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Anonymous users2024-02-07Ao, I was mistaken, I thought the container was a cube--
1, huang1hui report.
It's better to be an equation . Uh,,Well- - Let the height xcm, from the question: x<=40-20 The solution is x=9cm, the bottom radius is 6cm, and the volume of a metal cylinder with a height of 25cm is: cubic centimeters.
According to the rising volume equal to the volume placed in the object, the rising volume is also 2826 cubic centimeters.
Since the bottom area of the container is, so 2826 314 gets the water surface to rise 9 cm. ,2,2826 314=9,2, Let the water in the container rise xcm, according to the title:
102 12 + 22 (12 + x) = 102 (12 + x), (3 points).
1200 + 4 (12 + x) = 100 (12 + x), 1200 + 48 + 4x = 1200 + 100x (1 point), 96x = 48, x =, 2, set the water surface height in the container x cm.
314x=2826
x=9 The water surface in the container is 9 cm high, 0, the water surface is raised by h cm, and the volume of water after the fiber is raised - the volume of the metal cylinder immersed in water = the volume of the original water.
x10x10x(20+h)-πx6x6x(20+h)=πx10x10x20
The solution is h=9
i.e. the surface of the water rises by 9 cm, 0, a cylindrical container contains water 20 cm high, the bottom radius of the container is 10 cm, and the height is 40 cm
If a gold vertical head with a bottom radius of 6cm and a height of 25cm is put into a container, how many centimeters does the water surface in the container rise?
It's better to be an equation .
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Anonymous users2024-02-061) G gold = m gold g =
As can be seen from the figure, the spring dynamometer of the object submerged in a liquid indicates that f = buoyancy on the metal block a f float = g gold - f =
2) Obtained from p= liquid gh liquid = p gh = 4 10 2pa (10n kg*
3) The increase value of the pressure on the desktop is δf pressure = g gold - f float = increase of pressure on the desktop δp = δf pressure s =
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Anonymous users2024-02-05Answer: Analysis: Solve the problem According to the question, let the solution in the trouser container increase the digging rate per second, y=, and the time required to fill the container is 20 ()125 (seconds), and the definition domain of the function is 0 x 125
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