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Because of AE Cd, d+ e=180°
The sum of the internal angles of the pentagon is 540°, a+ b+ c+ d+ e=540°, a=130°, c=110°, and d+ e=180°
gives b=120°
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Bf cd is used as a parallel line, and the ipsilateral internal angle is complemented by C+ FBC=180; ∠a+∠fba=180.
b=∠fbc+∠fba=70+50=120
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Because of the AE CD
So angle e + angle d = 180
Pentagon inner corners and 540
So the angle b = 540-180-130-110 = 120
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ae//cd ;So e+ d=180° ; The sum of the internal angles of the pentagonal is (5-2)*180°=540°;
b=540° -a-∠c-∠d-∠e=110° .
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Parallel line bf of AE is made at point b
Because bf||ae
So A is complementary to ABF.
So abf=50°
The same goes for fbc=70°
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Because ae||The cd is based on two straight rows in parallel
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The sum of the internal angles of the pentagon is equal to (5-2)*180 degrees 540 degrees.
From the knowledge of parallel lines, we know that the angle e + angle d = 180 degrees.
So the angle b 120 degrees.
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Let a be x degrees.
then its co-angle is 90-x degrees.
The complementary angle is 180-x degrees.
Because the sum of the co-angle of a and the complementary angle of a is a flat angle, then (90-x) + (180-x) = 180
Solution x=45
So a = 45 degrees.
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Because A travels 4 hours, B travels 5 hours.
So the first speed is equal to the second speed.
So B has to travel for 5* hours.
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If the distance between A and B is divided into 9 parts, A walks 5 9 of the total distance in 5 hours, and 4 9 of the remaining distance in 4 hours. How many hours does it take B to walk 4 9 of the total distance in 5 hours?
B walks 4 9 5 = 4 45 per hour, 5 9 divided by 4 45 = 25 4 hours, that is, the hour, that is, B takes another 6 hours and 15 minutes to reach place A.
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Let the small rectangle be a long and a wide b
So 5a = 2b
9a+4b=76
The simultaneous solution is a = 4
b=10, so the small rectangle is 4m long and 10m wide
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Solution: Let the length and width of each small rectangle be x and y respectively, which can be obtained from the figure and the title
5x+2x+y)=76
5x=2y is solved by substitution elimination method: x=10, y=4
So the small rectangle is 4m long and 10m wide
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The length and width of each small rectangle x, y
2x=5y5y+x+2y)*2=76
2x+14y=5y+14y=19y=76
y=4x=5y/2=10
The length and width of each small rectangle is 10 meters, 4 meters.
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Solution: Let the length of the cuboid be y meters. The width is x meters. Since 5x=2y (the top and bottom sides of the large cuboid are equal), then 5x+2y+2x+y+2x+y=76 (the circumference of the large cube is 76) is solved x=4, y=10
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1. Set the excess part to x tons.
x = 12 This month's water consumption is 12 + 20 = 32 tons.
2. The question is incomplete. Less. Dad found out a few minutes later that Xiao Ming forgot to bring book 3, and the corner coe and the corner doc were redundant.
Angular AOD = Angular doc, Angular Coe = Angular EOB
Therefore, (angle doc + angle coe) = (angle aod + angle eob) = 180 2 = 90 so mutual congruence.
Do auxiliary lines. There is no picture.
4. Fig. Belch...
5. The angle boc = 30, so the angle con = 15
Angular aob=aAngle AOC = A-30Angular moc = (a-30) 2 angular mon = a 2
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1. Use water x tons, x must be greater than 20 tons.
So 20 gives x=32
2, Xiao Ming walked for a few minutes first, don't you know?
3. What about the figure? 1) Angles that are coincident with the angle doc: the angle boe and the angle coe reason: a0b=180°, so eod=90° boe= coe are co-angles.
2) The angle that is complementary to the angle doc has, BOD
Rationale: doc= aod is the way to go.
4. Give the picture.
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1 a(108%÷120%)
2. X kWh of electricity is used.
x=3923, motorcycles and trains depart from A and B at the same time, and meet in a few hours40 (45+35)=
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1. (1+8%) (1+20%)*100%=90%2.
x=280 electricity fee: 280*yuan).
3. Departing at the same time, how many hours will we meet?
Set x hours to meet.
40/x=45+35x=
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