There are 35 chickens and rabbits, and there are 110 of their feet

If you are an elementary school student, this question examines the problem of chickens and rabbits in the same cage. Let's start by analyzing, there are 35 chickens and rabbits, and 110 legs, we know that a chicken has 2 legs and a rabbit has 4 legs. If we assume that all chickens are chickens, then the number of feet = 35 * 2 = 70 (only).

The number of feet missing = 110-70 = 40 (only).

A chicken has 2 legs less than a rabbit, so the number of rabbits = 40 2 = 20 (chickens) then the number of chickens = 35-20 = 15 (birds).

A: There are 15 chickens and 20 rabbits.

Or you can assume that it's all rabbits, and the principle of calculation is the same. If you are an upper elementary school or junior high school student, we can consider using equations to solve it, which is also very convenient and easy to understand. There are two equiquantitative relations in the problem:

Chicken + Rabbit = 35

Chicken leg + rabbit leg = 110

We can choose to solve the unary equation or we can choose the binary equation to solve.

Unary Equation Solving Process:

Solution: If there are x chickens, then there are (35-x) rabbits, 2x+4*(35-x)=110

The solution is x=15

Then 35-x=20 (only).

The process of solving binary equations.

Solution: If there are x chickens and y rabbits, then x+y=352x+4y=110

The solution is x=15

y = 20 Answer: 15 chickens and 20 rabbits.

Suppose: If there are x chickens, then rabbits have (35-x).

2x+4 (35-x)=110 according to the title

Simplified to 2x=30

The solution is x=15

i.e. chickens have 15 rabbits have: 35-15=20.

Method 1. Solution: If there are x chickens, then rabbits (35-x) can be obtained from the title:

2x+4(35-x)=110

2x+140-4x=110

2x=30x=15

35-x=20

A: There are 15 chickens and 20 rabbits.

Method two. Column Equation:

Chickens have: (35x4-110) 2

15, rabbits have: 35-15 = 20.

Chicken has two legs, rabbit has four legs, if they are all chickens, then 35x2=70 is less than 40 legs, and these 40 legs are 20 rabbits, therefore.

There are 20 rabbits and 15 chickens.

There is no need to list equations.

If the column:

Set up x chickens and rabbits.

x+y=35

2x+4y=110

x=15 y=20

This problem can be solved by hypothetically, for example, if 35 chickens are all chickens, there are 35 2 70 legs. Or if all 35 rabbits are rabbits, the number of horns in common is 35, 4, 140.

If it is all chickens, it is 70 legs, then it is 40 feet less than 110 feet, because each chicken has two feet less than each rabbit, so with 40 2 20 legs, this is 20 rabbits. Chickens, that is, 35-20 15 pcs.

Of the 35, there are 15 chickens and 20 rabbits.

There are 35 chickens and rabbits, 110 of their feet, 15 chickens, 20 rabbits, 15x2=30 chickens, and 20x4=80 rabbits

Assuming these 35 are all rabbits, then there should be 35x4=140 legs. Now there are 110 legs, and 140-110 = 30 legs are missing, and these thirty legs are 15 chickens, which means that there are 15 chickens.

At this point, the number of rabbit legs is 110-30 = 80, and 80 legs are 80 4 = 20 rabbits.

Equation method: set x chickens, 35-x rabbits.

2x+4×（35-x）＝110

2x+140-4x＝110

2x＝-30

x 15 rabbits: 35-15 20 (only).

Arithmetic: Suppose all chickens have 35 2 70 feet, so rabbits have (110-70) 2 40 (chickens), then there are 35-20 15 chickens.

Let the chickens be x rabbits 35-x

2x+4x（35-x）=110

2x+140-4x=110x=15

Answer: 15 chickens and 20 rabbits.

Solution: If there are x chickens, then rabbits have 35-x

2x+4（35-x）＝110

2x+140-4x＝110

2x＝30x＝15

A: There are 15 chickens and 20 rabbits.

Solution: 110 22 4 dec. 11x2

20×4+15x2

20 dec. 15 35

So there are 20 rabbits and 15 chickens.

Chicken two legs, rabbit four bushes withered legs, if they are all chickens, then 35x2 = 70 less 40 legs infiltrate the Sun Cave, these 40 legs are 20 rabbits, so there are 20 rabbits, and chickens have 15.

There is no need to list equations.

If the column:

Set up x chickens and rabbits.

x+y=35

2x+4y=110

x=15 y=20

Chicken = 90 2 = 45

There are 45 chickens, and the question is wrong.

50 2 = 25 This is the number of chickens.

43-25=18 This is the number of rabbits.

The number of chicken feet is 60 more than the number of rabbit feet.

Indicates that chickens are more than twice as large as rabbits.

60 Crack Lack of Argument Slip 2 = 30.

Therefore: rabbit: (120-30) 2+1) = 30 chicken: 120-30 = 90

Good luck with your studies!

It's a wrong question: A chicken has two legs, and a rabbit has four legs. Even if it's all chickens, they have at least 200 legs, right?

There are two unknowns in this kind of problem: there are x chickens, and there are y rabbits. If the question gives a chicken rabbit and a foot b.

x+y=a2x+4y=b

Just solve it.

If you haven't learned equations in elementary school.

Let's think that there is only chicken A, a total of 2A feet, and the macro cavity value of (b-a) 2 is the number of rabbits (more feet because each rabbit has two more feet than chickens), and then the number of chickens is A minus the number of rabbits.