Seek superiority, seek superiority! 5th Grade Math! Thank you! Simple, thank you!!!!!!!!

Suppose 14 pieces are all five yuan, 5 14 is 70 yuan, and 30 yuan is less because 10 pieces are counted as 5 yuan, and no one is less than 5 yuan, then the number of 10 pieces is 30 divided by 5 equals 6, that is, 10 pieces of 6 pieces, 5 pieces of 8 pieces.

Set 5 yuan x sheets, 10 yuan (14-x) sheets.

5x+10（14-x）=100

x=8 A5 Yuan 8 sheets, 10 Yuan 6 sheets.

Seek (

Solution: There are x sheets for 5 yuan and (14-x) for 10 yuan.

5x+10（14-x）=100

5x+140-10x =100

5x=40x=8

14-8=6 (sheets).

A: 8 tickets for 5 yuan, 6 tickets for 10 yuan.

5*14=70 yuan 100-70=30 yuan.

30 (10-5) = 6 sheets.

14-6 = 8 sheets.

A: There are 8 tickets for 5 yuan and 6 tickets for 10 yuan.

If there are x sheets for 5 yuan, then there are 14-x sheets for 10 yuan.

Equation: 5x+10(14-x)=100

5x=-40

x=8, so ten dollars have 14-x=14-8=6 sheets.

A: There are 8 tickets for 5 yuan and 6 tickets for 10 yuan. Under.

Solution: If there are x pieces of 5 yuan banknotes, then there are (14-x) pieces of 10 yuan notes.

Column equation: 5x+10(14-x)=100

5x+140-10x=100

5x=40x=8

A: There are 8 5 yuan notes and 6 10 yuan notes.

Let the 5 yuan x sheet, 5x+10(14-x)=100, and solve the equation x=8.

Let's say the whole book is ten dollars. 10x14=140 yuan 140-100=40 yuan 10-5=5 yuan 40 divided by 5=8 pieces 14-8=6 pieces 10 yuan 6 pieces 5 yuan 8 pieces.

Set $5 to have a ticket, $10 to have a sheet. Get a+b=14, 5a+10b=100, and you can find it.

1.(12+8)*(39+39) 60=20*78 60=26 km The specific reasons will not be explained, I believe you can understand.

The first time the kilometer met was 6 kilometers away from place B, that is, B traveled 6 kilometers, then it would take two identical times to meet the two cars for the second time, that is, A needed three times as long to meet B for the second time, and then he traveled 18 kilometers, of which 4 kilometers were returned, so the two places were 14 kilometers apart. Of course, there is also a situation where A only takes twice as long to return to catch up with B, so the distance between the two places is 6*2-4=8 kilometers.

The original limit was to travel x kilometers per hour.

Solution: 1-[(x+12)*39]=1+[(x-8)*39].

x = 83 km.

1. A 100-page book, turn a page casually, and the probability that the page number is an odd number is (50%)

2. Xiaoli reads a book for 75 days on average, and it takes (4) days to read this book.

3. Of the three and thirty-three fifty-tenths, and three and two-thirds, the largest number is ( ).

50% 4 33/50.

According to the inscription, when the number increases by one person, it is divisible by five and three at the same time, while between 30 and 50, such a number is only 44

( Approximately equal to <19 and 18.)

So, up to 18 can be done.

1.Eight centimeters more equals 2 more widths, 8 divided by 2 = 4, and 4 is the radius.

2.The metal band should not be square! It is equivalent to saying that 4 times of a circle = the circumference of a circle, plus 4 diameters.

3.The third.

Tired of typing!! 1

I'll only answer the third question, and I'll choose 3

The meaning of the title can be known that the perimeter is the same, and it is set to c

The area of the square is (the square of c divided by 16) The area of the rectangle (you can assume that the length of one-third of the c, the width of one-sixth of the c,) the area of (the square of c divided by 18) and the circle of (the square of c divided by 4) Just compare.

Solution: Let the side length of the small square be x1 (cm) and the side length of the big square be x2 (cm).

4x1+20=4x2 （1）

x1²+60=x2² 2）

From (1): x1=x2-5 (3).

Substituting (3) into (2) yields: x2 +25-10x2+60=x2 10x2=85

x2= （cm）

Answer: The sides of a large square are centimeters long.

Let the side length of the large square be a centimeter and the side length of the small square be b centimeter.

So 4a-4b=20

a²-b²=60

a-b=5, (a+b)(a-b)=60, a+b=12 by a-b=5

a+b=12, a=,b=

Let the side length of the big square a and the side length of the small square b, then: 4a-4b=20,,a*a-b*b=60, so a= b=

Set the large positive to become long x1 and the small positive to become long x2

4x1-4x2=20

x1*x1-x2*x2=60

x1 = 17 2, x2 = 7 2

Let the side length of the large square be x, and the side length of the small square be y

Then 4x-4y=20

x^2-y^2=60

Simultaneous equations can be calculated as x=.

Centimeter. Where did the three answers come from?

The result is Note: The product is three decimal places and the whole part of the product is 1, and the thousandth place is 5, so this number is.

Keeping two decimal places is So the thousandth place should be up, the percentile should also be entered, and the tenths should also be entered... So it can only be...