Is there only one person answering the question at a time?

There are two questions in a test, 26 people answered one question correctly, 18 people answered the second question correctly, and 9 people answered both questions correctly

There are 17+9+9 35 people who answered at least 1 question correctly, and those who did not answer correctly: subtract 35 people from the total number of people to get both questions right. I don't know how many people there are, so I can't give a result.

Can answer the question but there is no bonus for the lead sparrow, not an excellent answer letter quietly. Huaitan early.

No, at present, it's just that the answer has become stricter, as long as you answer carefully, you can also trigger the reward without irrigation.

Yes, the current answer is very difficult to pass, I have basically given up on people, saying that it is a high-quality answer, but in fact, the standard of high-quality answer is even more vague.

No, but it's almost impossible to pass questions that want to be good answers right now.

It's possible, but there are many people, and there will definitely be a pass.

Generally speaking, you can pass, just don't do any bells and whistles.

It didn't pass last week!

Yes, I don't know what's wrong, no matter how I answer the question, I can't pass, it's been a few days, no matter what type of question I answer, I have been answering it respectfully, and I haven't been able to pass and be frank.

So far, there are several major questions that I have not passed every day, and I don't know how to answer them.

The answer is 1

From 1=4, we can see that 4=? The answer is 1

Hope it helps

Question 3:

Find the edge length: 60 12 = 5 (cm).

Cardboard area: 5 5 4 = 100 (square centimeters).

Note: Each edge of the cube is equal in length, for a total of 12 edges. Each face is equal in area, and the upper and lower bottom are subtracted, and there are 4 faces.

Question 4: Height: 30 5 6 = 1 (decimeter).

Surface area: (5 6 + 5 1 + 6 1) 2 = 82 (square decimeters) Note: Box volume = length, width and height, known volume, length and width, you can find the height. Box surface area = (length and width + length and height + width and height) 2

Question 5: According to the length of the cuboid, 6 2 = 3 (blocks) can be known

According to the width of the box, 4 2 = 2 (block).

One layer can put 2 3 = 6 (blocks).

High 5 2 = 2 (layer) ......1 (decimeter).

Therefore, in the case of not being exposed, you can put 2 layers and 6 cubes in the inner layer, a total: 2 6 = 12 (blocks).

It could be a problem with the phone, what I see here is basically blurry.

I also saw it vaguely, but I couldn't see it clearly.