How many watts are 2 15 watt bulbs in series

It depends on the working condition of the bulb, whether it is still in the rated working condition. For example, series circuits.

The voltage is 2 times the rated voltage.

When connected in series, each bulb is at a rated voltage, which is 15 watts, which adds up to 30 watts. But I guess what you're asking about is stringing them together and adding them at the rated voltage, where the voltage at both ends of each bulb is half the rated voltage, and the power is only a quarter of the original.

In the system of electrical units, it is volts multiplied by amperes (u i), if the current passing through them is constant, then it is 30 W (i 2 r, the resistance doubles after series connection), but if the voltage is constant, it is only after series (u 2 r, the resistance doubles after series connection).

When two 15 W bulbs are connected in series, the resistance is doubled, but the voltage acting on each end of each bulb is halved.

Let a single 15 W bulb have a resistance of r and a rated voltage of u, then u 2 r = 15 w

The power of two such bulbs in series is:

p=p1+p2=(u/2)^2/r + u/2)^2/r = u^2/r =

or p = U2 (R+R) = 15W2=

If the rated voltage of the two bulbs is the same, and the whole is still connected to the power supply of the original rated voltage after being connected in series, the overall power is watts. Otherwise, this question can't.

If the bulb is connected in series, and the voltage connected to both ends is 220V, then the power should be 50 watts, and the brightness of the bulb is not as bright as that of a single bulb.

The power supply voltage is U, the internal resistance r of the power supply is negligible, and the two bulb resistors are R1 and R2 respectively

A 100W bulb can get U R1=U R2=100 watts.

When two bulbs are connected in series, the total resistance r=r1+r2

Total power p=u r=u (r1+r2)=u 2r1=100 2=50 watts.

In this problem, the rated voltage of the bulb is not specified, and it is connected to a large power supply voltage after being connected in series. Of course, if two 100-watt lighting bulbs are connected in series, they are equivalent to 200-watt bulbs.

Theoretically, if two identical incandescent bulbs are connected in series to the original rated voltage, then because the resistance on the circuit is doubled, the current is reduced to half of the original, so the power consumed by the two bulbs is only half of the original bulb, that is, the two bulbs consume 50 watts of power, and the two incandescent bulbs may only have two filaments that emit dark red light.

If there are two different 100-watt bulbs, the situation will change.

Hello: 1, two bulbs of the same power in series, [ResistanceDoubled.

2. Two bulbs in series, connected to the [ of the bulbRated voltage, the current is half of a single bulb (p = u i), and the power is50w

70 watts.

Because a light bulb is 5 watts, according to the calculation of 14 watts is 70 watts, so 14 5-watt lamps are 70 watts in series.

Tile. The resistance value of each bulb is 220*220 Bihong 25=1936;The total power shed in series is 220 * 220 1936 * 10 =. Hand and book.

A: Five 12 watt lights are 60 watts. 5 12 60 watts.

How many watts is 48 300 watt bulb combustion segments in parallel.

48x300

48x300 = 14400 watts.

Answer: 48 300-watt bulbs are 14,400 watts.

Hello, it is a pleasure to serve you. No. Two bulbs with a nominal voltage of 50V are connected in series, which is equivalent to a 100V bulb, but the voltage in the circuit is still 50V.

When a circuit is connected in series, the components share the current, but the voltages are shared, i.e., the sum of the voltages experienced by each part equals the total voltage. Because voltage is the basic quantity in a circuit, the maximum voltage of the circuit is still 50V when two 50V bulbs are connected in series. Otherwise, if the 100V power supply is directly connected in series, the bulb is likely to be burned, damaging the equipment or causing other dangerous situations.

Unfortunately, two 50V bulbs cannot be connected directly in series to a 100V voltage. Because the voltage distribution in a series circuit is distributed according to the proportion of the resistance value, and the resistance value of the bulb is fixed, when two 50V bulbs are connected in series, their total resistance value is halved, and the voltage distribution is also halved, that is to say, each bulb can only get 50V of voltage, not 100V. If you want two 50V bulbs to work normally at 100V, you can connect them in parallel so that each bulb can get 100V voltage, but the leakage is not messy, at this time the current will increase, and you need to ensure the safety of the circuit.