The solution of the equation ax 3 4x 1 with respect to x is a positive integer, then the value of th

ax-3=4x+1

ax-4x=1+3

a-4)x=4

x=4/(a-4)

Because the solution is a positive integer, i.e., the value of 4 (a-4) is a positive integer.

That is, 4 is divisible (a-4), then the value of a-4 is 4 or 1 or 2, i.e. a-4 = 4 or a-4 = 1 or a-4 = 2

then a = 8, 5, 6

ax-3=4x+1

ax-4x=1+3

a-4）x=4

x=4÷（a-4）

To make the solution of the equation for x ax-3=4x+1 a positive integer.

So: a-4 = 1 or a-4 = 2 or a-4 = 4

So: a=5 or a=6 or a=8

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ax -3 = 4x+1 a-4)x = 4 , x is a positive integer and a is also an integer, then x must be a factor of 4, only the following possibilities.

x =1, a-4 = 4; a=8

x=2, a-4 =2, a =6

x=4 a-4=1; a=5

Solution: The original equation can be reduced to: (a-4)x=4, x=4 a-4 Because x is a positive integer, it is discussed in different cases that when a=8 x=1, when a=6 x=2, when a=5 x=4 so a=5 or 6 or 8

a-4 = 4 x, x is a positive integer, a is an integer, then x = a=8 6 5

Solve xax-3=4x-1

a-4)x=2

x=2/(a-4)

The solution of the equation is a positive integer.

2/(a-4)＞0

i.e. A-4 0

a 4 The integer a has a value greater than 4.

Solution ax+2=4x+1

a-4)x=2

Because the solution is a positive number.

So (a-4) is a positive number.

So a=3 a=2

ax+3=4x-1

ax-4x=-1-3

4－a﹚x=4

x=4／﹙4－a﹚

The solution is a positive integer.

4 a is the positive factor of 4 1,2,4

The integer a=3, or 2 or 0

ax+3=4x+1

4-a )x=2

x=2/(4-a)>0

4-a is an integer.

x is a positive integer.

x = 2 or 1a = 3 or 2

Solution ax+2=4x+1

a-4)x=2

Because the solution is a positive number.

So (a-4) is a positive number.

So a=3 a=2

Solution: Shift the term to obtain: (4-a)x=2,x=2 (4-a), the analysis obtains, 4-a must be greater than zero less than or equal to 2 to be a positive number, so when a=3, a=2, x=2, x=1

4-a)x=2

x=2/(4-a)

2 (4-a) is a positive and even number, and 4-a is an integer.

4-a=1 or 4-a=2

a=2 or a=3

ax+3= 4x+1

4-a) x = 2

x is a positive integer, so 4-a>0 a<4

2 can only be decomposed into 1x2 and 2x1

So when x=2, 4-a=1 a=3

4-a=2 a=2 at x=1

Solution: ax+3=4x+1

x=24-a

and x 0x=24-a 0

a 4x is an integer.

2 should be a multiple of 4-a.

a=2 or a=3

Solution: ax+3=4x+1,4x-ax=3-1,(4-a)x=2 ,x=2 (4-a).

Because x is a positive integer, x>0, 2 (4-a) > 0, and because 2 (4-a) is a fraction, (4-a) cannot be equal to 0, a cannot be equal to 4, (because x is a positive integer) so a=2 or 3

4x-ax=2

x=2 (4-a) is a positive integer.

So 4-a is a divisor of 2.

4-a = 1, or 2

a=3,a=2

The solution yields x=-2 (a-4)=2 (4-a).

2 (4-a) is greater than 0

2 is greater than 4-a or 4-a is greater than 0

A is an integer greater than 2 and a is less than 4.

So a=2 or a=3

2 or 3 mental arithmetic, accept to explain. The phone plays to explain the ink.