About Senior 3 Biology Review Questions Urgently

There is no biology question, only whether you know. If you have a plan to read the biology textbook or the summary of knowledge points, you will definitely see things that you have never known, and there are several model block diagrams that must be memorized (such as photosynthesis, respiration, various regulatory mechanisms of the human body, gene separation and recombination...).It will work soon, but the key is to have the right attitude, brother!

Summarize the knowledge points, in general, if you want to do a good job in biology, you should memorize and understand the key words, written phrases and distinguish between small knowledge points, read the book first when reviewing, and then do the test paper, it should be no problem with biology! A score of 90 is enough for a score of 70!

Books are the most important, I never look for questions to do outside of class, I only read books, read every corner of the book bar, take a book and make summary notes next to it, which is very effective!! See for yourself!!

I bought a biology paper from the previous year, which is a concentration of biology in the college entrance examination from all over the world, about a dozen articles, I will do one or two copies a day, and I feel good after doing it, but you have to look at the type of questions to be tested in the college entrance examination in your province and city, those teachers have not asked for it, and the knowledge in the book should be treated separately, for example, genetic engineering should be based on book memorization, and genetics must do more questions, and make some thematic breakthroughs, which will be useful, and then it is necessary to distinguish some concepts, such as populations, Community: These are all points that are prone to error.

Summary. During insulin synthesis and secretion, the area of the endoplasmic reticulum decreases because the precursor proteins that synthesize insulin are present in the lumen of the endoplasmic reticulum, while the mature form of insulin needs to be transported to other organs such as the Golgi complex. This process requires a large number of endoplasmic reticulum involvement, including synthesis, modification, folding, and transport, among others.

However, at the peak of insulin production, the endoplasmic reticulum needs to take on more of the task of synthesizing insulin, resulting in a shrinking surface area of the endoplasmic reticulum. In addition, the secretion of insulin also involves other organs in the pancreatic islet cells, such as insulin granules and insulin secretion granules, etc. The membrane structure of these organs is similar to that of the endoplasmic reticulum, and they also play an important role in insulin synthesis and secretion, further increasing the pressure on the surface area of the endoplasmic reticulum.

Therefore, the continuous reduction of the surface area of the endoplasmic reticulum is a normal physiological phenomenon during insulin synthesis and secretion.

During insulin synthesis and secretion, the area of the endoplasmic reticulum decreases (please explain why, thank you).

During insulin synthesis and secretion, the area of the endoplasmic reticulum decreases because the precursor proteins that synthesize insulin are present in the lumen of the endoplasmic reticulum, and the mature form of insulin needs to be transported to other organs such as the Golgi complex. This process requires a large number of endoplasmic reticulum involvement, including synthesis, modification, folding, and transport, among others. However, at the peak of insulin production, the endoplasmic reticulum needs to take on more of the task of synthesizing insulin, resulting in a shrinking surface area of the endoplasmic reticulum.

In addition, the secretion of insulin also involves other organs in the islet cells of pancreatic tan, such as insulin granules and insulin-secreting granules. The membrane structure of these organs is similar to that of the endoplasmic reticulum, and they also play an important role in insulin synthesis and secretion, further increasing the pressure on the surface curvature area of the endoplasmic reticulum. Therefore, the continuous reduction of the surface area of the endoplasmic reticulum is a normal physiological phenomenon during insulin synthesis and secretion.

Summary. Pro, 1Solar Energy 2The growth of algae can reduce the dissolved oxygen content of the water, which can affect the growth of submerged plants. 3.Decrease by 4Food 5 Growth 6 Genetic mutations.

Hello, you have a biology teacher you know.

Hello dear. The knowledge points of biology in the third year of high school are as follows: 1. Cell membrane (1) Composition:

It is mainly phospholipid bilayer (basic backbone) and proteins, with a small amount of sugars. (The membrane composition of other membrane-bearing cell structures is similar to this) (2) Structural characteristics: It has a certain fluidity.

You can ask specific questions so I can answer them for you.

Pro, 1Solar Energy 2The growth of algae can reduce the dissolved oxygen content of the water, which can affect the growth of submerged plants. 3.Decrease by 4Food 5 Growth 6 Genetic mutations.

The third question is inbreeding.

Parent, inbreeding is also available.

Teacher, are you a student or a teacher, are you teaching biology, are you teaching biology in Shanghai?

Dear, I'm a teacher, I don't teach biology in Shanghai, I'm in Hunan.

Is it to teach the second year of high school, is it teaching in school, or is it a make-up institution.

Dear, have been taught, institutions.

This question is to ask you which is the prokaryotic ......

Staphylococcus aureus.

Because introns are only found in eukaryotes.

Option c only has introns in the coding region of eukaryotes, which prokaryotes do not have, whereas Staphylococcus aureus belongs to bacteria and is prokaryotes, so there are no introns.

A, the transport RNA (tRNA) that carries a certain amino acid is fixed one or several fixed, so the tRNA carrying the same amino acid in all cells is the same one or several. Therefore, option A is incorrect.

b. The change of amino acid series leads to the change of intermolecular forces, resulting in the change of the spatial structure of the protein.

C, messenger RNA (mRNA) is transcribed by DNA, since it is a patient, there must be a change in the DNA sequence (gene mutation), according to the law of base pairing, the mRNA it transcribed must have changed, that is, it is different from ordinary people.

d, microscopic observation of red blood cells in the shape of a sickle (normal red blood cells are oblate); DNA molecular hybridization technology, this option can be carefully considered, if it is DNA and DNA hybridization, the patient's DNA and their own cell DNA hybridization is meaningless, it must be heterozygous; If you cross the DNA of other normal people, everyone's DNA is different, so in the case of hybridized DNA strands, there will be heterozygous parts and protruding parts (non-heterozygous), and the patient has only one base change, so it is not visible at all. If you hybridize with normal people, we all know that after DNA transcribs mRNA, mRNA will cut off the part of intron transcription to form mature mRNA, so such a base series and DNA hybridization must have both heterozygous parts and protruding parts. So strictly speaking, items a and d are incorrect. Thank you.

Choose A, because the tRNA is the transfer RNA, and the mutation of the gene has nothing to do with the anticodon on the RNA of the transformer brother Douyun, so it will not be different from the one who is envying ordinary people.

tRNA is transporter RNA, and every cell transports the same amino acid in the same RNA, and there is nothing to say about the rest of the options.

I choose A, the gene mutation has nothing to do with the glutamate codon, so A is wrong.

This seems to be the college entrance examination question C in a certain region in 09

The chloroplasts of C3 plants are only found in mesophyll cells, there are no chloroplasts in vascular sheath cells, and the process of photosynthesis can only be carried out in mesophyll cells, not in vascular sheath cells: options A and D are the processes of the photosynthesis photoreaction stage, and B is the photosynthesis dark reaction process.

Cellular respiration can be carried out in both mesophyll cells and vascular sheath cells: ATP and reducing hydrogen are produced (ATP is produced in the three stages of aerobic respiration in cellular respiration, and reduced hydrogen is produced in the first two stages; Anaerobic respiration stage 1 also has ATP and reducing hydrogen production).

There should be no doubt about this.

Ca is wrong, because the water light interprets oxygen release, a small fraction of chlorophyll A takes the hydrogen from the water, and there are no chloroplasts in the vascular sheath cells, so A is wrong.

bFalse: There are no chloroplasts in the vascular sheath, so it cannot carry out light and action, and cannot be fixed to form C3.

D False is the same as B.

You have to distinguish between a C3 plant and a C4 plant.

Answer: Choose B: This question mainly tests whether you are familiar with photosynthesis.

CO2 fixation involves both light and dark reactions.

Chlorophyll does not need to be involved in the absorption of light energy in the light reaction, and the corresponding pigments absorb light energy of different wavelengths.

CO2 fixation requires entry into the tricarboxylic acid cycle. Pyruvate carboxylase, phosphoenolpyruvate carboxylated kinase, phosphoenolpyruvate carboxylase, malate and other involved are required.

C3 (Calvin) cycle, under the action of ATP and enzymes, 6 CO2s can be synthesized into one glucose through six cycles.

ATP synthesis requires at least ATP synthase.

The fixation of CO2 includes C3 reduction and ATP formation, and joint memory is much simpler.

b Light energy is absorbed by the special state chlorophyll a.

b Absorbed light energy is converted by electron transport without the need for enzymes.

b The rest can refer to the process of photosynthesis in plants, which clearly states that enzymes are required.

b, because everything else is needed, and there is it in the book.

The main body of the stem is the gene and the carrier, and the key is the combination of the requirements are needed (i.e., necessary).

2 plasmids with resistance genes. Resistance genes are useful for screening recombinant plasmids (depending on the type of plasmid selected, the digestion site, and the gene of interest). But it doesn't have to be.

The success of the recombination can also be determined by the expression product of the gene of interest, which is a screening. Moreover, this is not the point of whether or not the reorganization (integration) can be smoothly achieved. Therefore, it is not chosen.

A brief description of the other options is attached

1 Same restriction enzyme. Ensure the same digestion site (same sticky end);

3 RNA polymerase. Enzymes required for DNA transcription into RNA.

4 Gene of interest. Purpose of the reorganization.

5 DNA ligase. Pair the same sticky ends and link the c-backbone.

6 4 deoxynucleotides. It is necessary for the synthesis of DNA and RNA.

7 atp。Both the digestion and ligation processes require energy.

Choose D1The same restriction enzyme is guaranteed to have the same cleavage site4Gene of interest.

The ligase connects the gene of interest to the carrier.

Provides energy.

Forehead? There is a problem with the options, is the question guaranteed to be correct?

1 Guaranteed to have the same sticky ends.

2 Easy to screen.

3 Genes are DNA

4 Of course.

5 Link the gene of interest to the vector.

6 It's not copying, why do you need raw materials?

7 This is not macromolecular synthesis and does not require ATP

I guess it's 1245.

1 Guaranteed to have the same sticky ends.

2 Facilitate subsequent screening.

4 Required for the gene of interest.

5 Link the gene of interest to the vector.