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It's easy to see the matrix symmetry, so just find the minimum value of the sum of columns or rows, and look at the graph to mean that in xls, give you a reference program, a=xlsread('filename');%** location.
for ii=1:10
b(ii)=sum(a(ii,:) sum the ii rows, which row you want to find or which piece of data you want to read, see the xlsread function.
endmin(b)% output minimum.
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clc,clear
num=rand(3);
num=[1,2,3;4,5,6;7,8,9]row=size(num,1);
col=size(num,2);
count=perms(1:col);Arrange the columns in full order.
data=zeros(size(count));
oricol=zeros(size(count));
for j=1:size(count,1)for k=1:row
data(j,k)=num(k,count(j,k));Take different row and column elements.
oricol(j,k)=count(j,k);Columns in the original matrix.
endend
dataoricol
result=min(sum(data,2)) is the smallest.
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Save the sum of the elements of different rows or columns into an array, and then use max() or min() to find the maximum or minimum value.
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I can't understand the question. However, it must be possible to use sort. You can use this function to return a sort of each row or column.
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sum(a) is the sum of columns.
sum(a,2) is the sum of the lines.
Generally, it is of the double type, if the whole matrix is summed, sum(sum(a)).
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The MATLAB min() function already provides the corresponding function, and it can be called as follows:
y,i] = min(x,,dim)
Returns the minimum value of x along the dim dimension, saved in y; Also return where this minimum is located, as an example of your problem:
a=[1,3,5,7;8,6,4,2]a =1 3 5 78 6 4 2
[y,i] = min(a,,1)
y =1 3 4 2i =1 1 2 2
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1. First open MATLAB and enter a=[12 35 24; 26 78 14;16 19 21], creating a 3 rows and 3 columns of a matrix.
2. Then you need to enter max(max(a)) to find the maximum value of the a matrix.
3. Then you need to press the enter key, and you can see that the maximum value of the A matrix is 78.
4. Then you need to enter min(min(a)) to find the minimum value of the a matrix.
5. After pressing the enter key, you can see that the minimum value of the matrix is 12.
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% assumes the following matrix a
a=[1 2 3;
We need to multiply the first row by 1, the second row by 2, and the third row by 3b=[1;
b is a column vector that holds the number that needs to be multiplied for each row.
First, copy b into a matrix of the same size as a according to the number of columns of a ([1 1 1; 2 2 2;3 3 3])
Then multiply it with the element corresponding to a, and you can get the desired result cc=a*repmat(b,[1,size(a,2)])
Here are the results. a =1 2 3
b =123
c =1 2 3
There's an easier way.
c=diag(b)*a;
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For the 10x10 matrix a, min(a) can be used to find the minimum value of each column matrix to form a row of vectors. Then use the min function to find the minimum value of the new row vector.
min(min(a))
[mi,i]=min(a) is used to find the maximum value of each column of matrix a and give it to mi, and the number of rows i where the minimum value of each column is located is given.
Using [m,j]=min(max), the minimum value and the number of columns j it is in are returned.
The simplest operation is that min(a(:)
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function minvalue=result(a)n=length(a);The length of a is sought, and this sentence can be omitted if n=10 is known.
int i;
for i=1:n % then n is 10
value(i)=min(a(i));value is an array of stored minimum values.
endminvalue=min(value);
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You can first find the column bai and, and then add du
The vectors of columns and components are transposed, and then the vectors after dao transpose are specialized. Example: Find all for matrix a.
The sum of the genus elements can be:
sum((sum(a))')。Example: a =
sum((sum(a))')
ans = 136There are about four functions for decimal rounding: floor, ceil, round, and fix
For example: if a = [, floor: near the nearest integer in the direction of negative infinity, floor(a)ans =
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You can ask for it first.
Column sum, then transpose the vector composed of the column and the source, and finally find the column sum of the transposed vector. For example, for matrix a, find the sum of all elements, which can:
sum((sum(a))')。Example: a =
sum((sum(a))')
ans =136
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a is a two-dimensional matrix.
sum of all elements(sum(a)).
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Actually, it doesn't have to be so troublesome, there is a better way:
eg:a=[1 2 3;4 5 6]
sum(a(:)
That is, summing all the elements.
There is a corresponding ** on the Internet, you can check it yourself!
Use the Symbolic Arithmetic tool.
Start by defining the variable symbol. symss >>>More
Given a square matrix a, ax-xa=0 is a system of linear equations with respect to the components of x. >>>More
You're doing it with less double quotes.
Here's an example: DimnAs >>>More
The famous writer Bi Shumin commented on this book: x0d This is a book that goes beyond everyday experience. Just started reading.