The master and apprentice made 200 parts, and the 1 4 made by the master was 1 4 more than the 1 5 m

Updated on military 2024-04-08
16 answers
  1. Anonymous users2024-02-07

    This kind of problem is all one type, and it is actually very easy to solve.

    First of all, you need to understand the question, and then you just need to list the equation according to the description of the question. For example, if you get a new machine, you must look at the manual to actually operate it, and this kind of problem is the same.

    Here's how to solve the problem::

    There are two variables for these types of questions (why?). Because you haven't learned how to solve three variables yet, hehe, so just find two. If there are three people mentioned in the question, then you have to read the question carefully, there must be one of them that is confused, so first look for two variables:

    You can see that in this problem it is the efficiency relationship between the master and the apprentice, so the variables are the master and the apprentice, set to x and y, respectively.

    Then there are two equations: the two equations are used to find the answer, so the question will inevitably give you two relationships between the two variables. From the title, you can see that "the master and apprentice make 200 parts", which is a relationship, so the equation is calculated:

    x+y=200。"The master makes 25 more than the apprentice makes one-fifth of 14" This is another relationship, so it has to be calculated: So that's basically the end of the question, and then you just need to calculate the answer.

    I'll give you a mantra for this kind of question: two variables, two relationships. Make a list of the equations and you're done.

    Here's the full solution:

    The master made x and the apprentice made y:

    x+y=200

    Bring in the solution: x=120, y=80 (the solution process is no longer auspicious) above the pure manual hand, I hope to help the landlord. (Pick mine!) )

  2. Anonymous users2024-02-06

    Master x Apprentice Y

    x+y=200

    1/4x-1/5=14

    Substitute for y=80

  3. Anonymous users2024-02-05

    Subtract 14 from the master's 1 4, and talk about it the same as the apprentice, the master made a total of 4 1 4, subtracting 4 14, that is: 14 4 = 56

    After subtracting 56 from the total, a total of 4+5=9 parts. One copy is: refers to the surplus (200 56) 9=16 (pcs).

    The apprentice did: 16 5 = 80 (pcs).

  4. Anonymous users2024-02-04

    The master does more than the apprentice and does 55% -45% = 10%.

    The batch of chain parts has (50 10%)=500 pcs.

    The master did it (500 55%) = 275, and the apprentice did it (500 45%) = 225.

  5. Anonymous users2024-02-03

    Set up x cooperation, 55%x-45%x=50;x=500

    The master made 275 and the apprentice made 225.

  6. Anonymous users2024-02-02

    Do 21 less than the master, that is, do less than the Biheng batch of parts (5 7 - 2 7) of the reputation socks 3 hands do 7a

    3/7a = 21

    a = 49

    There are 49 parts in this batch.

  7. Anonymous users2024-02-01

    The master and apprentice made a batch of parts in Rolling Orange Town together, the ratio of the number of parts made by the master and the apprentice was 5:3, the apprentice made 1500, how many did the master make?

    Solution: Use the proportional large bold equation:

    5:3=x:1500.

    x=1500x5/3

    x=500x5

    x=2500.

    Answer: The master made 2,500 of them.

  8. Anonymous users2024-01-31

    The master did: 1-2 7 = 5 7

    The master pen apprentice does more of the total number: 5 7-2 7 = 3 7

    The total is: 21 3 7 = 49.

  9. Anonymous users2024-01-30

    The apprentice did two-sevenths of the total, then the master did 1-2 7 of the total, which is equal to five-sevenths. The master did 5 7-2 more than the apprentice, and 7 equals three-sevenths. Three-sevenths corresponds to the number twenty-one, 21 3 7 49, and the total number of parts in this batch is 49.

  10. Anonymous users2024-01-29

    This question is answered like this:

    49 (pcs) 49 2 7 = 14 (pcs) ......Apprentice-made parts.

    49 5 7 = 35 (pcs) ......Parts made by the master.

    A: There are 49 parts in this batch.

  11. Anonymous users2024-01-28

    This batch of parts has:=49 (pcs).The apprentice made 49 2 7=14 (pcs).

    The master made 49 (1-2 7)=35 (pcs).

  12. Anonymous users2024-01-27

    Solution: From the meaning of the title, it can be seen that the master has done the total number of 5 7, which is more than the apprentice 5 7 - 2 7 3 7, then:

    21 (3, 7) 49 (pcs).

    A: There are 49 parts in this batch.

  13. Anonymous users2024-01-26

    According to the question, it can be seen that the apprentice has completed 2 7, and the master has completed 1-2 7 = 5 7. And the master has completed 5 7-2 7 = 3 7 more than the apprentice. It is also known that the master made 21 more, so the 3 7 of this batch of parts is 21, so this batch of parts is 21 3 7 = 49 (pieces).

  14. Anonymous users2024-01-25

    There are a total of 49 parts in this batch, and the calculation method is 21 3 7, and the final result is 49.

  15. Anonymous users2024-01-24

    Let the master do x apprentices do y x x + y = apprentices do 80.

  16. Anonymous users2024-01-23

    The master instructed the master to do x, and the apprentice did (200-x), and the first was purely according to the title:

    x/4=(200-x)/5+14

    x/4=40-x/5+14

    x(9/20)=54x=120

    So the master made 120 Lu Zhao, and the apprentice made 80.

Related questions
10 answers2024-04-08

Sequence of disassembling the lock cylinder:

1.Remove the inner and outer handle panels: Screw on the handle panel in the house, one on the top and one on the bottom. >>>More

16 answers2024-04-08

Depending on the scope of work over a certain period of time, you can specify the appropriate compression state for the component. This reduces the amount of data that is collected and estimated at work. Assemblies are displayed and rebuilt faster, allowing for more efficient use of system resources. >>>More

21 answers2024-04-08

Electronic components include resistors, capacitors, inductors, diodes, transistors, and MOSFETs. >>>More

17 answers2024-04-08

What parts are normally replaced for automobile engine overhaul? There are more things that are normally required to be replaced, but in many cases it is necessary to detect to determine the black and white, if you want to achieve a good effect, then it is necessary to change more things, what accessories must also look at the model, I will list the machine part for you: overhaul car engine overhaul which parts are normally replaced? >>>More

13 answers2024-04-08

As far as we know, the positioning parts are the parts that determine the installation position of the blank, including positioning pins (plates), retaining pins (plates), guide pins, guide plates, fixed-distance side knives, side presses, etc. Pressing, unloading and discharging parts Pressing, blanking parts include hemming rings, pressing plates, etc. The crimping ring applies a pressing force to the drawing blank, thus preventing the blank from arching under tangential pressure and forming wrinkles. >>>More