Can anyone help me do a few questions, add an additional 50 points, speak countably, urgently

∠qed=40

then fed=140

EG is the bisector.

So deg=70

ab//cd

So egf=70

Launch egb = 110 degrees.

1.After the price increase of the four schemes, the ** are x1, x2, x3, x4x1 = 1000 (1 + 10) 1-10 ) = 990 yuan.

x2=1000 (1-10) 1+10 )=990 yuan.

x3=1000 (1+25) 1-25 )= yuan.

x4=1000 (1-20) 1+20 )=960 yuan.

So the third type has the lowest selling price.

2. 1x2=1/3x(1x2x3-0x1x2）2x3=1/3x(2x3x4-1x2x3）3x4=1/3x(3x4x5-2x3x4)

It's definitely not 15 minutes, so it's 30 minutes, for example, the first child and the second child played for 15 minutes, even if the third child played with himself for 15 minutes, it was only a total of 30 minutes, not enough for 45 minutes, so it could only be 30 minutes. That is, the first and second played for fifteen minutes, and the third played fifteen minutes each with the first and second, respectively, for exactly 45 minutes.

30 minutes.

Since it is two people playing together, the total time should be multiplied by 2 and then divided by 3.

The 45 minutes are divided into three parts on average, each of which is 15 minutes, that is, each person has a 15-minute break in the 45 minutes, and the ball is played for 30 minutes.

The answer is 30 minutes.

30 minutes, let's say two people play, both of them can play for 45 minutes, and after adding one person, each person plays 15 minutes less, to the third person, and the result is 30 minutes for each person.

13 (2) Team A y=x*60 6=10x Team B y=(x-2)*(50-30) (6-2) +30=5x+20

1) When team B dug to 30m, it took 2 hours, A=10*2=20m30-20=10Fill in the blanks 2 10

3）10x=5x+20 x=4