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Muhaha, the standard answer is here!
According to your idea, you can finally calculate the radius of the sector r=16sfan=nr2 360 (n is the degree of the central angle, r is the radius)sfan=x 120 x 256 360, and finally we get sfan=256 3
If you don't know how to calculate R, I can give you a picture Oh hehe.
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Solution: The height of the bow is 8cm, the degree of the central angle of the circle is 120 ° extended to the center of the circle, and the right-angled side of the 30-degree angle in the right-angled triangle is equal to half of the hypotenuse, and the diameter of the circle is 16 cm.
The area of the sector is 1 3 16 and the area of the triangle is 1 2 8 16 -8 = 4 692
The area of the bow = 1 3 16 -4 692 Let's figure it out for yourself.
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What is Sector Height? Typing it wrong, right?
If the radius is 8 cm, then the area is 8 120 360) = 3 64 (square centimeters).
The formula for the area of the fan: s= r2 (360° at the center of the circle).
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Multiply by 8 squared and multiply by 120/360. The answer is 6/3 of a square centimeter.
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It is a circle with a radius of 8cm, take one-third of it, because the whole circle is 360°, area =
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There are two formulas.
1)s=1/2lr
2) s=n r square 360 = 80 degrees 5*5 cm 360 = square cm
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The sector area formula n(pai)r 360
i.e. system: (
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Find the area of the circle first, and then use the proportional calculation.
S fan = 5 2 * * 80 360) = squared.
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Sector area = 80/360 multiplied by 25
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The area of the sector is x120 360 times x=80 times 30x=720
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A 120-degree fan is one-third of a circle, that is, one-third of a circle with a radius of 1 cm is 1 3 r*r
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