Let f x x5 to the power ax bx 8 and f 2 10 then f 2 detailed answer and process answer should be cor

As can be seen from the question, let g(x)=f(x)+8, then g(x) is an odd function, and g(2)=10+8=18

So g(-2)=-18

So f(-2)+8=-18

So f(-2)=-26

Write g(x)==x5 to the power + ax + bx, then g(x) is an odd function.

and f(-2)=10, then g(-2)=18, so g(2)=-18 so f(2)=-26

Solution: f( 2) 32 8a 2b 8

obtained by f(2)10.

8a 2b 50 is 8a 2b 50

f(2) 32 8a 2b 8 40 50 10 There is no trick in this question, you just can't just look at it, and you can know that it's very simple, right?

f(-2)=10.

4a+b=-25

Bring x=2 into the formula.

32+8a+2b-8=32-50-8=-26

Analysis: Solution 1: Let g(x)=x5+ax3+bx,x r, g(-x)=-g(x), g(x) be odd functions.

And f(x)=g(x)-8, and f(-2)=g(-2)-8=10, g(2)=-g(-2)=-18∴f（2）=g（2）-8=-26.

Solution 2: The problem is f(x)+f(-x)=-16, f(2)+f(-2)=-16

f(-2)=10, f(2)=-16-10=-26

Answer: -26

1 put -2 substitution.

2^5-2^3a+bx-8=10

2^5=2^3a-bx=-18

When x=2.

f(2)=2^5+2x^3-bx-8

2 f(x）=f（x)-8

f(x)=x^5+ax^3-bx

Prove it yourself. f(x)=f(-x)

So f(x) is an odd function.

f（2）=f(-2)

f(-2)=10=f（-2)-8

f(-2)=18

So f(2) = -18

So f(2) = f(2)-8

Sissy: 100 percent right, even math is the best.

It's okay to ask me questions, me.

Let f(x)=f(x) plus the fifth power of 8=x plus the cubic of ax minus bx, this is an odd function, f(2)=18, so f(-2)=-18 ah, in is to make **.

f(x)=ax to the power of 5 + bx to the third power + cx-8 so that g(x)=f(x)+8=ax 5+bx 3+cx shows that g(x) is an odd function.

g(-2)=f(-2)+8=18

g(2)=-g(-2)=-18=f(2)+8f(2)=-26

f(-2)=-32a-8b-2c-8

f(-2)+8=-32a-8b-2c (1)f(2)=32a+8b+2c-8

f(2)+8=32a+8b+2c (2)(1)+(2)

f(-2)+8+f(2)+8=0

It is known that f(-2)=10 is brought in.

f(2)=-26 is not an odd function, don't listen to him.