anonymous users2024-02-02

    A round acacia is resistant to a cylinder, and Hongming changes the shielded volume of a semi-cylinder.

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The fun Olympiad questions in the Olympiad should be for some grades, and the fun questions for the third grade will not necessarily be done for the 6th grade students! But I'll still share with you a kind of problem, the pirate money problem, the specific details, you can search for it in the evening!!