Mobile phone masters, please come in!! 1, Hurry!! Online, etc., the master enters

Updated on number 2024-03-19
8 answers
  1. Anonymous users2024-02-06

    If you buy a straight board, you can choose E63 E52 C5 If you buy a machine like E66 6700S, if you buy a slide cover, you can choose a machine like 5230 5530 5233 If you buy a touch screen, you can look at it on the Internet.

    The mobile phone information inside is quite complete.

  2. Anonymous users2024-02-05

    Recommend e15i,I've just started,1700 blocks,It feels good,Android system,The software is very full of wifi、Navigation and other functions。

    Everything else is good, but the battery is not very good.

  3. Anonymous users2024-02-04

    Undoubtedly, Motorola's DeFi ME525.

  4. Anonymous users2024-02-03

    Don't buy Nokia, Meizu Spike.

  5. Anonymous users2024-02-02

    Meizu M8M9 floor owner pays attention....Good opportunity does not explain.

  6. Anonymous users2024-02-01

    I heard that N82 is also good, and many of my friends use it.

  7. Anonymous users2024-01-31

    (1) Let half a = third b = quarter c = 201120122013 = k, then a = 2k, b = 3k, c = 4k

    If m = 4a + 3b - 4 parts of 4c + 4b + c, then m = (6k + 12k + 4k) (8k + 9k - 16k) = 22k k

    Divide 22 into the sum of several integers so that their product is maximized.

    22 should be divided into several sums of 2s as much as possible.

    i.e., 22 2 2 ......2 (sum of 11 2's) then, n 2 2 ......2 (product of 11 2's) 2 to the 11th power (3) 1/2x4 + 1/4x6 + 1/6x6 + 1/6x8. nx(n+2) one.

    1/2)×(1/2-1/4+1/4-1/6+1/6-1/8+……1/n-1/(n+2))

    1/2)×(1/2-1/(n+2))

    n/4(n+2)

    2 to the 11th power) 4 (2 to the 11th power + 2) (2 to the 8th power) (1 + 2 to the 10th power).

  8. Anonymous users2024-01-30

    (1) A 2 = B 3 = C 4 = 201120122013 = K then A = 2K, B = 3K, C = 4K

    If m=(3a+4b+c) (4a+3b-4c) (there should be parentheses, right?) Then m=(6k+12k+4k) (8k+9k-16k)=22kk

    Divide 22 into the sum of several integers so that their product is maximized.

    Then 22 should be divided into 6 3's and 1 4, and their product size should be n=3 6x4=2916

    3)1/(2x4)+1/(4x6)+1/(6x8)..1 [n(n+2)] (There should be parentheses, right?) )

    1/2)(1/2-1/(n+2))

    1/2)[(n+2)-2]/[2(n+2)]=1/2)n/[2(n+2)]

    n/[4(n+2)]

    2916/(4x2918)

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