Why do HCl and Na2CO3 react at different concentrations to produce different products? The main expl

When Na2CO3 reacts with HCl, its essence is that CO32- reacts with H+, and CO32- can combine two H+ in total to form H2CO3, which decomposes to form CO2 and H2O. The mechanism is as follows:

co32- +h+ ==hco3- ;hco3- +h+ ==co2↑+h2o

If there is a small amount of HCl, or if the HCl solution drops into the Na2CO3 solution dropwise to start a reaction, only the first step of the reaction can occur. Namely.

na2co3+hcl ==nahco3 +nacl+h2o

If the amount of HCl is sufficient, or the HCl solution is dropped dropwise into the Na2CO3 solution for the next stage of the reaction, the reaction can be carried out to the second step. At this time, it is generally regarded as the occurrence of a total reaction CO32- +2H+ ==CO2 +H2O

That is, Na2CO3 + 2HCl ==2NaCl +CO2 +H2O

Because the Na2CO3 solution contains carbonate and a small amount of bicarbonate, carbonate is more likely to form hydrogen ions than bicarbonate. Therefore, when the concentration of hydrochloric acid is small, the hydrogen ions are not enough, and the sodium carbonate can only be converted into sodium bicarbonate. The concentration is high, there are many hydrogen ions, and sodium bicarbonate becomes sodium chloride and carbon dioxide and water.

The reaction is actually carried out in two steps, first the hydrogen ions react with the carbonate ions to form bicarbonate ions, and the living bicarbonate ions react with hydrogen ions to form carbon dioxide and water. Therefore, when the sodium carbonate solution is excessive, carbon dioxide gas will not be generated, and when the sodium carbonate solution is small, carbon dioxide gas will be generated.

It is related to the amount of carbon dioxide produced.

Na2CO3 and HCl reaction phenomenon: a large amount of gas is generated;

The chemical reaction equation for the reaction of Na2CO3 and HCl: Na2CO3+2HCl=2NaCl+H2O+CO2

Types of Na2CO3 and Brigade-Bond Destruction HCl Reactions: Dismantling and Metathesis Reversal Bright Response.

Na2CO3 is overdosed in a circular state.

Na2CO3 + HCl = NACl + NAHC3HCl when there is an overdose of the cavity is done.

na2co3+2hcl=2nacl+co2↑+h2o

When the hydrochloric acid is sufficient, sodium chloride and carbonic acid are generated, and the unstable carbonic acid immediately decomposes into curved ridge carbon dioxide and water. This reaction can be used to prepare carbon dioxide: the total chemical equation is:

Na Co +2HCl = 2NaCl + H O+Co When hydrochloric acid is small, the following reaction occurs: sodium carbonate can also react similarly with other kinds of acids.

na₂co₃+hcl=nacl+nahco₃<>

Non-reactive, metathesis reactions are conditional on the formation of weak electrolytes (e.g., water), gases, or precipitates.

N(Na2CO3) to osmotic reflux", N(HCl) HCl+Na2CO3=NaHCO3+NaCl(NaHCO3, Na2CO3 nuclear starvation).

n(na2co3) shouted no.

Because of the amount of the same substance.

NaHCO3 and Na2CO3, the amount of substances that NaHCO3 requires hydrogen ions is a multiple of the amount of substances that Na2CO3 requires hydrogen ions.

In addition, the reaction of NaHCO3 with hydrochloric acid requires a one-step reaction, the chemical equation of the reaction.

For: nahco3

hclnacl

h2oco2↑

Na2CO3 requires a two-step reaction to produce gas:

Step 1: Na2CO3

hclnacl

nahco3

Step 2: NAHCo3

hclnacl

h2oco2↑

Sodium carbonate. The second step of the reaction is sodium bicarbonate.

The first step of the reaction, so NaHCO3 reacts faster than Na2CO3 with HCl.

nahco3

Because the reaction essence of Na2CO3 is:

Na2CO3+HCl=NaCl+NaHCO3NAHCo3+HCl=NaCl+H2O+CO2 can be summed up as follows.

Na2CO3+2HCl=2NaCl+H2O+CO2 Because there is one more step, it is slower and the first year of high school should be talked about.

First of all, correct one of your mistakes: the chemical formula of sodium carbonate is Na2CO3, not NaCO3 When NaHCO3 and Na2CO3 react with the same concentration of hydrochloric acid, respectively, NaHCO3 reacts more violently.

If a small amount of dilute hydrochloric acid is dropped into the sodium carbonate solution, no bubbles will be seen, because the following reaction has occurred

Na2CO3+HCl==NaHCO3+NaCl, you have to continue to add hydrochloric acid dropwise to see bubbles. Dilute hydrochloric acid drops into NaHCO3 solution, and bubbles appear at the beginning.

Na2CO3 + 2HCl (excess) ==== 2NaCl + H2O + CO2 Na2CO3+ HCl (small amount) ==== NaCl + NaHCO3

Na2CO3 is an alkaline salt, hydrolyzed into alkaline Na2CO3 ==== 2Na++CO32- CO32- +H2O ==== HCO3- +OH- HCO3- +H2O ==== H2CO3 + OH

Therefore, it reacts with dilute HCl to form NaHCO3