A cylindrical flat bottomed container with a bottom area of 0 05 square meters, place it on a horizo

Replace the units with uniform centimeters for easy calculation.

square meters = 500 square centimeters.

square meters = 200 square centimeters.

m = 15 cm.

3 kg of water = 3 liters = 3000 cubic centimeters (at room temperature and pressure), and the average density of blocks is 800 kg per cubic meter.

That is, less than the density of water, as long as there is enough water to make it float.

The space behind the object in the dissolver = 500-200 = 300 square centimeters.

After pouring 3000 ml of water, it is only full to 10 cm = meters.

The buoyancy force of water on the object = ox.

The weight of the object itself = ox.

The pressure of the object on the bottom of the container = cattle.

The pressure of the object on the bottom of the container = Ox square meter = 196 Pa.

After removing the block.

The height of the water = 3000 cubic centimeters 500 square centimeters = 6 centimeters = meters.

The pressure of water on the bottom of the container = 1000 * Pa.

A: Pour 3 kg of water into the container, and the pressure of the block on the bottom of the container is 196 Pa.

After removing the block, the pressure of water on the bottom of the container is 588 Pa.

1) The pressure of the object is equal to the pressure on the bottom of the container.

1176-980=196 (pa)

1.Volume of block a = 10 3 = 1000 cm 3= cubic meter of gravity experienced by object b = n

Volume of object b = cubic meter.

d = [10000( kg cubic meter.

2.Water level elevation = (

The pressure of water on the bottom of the container increases n square meters.

1.Pressure of water = PGH = 10 cubic times 10 times 10.

2.Density = Mass Volume =

3。Since the cube is denser than water, it must sink into the water. Furthermore, the volume of the cube (1x10 -3) is larger than the volume that the container can hold (.

So consider that the mass of the overflow water = (the volume of the cube - the volume that can still be contained) multiplied by the density of the water = , which is equivalent to putting in a cube with mass (.

So the pressure change is = (area =

The density of the cube is greater than the density of water, and it sinks to the bottom of the water, and the surface is exposed to the surface of the water (1) The pressure of water on the bottom surface:

p=ρgh=

2) (3) The increased pressure is equal to the gravitational force of a:

So the increased pressure: p1=

The pressure of water on the bottom of the cup p= gh = 1 10 10 10 100 = 1 10 pa

The pressure of water on the bottom of the cup n=ps=1 10 2 10 -2=20n

Distinguish between water to the bottom of the cup and the cup to the tabletop.

Yanchi 1) :p = f s f = m (water) g m (water) = dense width modified coarse Li multiplied by volume = f = p = 1