Knowing the system of equations, find the magnitude relation of m n.

Solving this equation yields:

m = (a^2 b + a b^2)/(a^2 + a b + b^2)

n = (a^2 c + a c^2)/(a^2 + a c + c^2)

m - n = (a^3 (b - c) (a + b + c))/((a^2 + a b + b^2) (a^2 + a c + c^2))

Because A > B > C, (B - C) (A + B + C) ((A 2 + A B + B 2) (A 2 + A C + C 2)) 0

If a > 0, then m > n; a < 0，m < n.

Discuss the case when , a>b>c>0 a>b>c<0 Find the relationship between m and n.

m = (a^2 b + a b^2)/(a^2 + a b + b^2)

n = (a^2 c + a c^2)/(a^2 + a c + c^2)

m - n = (a^3 (b - c) (a + b + c))/((a^2 + a b + b^2) (a^2 + a c + c^2))

Because A > B > C, (B - C) (A + B + C) ((A 2 + A B + B 2) (A 2 + A C + C 2)) 0

If a > 0, then m > n; a < 0，m < n.Please like.

Known systems of equations <>

There is a solution with the same rough bench as the <>, and the values of m and n are obtained from the known: <> solution: <>

Put <>

Substituting the remaining two equations to form the Dan stool reed equation mold band group <> solved: <>

So the values of m and n are: 4,6

x-5y=2m ,2x+3y=m-12

Substitute x=2m+5y into 2x+3y=m-12

y=-(3m+12) 13

x=(11m-60)/13

x+y=(8m-72)/13=0

m=9When m is 9, the solutions of the system of equations {x-5y=2m {2x+3y=m-12 are opposite to each other.

Hello! If you have any questions, please complete the questions.

Consider x-5y=2m as a formula.

Think of 2x+39=m-12 as a 2.

Equation 1 2 gives 2x-10y=4m as equation 3, subtracts equation 3 from equation 2 to get -13y=3m+12, y=3m+12 -13, denotes equation 4.

Bringing 4 into 1,2 gives x+3m+12=2m, 2x+(9m+36)-13=m-12, which is denoted as 5,6.

In solutions 5 and 6, we get m=-4The answer comes out.

Analysis of test questions: According to the meaning of the question, the thing is due to the question. m=n=

Then the nature of the inequality segment can be relied upon.

It can be concluded that:

Comments: It mainly examines the use of all-finger inequalities, which is a basic question.

Method 1: The source of the cherry blossoms.

It is known from the hail bushes.

ma[1]+(m(m-1)d 2) = (m n), where a[1] denotes the first term).

na[1]+(n(n-1)d/2)=(n/m) .

2mNa[1]+mn(m-1)d=2m .

2mNa[1]+mn(n-1)d=2n from (2) is obtained

3)-(4) obtains mn(m-n)d=2(m-n), (m≠n) is solved by (5) to obtain d=2 mn, and this is substituted.

3) The solution yields a[1]=1 with bridge mn

Substituting the values of a[1] and d into the equation of the sum of the first m+n terms can be solved:

s[m+n]=(m+n)^2)/mn

Since (m≠n), it is easy to prove [(m+n) 2]mn according to the basic formula [(m-n) 2]>0

Law II. Solution: Let s(n)=an 2+bn, then there is:

When s(m)=am 2+bm=m n, am+b=1 ns(n)=an 2+bn=n m, an+b=1 mm≠n: a(m-n)=(m-n) mn

a=1/mn,b=0

Therefore, there is: s(m+n)=(m+n) 2 mn=(m n)+(n m)+2>4 (due to m,n>0 and m≠n).

Solution: y=3a+1, y=a

a+5, then in the Cartesian coordinate system of the hail clearing of Guan Qinsocks in a, y, it can be seen that the straight line is below the parabola, and the two equations can be solved by concatenating a=2, and the positive excitation y=7, that is, the intersection coordinates, m can be equal to n, m n, please click "for the answer".

2 Grip 1

According to the paragraph which and slow the reading of the question.

The solution yields m=2 and n=1

(0, 4) within, 1>sin

cos because (sin) cos and (cos) sin are both exponential functions, and when the base is greater than zero, it is an increasing function, and the larger the base, the larger the result, sin

cos again because when.

The number of land at the bottom of the feast. In (0,1), the larger the exponent, the smaller the value of the function, and sincos, i.e., cos

cosα）^sinα

1) When m=6, n=10 has an infinite number of solutions, then the system of equations becomes {x+3y=5,2x+6y=10} This system of equations is equivalent to the equation x+3y=5, and this equation has an infinite number of solutions.

2) m≠6, n is a unique solution for any real number, equation 1 becomes x=5-3y, bring in equation 2, because m≠6, y=(n-10) (absolute argument m-6), y has an infinite number of solutions, then the equation has an infinite number of solutions, 3) m=6, n≠10 has no solution, if you multiply the left and right sides of equation 1 by 2, we get 2x+6y=10, and equation 2 is 2x+6y=nSubtract the two formulas to get 0=10-n, and brother Hongzheng n is not equal to 10, so the contradiction, that is, there is no solution at this time.

m＞0，n＜0

So m>n , m<-n

For example, lml>lnl, then.

m>-n>n>-m

For example, Lem > - > Grace

To sum up, the beauty >->-grace>-beauty or -grace> beauty>-beauty >