Why is the mass of a photon 0 and why is the mass of a photon

Einstein's special theory of relativity.

It shows that objects without rest mass move at the speed of light, and they can only move at the speed of light. Since photons always move at the speed of light and never get stationary, the rest mass of the photon must be 0. It is impossible for an object with a resting mass to move at the speed of light because the mass of motion of the object increases with velocity.

If a photon has a mass at rest, even if it is a very small mass, it will have different speeds depending on the difference in wavelength and frequency, and the speed of light in a vacuum will be different, c, which is the speed of light constant.

It doesn't exist. However, photons are elementary particles.

The physics community has confirmed the wave-particle duality of elementary particles, including photons.

A particle is a substance, and in both a physical and philosophical sense, it must contain both mass and energy, no matter how small its mass is.

The photon is massive, m=h c;

There is no rest mass, i.e. the rest mass is 0;

In fact, it is also very easy to understand, light is electromagnetic waves, it is the vibration of space, if the light is still, it will stop vibrating, and the light will disappear, how to talk about quality.

Light actually travels in the form of a field, such as an electromagnetic field, and the speed of propagation is also the speed of light, which can be understood as the establishment of the field at the speed level of "speed of light".

However, in the process of studying light propagation, it is found that some phenomena can be explained by the characteristics of mechanical wave propagation, while some phenomena can be explained more clearly by introducing the way of "particle" motion, so light is regarded as having both the characteristics of wave (light wave) propagation and particle (photon) motion.

However, light propagation has a certain energy, and even the "light pressure" generated when the light hits the surface of the object can be measured, when the light exists, that is, when the photon exists, according to the nature of the particle, its kinetic energy should be related to its speed and mass, so as a "photon", it can be regarded as having a certain mass; But when the speed of light is zero, the light no longer exists, and there is no "photon", that is, the zero-velocity photon does not exist, and there is no quality problem of the zero-velocity photon.

Personal understanding, please correct.

Let me share my views on this issue. The static mass of the photon is zero, which is defined in the theory of relativity, on the one hand, for mathematical self-consistency, but also for the process of derivation.

According to the description of the theory of relativity, a photon has no rest mass since it cannot be stationary, so the photon only has relativistic mass.

From the perspective of waves, a photon has two possible polarization states and three orthogonal wave vector components, which determine its wavelength and propagation direction. From the point of view of the particle photonic crystal junction, the photon has zero rest mass, zero electric charge, and an infinite half-life rock. The photon is a canonical boson with a spin of 1, so the lepton, baryon, and singular numbers are all coarse elimination zeros.

The rest mass of a photon is strictly zero, which is essentially equivalent to Coulomb's law, which is strictly inversely proportional to the square of the distance, and if the rest mass of the photon is not zero, then Coulomb's law is not strictly inverse square law. All relevant classical theories, such as Maxwell's equations and the Lagrangian quantities of electromagnetic fields, rely on the assumption that the static mass of photons is strictly zero. From Einstein's mass-energy relationship and the equation of light quantum energy, the upper limit of the photon mass can be roughly obtained:

m=hν/c2。

Photons are particles that carry energy in light. The amount of energy of a photon is related to the wavelength, and the shorter the wavelength, the higher the energy. When a photon is absorbed by a molecule, an electron gains enough energy to jump from the inner orbital to the outer orbital, and the molecule with the electron transition changes from the ground state to the excited state of the rock hyo cavity.

According to the mass-energy equation, e=mc 2=hv, find m=hv c 2, the photon has no rest mass because it cannot be stationary, and the mass here is the relativistic mass of the photon. In the sense of wave-particle duality of microscopic matter, photons are indivisible. The photon energy is equal to the product of Planck's constant coarse shirt and the frequency of the photon, which is proportional to the frequency of the photon.

Different photons (e.g., gamma photons and X-rays) have different frequencies and therefore different photon energies. <>

There is a misunderstanding ... Try explaining...

e=mc 2, this is the formula for the conversion of mass and energy, but it is not a panacea, it can only be used in certain places, and some characteristics of photons make the formula meaningless.

The previous explanation is certainly difficult to accept, so let's explain it below.

1. Photons are by no means the yellow balls in most **, all elementary particles, including photons, are 0-dimensional things (3 dimensions are spheres, 2 dimensions are infinitely thin planes, 1 dimension is infinitely thin ropes, and 0 dimensions are infinitesimally small points).

2. Photons are particles of light, but light can also be interpreted as waves, and the formula e=hv uses the characteristic of wave-particle duality, and the energy of photons is Planck's constant frequency of light.

The front is all nonsense, in order to supplement common sense, the following questions.

Einstein is outdated, and the first thing to know about this problem is that the mass is **, and the mass is affected by the passage of particles through the Higgs field composed of Higgs bosons"Obstruction"generated. The photon is characterized by its ability to travel through the Higgs field without being hindered, so it has no mass, so it seems that no matter how large the e in e=mc 2 is, m will always be 0.

If you are interested, look for the Higgs boson, there should be a detailed explanation, as for there, you know the drop!