Why is the solid of Na2CO3 not alkaline while the solution of Na2CO3 is alkaline 5

It is alkaline because there are more hydroxide ions than hydrogen ions in the substance... Sodium carbonate solids, on the other hand, are not electrolyzed, and they have these two ions, but in exactly equal amounts. In the sodium carbonate solution, the carbonate ions undergo secondary hydrolysis and ionize the hydroxide ions, so the sodium carbonate solution is alkaline.

Na2CO3 has no hydroxide ions in the solid at all, so it is not alkaline, but Na2CO3 can be hydrolyzed in water to form hydroxide ions, so the solution is alkaline.

The range of discoloration of phenolphthalein is so phenolphthalein can only detect alkalis and not acids. (light red) (red).

The alkaline PKB of sodium acetate = should have a red low concentration and may appear red when heated and boiled.

1.The concentration of sodium acetate solution is extremely low. For example, the experimental teacher of our school added medicine like this: after the first class was completed, he found that the amount of a certain drug was not much, so he put a small amount of water on the tap and filled it up, which may cause the concentration of the drug to be extremely low.

2.The previous class of classmates at the experimental table made by the landlord deliberately made trouble, adding a small amount of acid (such as hydrochloric acid) to the sodium acetate solution you used, which inhibited the hydrolysis of acetate ions, and the hydrochloric acid volatilized after heating, so there was pink. If that's the case, the experimental phenomena before and after your lab table are different from yours.

3.It may be that the experimenter has mismatched the drug. The whole class is the same.

Na2CO3 (sodium carbonate) added to phenolphthalein is red Sodium carbonate itself is hydrolyzed in water, and the degree of hydrolysis is greater than the degree of ionization, so the solution is alkaline and turns red immediately after phenolphthalein is added.

Sodium acetate is a strong electrolyte that is completely ionized, and the acetate ions are hydrolyzed to combine with the hydrogen ions in the water, so that the concentration of hydroxide ions in the solution is greater than the concentration of hydrogen ions, so the solution is alkaline.

As for the smell of alcohol, it is estimated that the medicine is contaminated with alcohol.

Sodium acetate is easily soluble in water but insoluble in alcohol, and when the two solutions are mixed, sodium acetate becomes a gel precipitated in alcohol. The liquid gradually changes from turbid to thick, and finally condenses into a single piece, resulting in solid alcohol.

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Phenolphthalein is prepared by heating phthalic anhydride and phenol to 115-120 for condensation under the condition of adding dehydrating agent.

Upstairs said that phenolphthalein indicators contain alcohol and I agree.

This involves a problem related to the hydrolysis of jujube beams

Na2CO3 + 2H2O === Reversible reaction) 2NaOH + H2CO3 So it can be seen that a very small part of NaOH and H2CO3 are formed by hydrolysis, so we know that NaOH is more alkaline than H2CO3 acidic, so the solution is alkaline

The ionic equation is written in two steps, because ionization produces 2 acids, and that's the first step, CO32- +H2O=HCO3- +OH- and that's the second step, HCO3- +H2O=H2CO3 + OH- Together, it's CO32- +2H2O=2Oh- +H2CO3

Because Na2CO3 can be regarded as the neutralization product of strong alkali (NaOH) and weak acid (H2CO3), and the aqueous solution of salt obtained by the neutralization of strong alkali and weak acid is alkaline.

The aqueous solution of the resulting salt neutralized by strong acids and weak bases is acidic.

The aqueous solution of the resulting salt neutralized by strong alkalis and strong acids is neutral.

The aqueous solution of the resulting salt by the neutralization of weak alkali and weak acid is neutral.

Why is the aqueous solution of Na2CO3 alkaline!!

Because water will decompose into H+ and OH-, and CO3 and H+ combine to form HCO3-, the number of OH- in the solution is greater than the number of H+, and it is alkaline.

Sodium carbonate is a strong base and weak salt. The carbonate in it is hydrolyzed in an aqueous solution. Hydroxide is generated. Inherently alkaline.

Equation: CO32-

h+= (double arrow) h2o+CO2

Causes fewer hydrogen ions in the water and more hydroxides. As a result, the solution appears alkaline.

It is its aqueous solution that is alkaline.

The reason is that water is weakly ionized with H+

It is completely ionized with OH-Na2CO3 to produce Na+ and CO3(2-)H+ combined with CO3(2-).

HCO3- causes more OH- than H+ in the night.

At the same time, HCO3- can also combine with H+ to form H2CO3, but this is an extremely small amount, although there are but sometimes can be ignored, but the previous part can not be ignored, and the above all make OH- much more than H+.

As a result, the solution becomes alkaline.

Note that the reason why H+ is combined with CO3 (2-) is because H2CO3 is a weak acid, which involves hydrolysis knowledge, if you haven't learned it, you can understand it first.

Na2CO3 + 2H2O = 2NaOH + H2CO3, and NaOH can ionize all the OH roots, and carbonic acid can only ionize some H ions, so the solution will be alkaline, which is also the general law of strong alkali and weak salt.

Because of CO3

2-ion is a weak acid ion··· Easy hydrolysis in solution Hydrolysis process: CO32-+

h20=(reversible)=

hco3-oh-

When the concentration of OH- increases, it becomes alkaline.

It can be known by the method of ionization hydrolysis.

na2co3===na+

co32-h2o===h+

OH- Positively charged and negatively charged ions are added.

na++oh-===naohh++

co32-===h2co3

It can be known that it is a strong base and weak salt.

Alkalinity accounts for a large proportion, so soda ash is alkaline.

The ionization of NaHCO3 gives HCO3- ion Its hydrolysis: HCO3-+H2O ==H2CO3+OH- is greater than that of its ionization:

HCO3 == reversible) H+ +CO32- that is, there is more OH - in solution than H+, so it shows alkalinity.

And the degree of HSO3- corresponding to the ionization of NaHSO3- is stronger than that of carbonic acid, so its ionized HSO3- = reversible) H+ +SO3 2- is greater than the degree of hydrolysis: HSO3- +H2O ==H2SO3 + OH- is H+ than OH- so the solution shows acidity.

Bicarbonate is mainly hydrolyzed, and hydrolysis produces carbonic acid and hydroxide. Bisulfite is mainly ionized, producing hydrogen ions and sulfite.

NaHCO3 is decomposed into Na+ and HCO3- in water: HCO3+H2O=H2CO3+OH-

NaHCO3 is decomposed into Na+, H+, and CO3- in water

ionic reaction co (

h₂o=hco₃（-

The oh(-) equation Na2CO3+H2O=NaHCO3+NaOH is alkaline due to the production of empty OH-.

After the hydrolysis of Yikai bend, there will be no more level 2 Hengsun blind hydrolysis.

Hope it helps

It is not an acid salt, an acid salt.

The alkalinity of Na2CO3 comes from CO32-, and its hydrolysis shows alkaline CO32- +H2O = HCO3- +OH-

NaHCO3 is an acid salt, and its solution is also alkaline.

It is because the degree of HCO3- hydrolysis is greater than that of ionization, and the acid salt and basic salt are classified according to whether the salt contains OH- and H+, and has nothing to do with the acidity and alkalinity of the solution.

The solution of Na2CO3 is alkaline, but it is not an acidic salt.

You're talking about nahco3, right? He is alkaline in aqueous solution, and he calls it an acid salt.

Because NaHCO3 ionizes NA+, H+, CO32-, and hydrogen ions when it is ionized, it is called an acid salt.

NaHCO3 is alkaline in solution hydrolysis, and the degree of hydrolysis is greater than that of ionization, so although it is an acid salt, the solution is alkaline.

Na+ is a metal ion, CO3- is an acid ion, so it is an acidic salt, and because it is a strong alkali and weak salt, it is alkaline.

The ionic reaction Co ( HO=HCO (-OH(-) equation Na2CO3+H2O=NaHCO3+NaOH is basic due to the production of OH-.

After one hydrolysis, there will be no more secondary hydrolysis.

Hope it helps

Hydrolysis of salts.

co3(2-)+h2o=hco(-)oh(-)

The equal sign is a reversible sign.

Na2CO3 is hydrolyzed when it is placed in water.

CO32-+H2O reversible sign HCO3-+OH-HCO3-+H2O reversible sign H2CO3+OH- So, sodium carbonate solution is alkaline.