Which master can help solve this math problem, try to be clear, I m only in the fifth grade.

Solution: If there are a total of x pencils, then A 1 7x, B 1 4x, C 2 * (1 4x-1 7x).

x-1 7x-1 4x-2*(1 4x-1 7x)=11 (subtract A, B, and C from the total amount to equal the remainder).

x = 28 A: 1 7x = 4, B : 1 4x = 7, C : 2 * (1 4x-1 7x) = 17

Answer: 4 A, 7 B, 17 C.

Hope, thank you.

There are x pencils in this batch.

So A has x 7.

B has x 4.

C has 2 (x 4 x 7).

So x 7 + x 4 + 2 (x 4 x 7) + 11 = x to get x = 28

So A gets 4 pencils.

(1 4-1 7)*2 of the total allocated to C

1 7 1 4 (1 4-1 7)*2 3 4-1 7 17 28 of the total

The rest occupy: 1 17 28 11 28

There are 11 left, so how many are there? A, B, C?! ～

First divide 1/7 and 1/4 into 4/28 and 7/28, and their difference is 3/28, then C will be 6/28. The sum of the three is: 17/28, and 11/28 represents the remaining 11 pencils, so that 1/28 represents 1 pencil, and A gets 4 pencils.

If there are x pencils, then A is given 1 7 x and B 1 4 x is divided, so C has 2x (1 4 x-1 7 x), so x - 1 7 x - 1 4 x - 2x (1 4 x - 1 7 x) = 11, and the equation is solved, x = 28

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Quite simply, because there are 36 volleyballs, and if you look at the total number of volleyballs as a unit of "one", then the volleyball borrows one-sixth.

With 1/36 x 6, volleyball borrows six.

In the same way, 1-5/9 = 4/9, 36*4/9, football borrows 16 in the same way, 1-3/4 = quarter, 36*4/1, basketball borrows 9 So, football borrows the most.

Soccer subtracts the remaining points from 1 to get 1 6, 4 9, 1 4. The largest of them is 4 9

36*5 6 36*5 9 36*3 4 Calculate that the remaining ones borrow less, and the remaining ones borrow more.

The decomposition of the material is too mathical.

So one of the four people must be 7 years old and the other person 5 or 10 years old, so the guess may be 4 5 6 7 or 5 6 7 8 or 7 8 9 10, and then the test is 5040 = 7 * 8 * 9 * 10

In the cousin is older than the cousin, the smile is bigger than the naughty, and the smile is the oldest, so the age of the four people from the oldest to the youngest may be.

Laughing naughty cousin cousin.

Laughing cousin naughty cousin.

Laughing cousin cousin naughty.

Then you can substitute them in turn.

5040=2*2*2*2*3*3*5*7

Note: This is often the case in the fifth grade, and the method is to decompose prime factors.

Suppose all four are six years old, the product is 1026, so the oldest cannot be less than six years old, and the product of four tens is 10000, so the youngest is under 10 years old.

The age is 7, 8, 9, 10

The sum of two numbers ab: 24 2=48

The sum of two numbers BC: 30 2=60

The sum of two numbers of ac: 42 2 = 84

The sum of the three numbers of abc: (48 + 60 + 84) 2 = 96 The average of the three numbers of abc is: 96 3 = 32

Solution: x=18

x=431+a=46

Solution: a=46-31

a=15 solution: x=

x = x divided by 9 = 13

Solution: x=13*9

x=117 solution :y=

y=y divide.

Solution: y=1*

y=Don't listen to the landlord's nonsense I'm a fifth-grade student, and the first step in solving an equation is to write the word "solution", and he got the third question wrong.

When 4 meters 4 roots, 3 meters 2 roots, when 4 meters 1 root, 3 meters 6 roots.

Idea: 3 is an odd number, 4 is an even number, and then 22 is also an even number, so the root number of 3 meters must be an even number, so when there are 0, 2, 4, and 6 in 3 meters, only 4 meters have 1 or 4 in line with the topic.