How to balance sodium peroxide, how to use valency to adjust the reaction of sodium peroxide and wat

For a good understanding, you can use the following principle:

2na2o2 + 2h2o = 4naoh + o2↑……

fecl2 + 2naoh = fe(oh)2↓ +2nacl……②

4fe(oh)2 + o2 + 2h2o = 4fe(oh)3……③

The intermediate products are NaOH, O2, Fe(OH)2, and three equations.

Remove NaOH and Fe(OH)2 by 2 +4 + to obtain the total reaction equation:

4na2o2 + 6h2o + 4fecl2 = 4fe(oh)3↓ +o2↑ +8nacl

If you have to balance in one step, think about the form in which Na+ ions and Cl- in Na2O2 and FeCl2 will exist, yes, in the form of NaCl in solution, so that Na2O2 and FeCl2 will be 1:1. Then think about 1molFe2+ becomes +3 valence and loses 1mol electrons, while 1molO22- (peroxide ion.

The oxygen element from -1 to -2 gives 2mol electrons, which is obviously unreasonable, so there must be -1 valence oxygen element to 0 valence, that is, O2 is generated. In this way, the reactants and products are known.

fecl2 + na2o2 + h2o — fe(oh)3 + o2 + nacl

Then analyze the valency:

Fe: +2 +3, each Fe atom loses 1E-

o:-1 -2, each o atom gives 1e-

o: -1 0, each o atom loses 1e-

There are two kinds of atoms that lose electrons, and you have to merge the above changes into one rise and one drop before you can use the least common multiple.

The method of balancing, and this has to use the remaining NaCl in the solution, knowing in advance that FeCl2 and Na2O2 must be 1:1, but it is verbose.

You can try both.

I hope I explain it to you clearly, and I won't ask if I don't understand. Hope.

2 fecl2 + 3 na2o2 + 4 h2o = 2 fe(oh)3↓ +o2↑ +4 nacl + 2 naoh。

The way to write this is to first determine 2 Fe(Oh)3 +O2 and then write it according to the valency. In the end, you will find that there are many NAs on the left, so there must be NAOH on the right.

reactant, 8 o is -1 valence. After the reaction, only 2 o's are 0 valence. For the other 6 O's, the valency is reduced to -2.

This reaction is usually written to illustrate the phenomenon. Don't worry about it, and don't need to remember.

First, write the equation for sodium peroxide to react with water to form sodium hydroxide, sodium hydroxide to form ferrous hydroxide and sodium chloride, and ferrous hydroxide to react with water to form iron hydroxide.

2Na2O2+2H2O=4NaOH+O2 The oxygen element in sodium peroxide is -1 valence, part (half) is increased to 0 valence in O2, and part (half) is reduced to -2 valence in NaOH, because O2 contains 2 O atoms, so the coefficient before Na2O2 is 2, then the coefficient before NaOH is 4.

The oxygen in sodium peroxide rises from -1 valence to 0 valence and becomes an oxygen atom (i.e., an oxygen molecule), and the other decreases from -1 to -2, so the sodium peroxide gives itself electrons. Therefore, the stoichiometric number is 1, according to the conservation of sodium atom, sodium hydroxide is preceded by two to obtain Na2O2+H2OH=2NaOH+(.

After tidying up, we have 2Na2O2+2H2O=4NaOH+O2. The ionic equation is: 2Na2O2+2H2O=4(Na+)+4(OH-+O2).

The reaction is carried out in two steps: Na O + H O ===2NaOH + H O

Hydrogen peroxide instability: 2h o ==2h o+o

The two are combined: 2Na O + 2H O==4NaOH + O (which is what we commonly use).

Sodium peroxide is one of the products of sodium combustion in oxygen or air, pure sodium peroxide is white, but the generally seen sodium peroxide is pale yellow, because a small amount of sodium superoxide (NAO, light yellow) is formed during the reaction. Sodium peroxide is easily deliquescent and corrosive, so it should be sealed and stored. Sodium peroxide has strong oxidizing properties and can be used to bleach textiles, straws, fibers, etc.

Extended Information: Sodium peroxide can absorb nitric oxide (NO) and nitrogen dioxide (NO).

na₂o₂ +2 no = 2nano₂

na₂o₂ +2 no₂ =2nano₃

Sodium peroxide does not belong to basic oxides, belongs to peroxides, can react with carbon dioxide (does not react with dry carbon dioxide), acid, oxygen is released during the reaction, and the chemical equations are: 2na o +2co = 2na co +o

The reaction between sodium peroxide and water first produces hydrogen peroxide, which is unstable and will decompose Na o +2H O=2NaOH+H O; 2Ho = 2Ho + O, the reaction is exothermic.

Total reaction chemistry equation: 2NaO + 2HO = 4NaOH +O

In an alkaline environment, sodium peroxide can oxidize +3-valent arsenic (AS) to +5 valence and +3-valent chromium (Cr) to +6 valence in compounds. This reaction can be used to remove +3 chromium number lead from certain rock minerals. It can also oxidize organic matter to ethanol and carbonate under general conditions, and can also react violently with sulfides and chlorides.

Sodium peroxide also has bleaching properties, because sodium peroxide and water reaction will generate hydrogen peroxide (HO), because hydrogen peroxide has strong oxidation, Mingju will bleach some reagents such as magenta, so sodium peroxide is put into phenolphthalein solution phenolphthalein first reddened and then faded, this process is irreversible. <>

2na2o2 + 2co2 ==2na2co3 + o2

The two O atoms in Na2O2 are both -1 valence, and after the reaction, one of the O atoms is converted into 0-valence O2 and the other into -2 valence Na2CO3, so two Na2O2 are required to generate one O2, so the coefficient before Na2O2 = 2

Then according to the conservation of atoms, the coefficient = 2 in front of Na2CO3 in the product, so the number of atoms in C = 2, so the coefficient in front of reactant CO2 = 2

2Na2O2 + 2H2O ==4NaOH + O2 (gas).

The two O atoms in Na2O2 are both -1 valence, and after the reaction, one of the O atoms is converted into 0-valence O2 and the other into -2 valence NaOH, so two Na2O2 are required to generate one O2, so the coefficient in front of Na2O2 = 2

Then according to the conservation of atoms, the NaOH front coefficient in the product = 4, so the number of h atoms = 4, so the reactant H2O front coefficient = 2

How is the trim with the redox method?

First, find out the oxidant and reducing agent, and write the valency of the oxidant that decreases and the valency of the reducing agent increases. The coefficients that precede them make the valence decrease and the valency increase equal.

After the oxidant and reducing agent are prepared, other substances are prepared according to the conservation of atoms.

What's going on with the electronic type of gain and loss?

The gain and loss of electrons is the change in valency. The electron valency decreases, and the electron valency increases.

2 times the sodium peroxide and carbon dioxide = 2 times the sodium carbonate + twice the oxygen.

2 times the amount of sodium peroxide + 2 times the amount of water = 4 times the amount of sodium hydroxide + twice the amount of oxygen.

Find the least common multiple of the electron gain and loss, and then use the observation method, and the general one is about the same.

2na2o2+2h2o=4naoh+o2↑

You can directly use the observation method, Na2O2 corresponds to 2NaOH, and then according to the 2 H in 2NaOH to get the H2O coefficient is 1, Na2O2 and H2O are a total of 3O, subtract the 2 O's of 2NaOH to get 1O, corresponding to O2, and then multiply all coefficients by 2 (avoid decimals).

2 Na Peroxide + 2 Water = 4 Na Hydroxide + 1 Oxygen (gas symbol).