I know how to calculate the color of a flag, one red, two white, three black, and the forty third si

If it's only red, white, and black, you can count it like this!

Let me start with the reason: there is only 1 red one

There are 2 white ones and 3 black ones

So in order, the first side is definitely red, the third side is definitely white, and the sixth side is definitely black!

If there are no other requirements, let's go step by step. Simple calculations from 1 to 6 have six Arabic numerals!

But the way these types of red flags are counted has to be changed! 6 is already occupied! So if we want to add 6 more flags, we have to start with 7!

That is, the relationship between adding 1 and subtracting one! If so, what color is the twelfth side? The twelfth is also a black flag!

Then 12+12 equals 24, and the 24th is also a black flag.

24+24 equals 48 The 48th is also a black flag, so after deducting the last 3 black flags, the last 2 white flags, then the 43rd is definitely red.

Of course, the direct way of calculation (I calculated according to the number of flags given by the title): 43 divided by 6 (the reason is that the sixth place is black, which is fixed!) There are 6 Arabic numerals from 1 to 6, and 7 to 12 are also 6 Arabic numerals. 13 to 18 too! And so on).

Then out of 43 flags, there are 7 groups of 6! In other words, 42 happens to be a black flag! Then 43 is undoubtedly a red flag!

A: Black. Divide the missing megabytes:

Take 3 yellow, 2 white and 4 black, a total of 3 + 2 + 4 = 9 flags as 1 group of leaks.

243 9 = 27 (group).

The above formula shows that the 243rd flag is at the very end of the last guess of the old group, so it should be black.

x y=1 2,x+y=,x=Because the arrangement is by integer, x represents the black flag first, and according to the rule of the cycle, it represents 1 black flag, so the black flag is 34 and the white flag is 66.

There are 66 white flags and 34 black chess. Because three flags are a group, 100 flags are divided into 33 groups, and one more is a black flag. So black is 33 + 1 and white is 33 + 33 = 66Thank you. You're ruthlessly smart. Admire.

Let's look at how many 99 sides there are, every 3 groups, there are 33 groups, black 33 white 66, 100 faces are black 34 white 66

1+2+3=6

It means that after 6 reincarnations, there are 2 red flags, 3 green flags, and 1 yellow flag: the total number of red flags is: 2 14 + 2 = 30.

The total number of green flags is: 3 14 + 3 = 45.

The total number of yellow flags is: 1 14 = 14.

89÷（2+3+1）=14---5

The color of the 89th bunting is the green flag.

Red flag: 14 2 + 2 = 30 faces.

Green flag: 14 3 + 3 = 45 sides.

Yellow flag: 14 1 = 14 sides.

2 pink flags, 4 yellow flags, 2 red flags, a total of 8 flags as a group of cycles, 45 flags a total of 5 groups of more than 5 flags.

The order of the extra 5 sides is pink pink yellow yellow yellow.

So the last flag is yellow.

Pink flag: 5 2 + 2 = 12

Yellow flag: 5 4 + 3 = 23

Red flag: 5 2 = 10

Divide 38 by 4 to get 9 and 2, that is, there are 9 black flags, so white flag = 38-9 + 2 = 29

2 red, 2 yellow, 1 white in order, that is to say, a round is a total of five flags, five rounds down, that is, a total of twenty-five flags.

Forty percent (two-fifths) of this is red

That is, two-fifths of twenty-five, that is, ten-sided.

And the twenty-sixth side is naturally the original red, so there are eleven sides in total.