00 50 01 57 02 59 ?How much is the answer?

Updated on Car 2024-03-07
4 answers
  1. Anonymous users2024-02-06

    From min to h is the 60-digit system.

    Correspondingly, from h to min is abdicated by 60.

  2. Anonymous users2024-02-05

    From 1 to 10, multiply 10 consecutive integers: 1 2 3 4 5 6 7 8 9 10. How many zeros are at the end of a product?

    The answer is two zeros. Among them, 1 0 is obtained from the factor 10, and 1 0 is obtained by multiplying the factors 2 and 5, making a total of two. Exactly two zeros?

    Will there be a few more? If you don't believe it, you can calculate the product, and the result is the original formula = 3628800. You see, there are exactly two zeros at the end of the product, and there is no one more than one.

    So, what if you expand the scale and lengthen the ranks? For example, multiply from 1 to 20: 1 2 3 4 ....×19×20。

    How many zeros are at the end of the product? Now the answer becomes 4 zeros. Among them, 1 0 is obtained from the factor 10, 1 0 is obtained from 20, 1 0 is obtained by multiplying 5 and 2, and 1 0 is obtained by multiplying 15 and 4, for a total of 4 zeros.

    Exactly 4 zeros? Will there be a few more? Rest assured, it's not much.

    To get a 0 at the end of the product, a prime factor 5 and a prime factor 2 need to be multiplied in pairs. In the prime factor of the product, 2 is more and 5 is less. There is a prime factor of 5, and there is only a 0 at the end of the product.

    Multiply from 1 to 20, only there is a prime factor of 5 in each of them, and there can only be 4 zeros at the end of the product, and there is no more. Multiply the scale a little more, from 1 to 30:1 2 3 4....×29×30。

    Now how many zeros are there at the end of the product? Obviously, there are at least 6 zeros. You see, from 1 to 30, the sum of 30 is a multiple of 5.

    From each of them, one 0 can be obtained; They have a total of 6 numbers, and you can get 6 zeros. Exactly 6 zeros? Will there be more?

    Whether you can have more or not depends on the number of prime factor 5. 25 is 5 squared, and it contains two prime factors of 5, and here there is an extra 5. Multiplying from 1 to 30, although only 6 of the 30 factors are multiples of 5, they contain 7 prime factors of 5.

    So there are 7 zeros at the end of the product. Multiply it to 30 and do it, no matter how wide it is. For example, this time multiply a little more, from 1 to 100:

    1×2×3×4×…×99×100。How many zeros are there at the end of the product now? The answer is 24.

  3. Anonymous users2024-02-04

    1:00+9:34=(10:34) 12:

    59 2:35=(10:24) 9:00 3:

    45=(5:15) 7:00 1:13=(5:47) 10:

    57 2:32=(8:25) 13:00 4:

    17=(8:43) 15:37+2:13=(17:50) 17:

    30+4:16=(21:46) 5:55+6:

    55=(12:50).

  4. Anonymous users2024-02-03

    When the cumulative number of seconds exceeds 60, divide by 60, and the divisor is rounded to minutes, and the remainder is seconds.

    When the cumulative score exceeds 60, divide by 60, and when the divisor is disturbed and imitated, the remainder is Cong Li distribution.

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