Is the object placed on the carriage or, inside the carriage, the object is subjected to static fric

If you do not exert a force on him in the horizontal direction, then there is no static friction. (Because of the vertical.)

Straight gravity and support force are balanced, and he doesn't care).

If you exert a force on him horizontally, but the force you exert does not make him move (that is, no.

push, hehe), but he has a tendency to move at this point, so then he is subject to static friction.

PS: If you push, then the object is subject to sliding friction, not static friction.

If there is no force exerted on him in the horizontal direction, then there is no static friction.

If a force is exerted on him in the horizontal direction, but the applied force does not move him, but he has a tendency to move at this time, there is static friction (if the carriage is moving, there must be air resistance, then there is static friction).

If the object is pushed by the action of a horizontal force, then the object is subjected to sliding friction, not static friction.

The position and motion state cannot be seen without static friction. So the question above can't.

Whether it is subject to static friction, in fact, it is best to read a book. The description of static friction in the book is to overcome the relative movement trend, the word trend is very important (I don't mean relatively unimportant), when there is a trend, it is static friction, and when it actually moves, it is kinetic friction. That's how it should be.

No. 1.You analyze their forces, and if so, with whom do they constitute a balanced force? And who is the reaction force?

2.There is no relative movement or tendency between them.

It depends on how the car moves, the car is in equilibrium, and the object is not subject to static friction, because there is no force to cancel it, the car is not in equilibrium, and the object receives static friction because it is in the same state of motion as the car, and it must provide acceleration strongly.

Not subject to friction. You draw a exploded diagram of the force, gravity, support. If there is friction, who balances it? Objects and cars move quickly, no.

The car has acceleration. Vice versa.

There is ma=mg by the title

Get a=g

Hence the acceleration a g =

There are many reasons for this.

The main reason is that the friction of the wheel rolling is very small, but the wheel of the front of the car is dragged by the pulling force generated by the reaction force generated by the static friction, and the friction of the static friction is many times greater than the friction of the rolling friction, and in addition, the weight of the front of the car is heavier than the carriage, which also increases the friction of the front of the car.

That's why the front of the car can drag so many cars.

The wide holding force of the support is n=ma

Friction f= n mg

ma mga g = 10 for Qi Zao's first dress of S 2

For the object p, in the vertical direction there is: f=mg, because f= n, the minimum elastic force is solved: n=mg

According to Newton's second law: n=ma, the minimum acceleration of Lasenmin is: a=nmg to the right, so the answer is: g

Horizontally to the right of the wheel branch

Solution: Let the mass of the object be m, and in the vertical direction there is mg=f, and f is the frictional force. Peeling and rolling in the critical combustion grinding state, f= fn

fn is the elastic force of the horizontal bucket on the object.

fn is obtained from Newton's second law

ma is <> from the acceleration of all of the above

Because when the object is just stationary, the car trembles in the vertical direction of the vertical key: mg= n, and the solution is: n=mg

According to Newton's second law, it is obtained: n=ma, and the solution is: a=nmg, so a is correct, and b, c, and d are wrong.

Therefore, a

The friction force of the inner wall of the carriage against the object is equal to the gravitational force of the object, and the friction is caused by the pressure of the object on the carriage generated by the acceleration.

From mau=mg, a=g u, if the object and the inner wall are used as the direction, it moves in the direction of the object.

Hello classmates. I can tell that this question is a basic question and should be one of your assignments. It's simple and basic.

I'm guessing you're lazy, it's no good. If you read the book carefully and read what you have learned today, you will definitely be able to make it. The first question is always the most difficult, but the second and third questions are slowly becoming more and more proficient and confident, so that you don't get bored with physics.

I'm for your good, because you remind me of my little cousin. Work hard, study steadfastly, and work hard. Famous sayings through the ages:

Let the mass of the object be m, in the vertical direction, from the equilibrium condition: mg=f, and the frictional force: f= fn

fn is the horizontal elastic force exerted on the object in the horizontal direction, which is solved by Newton's second law: fnma and obtained: a=fnm

mgmμm/ m/s2

A: Carriages should be at least M S2

The acceleration of the forward