Pascal has an old rabbit and gives birth to baby bunnies every month, then

Fibonacci sequence.

Divide. 1. Each item except the second item is the sum of its first two items;

If the first term is f0 and 0, then the sequence is 0, 1, 1, 2, 3, 5, 8....The recursive relationship is (n>=2)fn=fn-1+fn-2

The sum of the first n terms sn=f0+f1+f2+.fn=fn+2-1

Example 9: Here's an example of fibonacci:

1.There are n steps on the stairs, you can go up 1 step up the stairs, you can also go up 2 steps in one step, how many different ways to walk in a program?

2.There is a pair of male and female rabbits, and every two months they breed a pair of male and female rabbits. Q: How many pairs of rabbits are there after n months?

3.There is a rectangular square with n*2 and a 1*2 domino covering the square. What is the total number of paving methods?

Then I'll give you another program:

program lk;

vara,b,c:longint;

i:longing;

begina:=5;

b:=7;for i:=5 to 10 do

beginc:=a+b;

a:=b;b:=c;

end;writeln(c);

end.

Is the little rabbit an old rabbit after three months?

God! I haven't touched that thing for half a year! It should be an array conditional loop, right? Should I also use loop nesting?

Oh Mommy.,Do your own research.。。。 I'm going back to study too... I'm a lazy silver who skips class.。。。

MS even did this question.。。。 If you find the original question, I'll call you.。。。

In the first month, 1 pair produces 3 pairs, in the second month it becomes 4 pairs and 12 pairs, in the third month it becomes 16 pairs and 48 pairs, in the fourth month it becomes 64 pairs and 192 pairs, by the fifth month it becomes 256 pairs and 768 pairs, and in the sixth month (i.e. half a year) it becomes 1024 pairs and 3072 pairs, and finally there are 4096 pairs

4 to the sixth power = 4096

This is the final number of rabbits that exist, and this question asks about the number of rabbits that have been bred, and you have to subtract the first pair, so the answer is 4095

It is 144 pairs of rabbits, and the Philippo number sequence is suitable.

Because each pair of baby rabbits can only become a pair of mature rabbits after one month, that is to say, the cycle of rabbits from birth to childbirth is not one month, but two months.

The logarithm of rabbits from January to December is:

0 means that the first pair of rabbits did not mature in the first month.

My rabbits give birth to bunnies at around 8 months.

After one year, it can become 377 pairs of rabbits.

Count an extra month.

This is the Fibonacci sequence.

Maybe every time it is a male rabbit, is it a female rabbit?

Half a year and 6 months.

January ——— 1 pair (1 large).

February——— 4 pairs.

March ——— 7 pairs.

April ——— 19 pairs.

May ——— 21 pairs.

June ——— 79 pairs.

79 pairs in half a year.

One pair of baby rabbits is bred every month, and 144 pairs of rabbits can be bred in a year.

First, enumerate the logarithms of rabbits after 1 to 6 months as 1,1,2,3,5,8. It is not difficult to see that the sequence is characterized by the following: starting with the third term, each term is equal to the sum of the first two terms.

Thus, according to this rule, we can get the logarithm of rabbits in a year. It can be seen that there are 144 pairs of rabbits in a year.

The Fibonacci sequence refers to the sequence of numbers 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233,377,610,987,1597,2584,4181,6765,10946,17711,28657,46368

This is a Fipuccina sequence, and the answer is 144 pairs.

Suppose a newborn male and female pair of rabbits can give birth to a male and female pair of rabbits in two months, and then give birth to a pair of rabbits every month thereafter. If you have a newborn pair of rabbits, ask how many pairs of rabbits you can get at the end of the year.

First month: only 1 pair of bunnies.

Second month: A pair of baby rabbits grows into a pair of large rabbits, but they do not yet reproduce. There was still only a pair of rabbits.

3rd month: The pair of big rabbits gave birth to a pair of baby rabbits, a total of 2 pairs of rabbits.

Fourth month: The big rabbit gives birth to another pair of rabbits, and the rabbits born last month are growing, at this time there are 3 pairs of rabbits.

Fifth month: At this time, there are already two pairs of rabbits that can reproduce (the original big free and the rabbits born in the third month), so two pairs of rabbits are born, and there are a total of 5 pairs of rabbits.

Number of months. One. Two. Three.

Four. Five. Six. Seven.

Eight. Nine. Ten. Eleven.

Twelve. A baker's dozen.

Rabbit logarithms. Put the estimated results into a table.

As can be seen from the table, 144 pairs of rabbits can be obtained at the end of the year.

This method is difficult if the time is long, and now we come to the recursive relationship.

Used to represent the logarithm of rabbits at the nth month, then.

It is easy to find that the recursive formula is.

un= un-1+ un-2.

Now it shows that this recursive formula is correct. Because there are two types of rabbit pairs in the nth month, one is the rabbit pair in the nth-1st month, and the other is the rabbit pair that is born in the current month, and the number of these rabbits is exactly the rabbit pair un-2 in the nth-2nd month

With the recursive formula above, the 12th term can be written as 144 pairs.

If it's an arithmetic problem, if it's a technical problem, I can, a female rabbit breeds 6 to 8 litters a year, a litter of 5 to 8, and many, but it is not easy to survive.

(12-2) Month * 2 + 2 = 22.

Because inbreeding cannot reproduce, the first pair of rabbits born of the second generation of rabbits are all inbred, so only the first pair of rabbits have the ability to reproduce, and the others do not.

Even if the condition that inbreeding is not allowed to be reproduced is removed, the possibility of a rabbit being born for three consecutive months cannot be ruled out (for example) that all male rabbits are followed by three consecutive months of female rabbits

If you want steps, you can only list **:

month rabbit logarithm )

Therefore, the answer is: 144 pairs of rabbits can be bred...It is known as the "Fibonacci sequence".

Just copy the brackets!

There should be an answer to the p65 side in the current sixth-grade math book!

The survival rate of inbred rabbits is very low, and it is normal to have only seven or eight litters a year.