Finding Volume 6th Grade Arithmetic Problems, Primary 6 Math Application Problems About Volumes!

Analysis: Volume Bottom Area High.

The circumference of the bottom surface is enlarged by 2 times, and the bottom area is expanded by 2 square times, that is, it is expanded by 4 times.

So now the volume (4 base area) (height 2) 8 base area is high.

Therefore, the circumference and height of the bottom surface are increased by 2 times, and the volume is increased by 8 times.

If the volume is increased by 35 cubic centimeters, the original volume is: 35 (8 1) 5 (cubic centimeters).

8. The circumference and height of the bottom surface are enlarged, 2, and the volume is expanded by 8 times, 8x-x=35x=5

Solution: When the circumference of the bottom surface is expanded by 2 times, it means that the radius has become 2 times the original.

When the radius is doubled, the base area becomes 4 times.

When the base area becomes 4 times the original and the height becomes 2 times the original size, then the current volume.

That's 8 times the original volume.

This is the subject of a difference problem.

Then we can know that the original volume is: 35 (8-1) = 5 (cubic meters).

Let the original radius be x and the height be h, then the perimeter of the original bottom surface is 2*, and the original volume is set to v

The circumference of the base surface is expanded by a factor of 2, that is, the radius becomes 2x, and according to the title, the new volume after expansion is 7 (

7v=35v=5

That is, the original volume is 5 cubic centimeters.

The water height at this time is x centimeters.

20×20x+40×30×10=40×30x400x+12000=1200x

800x=12000

x=15A: The water is 15 cm high.

Equation: 40 30 10 = 12000 cubic centimeters 40 30-20 20 = 800 square centimeters.

Water height: 12000 800 = 15 cm.

The details are as follows: according to the volume of water before and after the iron block is unchanged to calculate, the volume of water before it is: 40 30 10 = 12000 after the volume of water is: (40 30-20 20) x = 800x where the brackets are the bottom area of the water now, x is the height of the water, and then use 12000 800 = 15, then 15cm should be the current water height What does the owner think?

In fact, a very important sentence in this question is: the iron is exposed to the water, which is a hint. If you don't have this prompt, you have to think about it in many ways.

Calculate the volume of the graph below

= cubic centimeters).

= cubic centimeters).

Send it over and take a look.

Let the original radius be x and the height be h, then the circumference of the original bottom surface is 2*, and the original volume is.

Then set the original volume to v

The circumference of the base surface is expanded by a factor of 2, that is, the radius becomes 2x, and according to the title, the new volume after expansion is 7 (

7v = 35v = 5, that is, the original volume is 5 cubic centimeters.

Hello! Solution: When the circumference of the bottom surface is expanded by 2 times, it means that the radius becomes 2 times the original When the radius becomes 2 times the original, the bottom area becomes 4 times the original When the bottom area becomes 4 times the original and the height becomes 2 times the original volume, then the current volume is 8 times the original volume.

This is the subject of a difference problem.

Then we can know that the original volume is: 35 (8-1)=5 (cubic meters) only represents a personal opinion, don't spray if you don't like it, thank you.

Solution: Bottom area of the fish tank:

Volume of water: area of water pipe: (4 2) square.

Irrigation for about = 4 minutes.

Good luck with your progress.

Length, width, height = length 120 cm, width 40 cm, height 60 cm to be injected into deep water = to be injected into 50 cm deep water.

First calculate the cross-sectional area of the pipe, then calculate the amount of water to be injected per second, and then calculate the volume of water that needs to be filled divided by the amount of water per second.

The unit goes to convert it itself.

Deep water, with a volume of.

Flow rate per minute = water pipe cross-sectional area * 50m = pi * (4 2) 2 * 50 10 4 =

Time minutes.

4cm=, the volume of water to be injected is cubic meters, and the volume of water that can be injected into the water pipe per minute is approximately equal to cubic meters, minutes.

It's so simple!! Multiplying 4 times 6 equals the volume of the cylinder, multiplying 4 times the square multiplied by 3 times one-third equals the volume of the cone, just add it up.

Length, width, height = length 120 cm, width 40 cm, height 60 cm to be injected into deep water = to be injected into 50 cm deep water.

Deep water, with a volume of.

Flow rate per minute = water pipe cross-sectional area * 50m = pi * (4 2) 2 * 50 10 4 =

Time minutes.

(20+10) multiply by 25 divided by 2 and multiplied by 35

30 times 25 divided by 2 and then multiplied by 35

750 divided by 2 and multiplied by 35

375 times 35

13125 cubic centimeters.

Take another one of the same and put this one together to form a cylinder, then the volume is the large cylinder divided by 2, and the large cylinder is equal to {base area} x4x4 multiplied by {10+18}, so the area is cubic centimeters.

Copy this figure and paste it upside down to make a cylinder with a height of 36 cm. Just divide the volume by two.

Just the easiest way.

8 divided by two squared into the bottom area) into (18 2) divided by 2

Answer cubic centimeters.

This question is actually very simple, it is a cylinder with a diameter of 8 and a height of 10 + half of a cylinder with a diameter of 8 and a height of 8.

Volume = (cm3).

= cubic centimeters).

You can add one more section to this irregular cube and it will become a cylinder, so divide by 2 and you're good to go.

Just adopt lalala.

It is solved in two parts, one part is a cylinder with a base diameter of 8 and a height of 10, v1 = 160 vultures. The other part is half of the cylinder with a base diameter of 8 and a height of 8, v2 = 64 vultures. then v=v1+v2=224.

It looks so rare ......I was also ...... in sixth grade

8÷2)x(8÷2)

Split it into two parts, cut a cylinder from a height of 10 centimeters, and half the volume of the cylinder.