How should this question be answered?????? I urgently need help from a master!!!!!!!!!!!!!!!!!!!!! 1

Hello! First of all, we should know that the start point A corresponds to t=0, and the end point B corresponds to t= 2x't=2 root number 7sint*cost

y't=-6cost*sint

So. x't)^2+(y't)^2=7(sin2t)^2+9(sin2t)^2=16(sin2t)^2

So the root number [(x't)^2+(y't)^2]=4|sin2t|Because t goes from 0 to 2

So 2t goes from 0 to , and sin2t > 0

So the root number [(x't)^2+(y't)^2]=4|sin2t|=4sin2t

From 0 to 2, we can take the original function of 4sin2t is -2cos2t, so take in the starting point t=0 and the end point 2, and get it.

The final integral value = -2cos +2cos0=2+2=4 I hope you understand o( o ha!

I wish you a happy study life o( o ha!

The sum of the three numbers of the same straight line is 19, such as 5+6+8=19, 10+6+3=19, and f=19-4-6=9, 乚=19-11-6=2, g=19-1-6=12.

Arrange the numbers in order from smallest to largest and write them in one line;

The number 6 in the middle is filled in the circle in the center; The rest are grouped in groups from the middle to the sides from the middle to the sides, and are filled in a line;

The sum of each straight line passing 6 is 18

Solution: As shown in the figure.

The five sides of the pentagon are all equal in length.

b=∠e ,∠c=∠d

And 6 a = 360 ° (the position of the central Xun ant is all composed of angle a) Hall Changming a = 60 °

and a+2 e=360 ° at any node in the second circle in the middle)2 e=300°

e=150°

Solution: According to the blind call diagram.

The five edges of the five holes are all equal in length.

b=∠e ,∠c=∠d

So 6 a = 360 ° a = 60 °

Grinding Kai a+2 e=360° 2 e=300°E=150°

The arc length of the 4 corners is to make up a circle 2 r 2*

4 side length 2dm *4=8dm

2 to the 43rd power Centimeter = km 385,000 km.

The thickness of the paper has been doubled each time, and 43 times is a 43rd power multiple of 2. The height is centimeters times 2 to the 43rd power.