A cylindrical pool, the diameter of the bottom surface of the pool is 3, its volume is 18 26m, how d

Solution: (1) The bottom surface area of the pool: s = (3 2) (3 2) = square centimeter cubic meter = 18,260,000 cubic centimeter.

2) The volume of the pool is v=s h, (h is the depth of the pool).

The depth of the pool h is: h=v s=18260000 A: The depth of the pool is meters.

P.S. After calculating the problem, I would like to repeat a few words, calculating engineering problems, we will naturally connect with reality, for example, calculating the flight speed of an airplane is 60 kilometers per hour, then this problem is wrong. The same is true for this question, no matter how smart people are now, no matter how good the technology and how good the materials are for modern people, it is impossible to make a pool with a diameter of 3cm and a depth of water.

It may be that the diameter of the bottom surface of the pool is 3m, and it may be that 3m is copied to 3cm when copying the question.

Bottom area: s==

18260000cm²

High: 18260000

Oh my God, it's higher than Mount Everest!!

There is a problem with your pool, the floor diameter is 3cm...

The bottom surface of the pool is 8 meters in diameter and 4 meters in radius. Therefore, the base area is r = 4m) =16 square meters.

The height of the pool is 6 meters, so the side area of the pool is the perimeter multiplied by the height. The circumference of the circle is 2 r, so the area of the side of the file is 2 r h=2 (4m) 6m=48 square meters.

Therefore, the total area of the pool is the bottom area plus the side area, i.e. 16 square meters + 48 square meters = 64 square meters. Rent a limb.

The final answer is 64 square meters, or about square meters.

Pool floor area = square meters.

The area of the plastered part = 314 + 2 square meters.

Hello Pool floor area = square meters.

Forehead... I'm just here to hit the soy sauce drops, yes, the landlord, are you in the sixth grade?

The square area is 314 square meters.

Actually, I also came to check. So...

This circular pool is 16 meters in diameter and meters deep, and its volume and area are as follows:

First, the area of the pool:

square meters) two, the volume is:

The footprint of this pool is:

Square metre.

乄16 2x16 2 two answer covers an area of square meters.

Volume = base area x height.

Cubic metre. Money: Yuan.

10 is the diameter, so the radius is 5, the radius squared is 25, and the base area is multiplied by 25.

It is 47 cubic meters of water once put in, which is 47 tons, which is yuan.

Circumference = 2 r =

So r is approximately equal to 1

So... Base area.

r*2 is approximately equal to.

Because volume = s*h

So the volume = 2* is approximately equal to cubic meters.

Hope, thank you.

Radius: 20 2 = 10 (m), bottom area: square meters), side area: square meters), cement surface area: square meters), A: The area of the cement surface is square meters.

Hope!!!

The radius is 10m, then the bottom perimeter is 20, so the side plastering area is 20 2=40

The bottom plaster is 100 square meters, so it's 140 square meters in total.

Second question. Bottom area height = 100 2 = 200 m so it can hold 200 tons of water.

Thank you. If you can't, continue to ask me.

But I won't illustrate the 、、、 that the volume of the cylinder is cubic meters, which means that the volume of the cylinder is cubic meters.

The diameter of the bottom of the pool is 4 meters, you can know that the radius of the cylinder is 2 meters, the problem is to find the height of the cylinder, you can understand this.

The volume of the cylinder = base area x height = r x height (you can solve the equation with unknown numbers, or you can directly substitute the formula).

Let the rough height of the cylinder be x meters ( take.

x=4x=6x=

The depth of the pool is meters.